The famous poet of the sixth grade wrote quickly, quickly

I don't know which ones are in the sixth grade, so I'll write down the famous poets I know, and you can choose them.

Li Bai, He Zhizhang, Du Fu, Meng Haoran, Wang Wei, Bai Juyi, Su Shi, Du Mu.

Yang Wanli, Li Shangyin, Wang Bo, Gao Shi, Wang Zhilian.

Li Bai, He Zhizhang, Du Fu, Meng Haoran, Wang Wei, Bai Juyi, Su Shi, Du Mu.

Yang Wanli, Li Shangyin, Wang Bo, Gao Shi.

1. On the map with a scale of 1:10000, the distance between A and B is 4cm, if on the map with a scale of 1:8000, how many centimeters are between A and B?

4x10000 8000 = 5 (cm).

2. The printing house binds a batch of maps, if 3,000 copies are bound every day, the binding will be completed in 16 days. If I want to bind 4 days in advance, how many volumes should be bound per day?

3000x16) (16-4) = 4000 (volume) 3, the ratio of the tonnage of grain stored in the two warehouses of A and B is 9:11, after transporting 15 tons from the B warehouse, the tonnage ratio of the grain in the two warehouses of A and B is 3:2, how many tons of grain in the original A?

A: B = 9:11

A: B = 3:2 = 9:6

Per serving: 15 (11-6) = 3 (tons).

Jiayuan: 3x9=27 (tons).

1. 4cm=

Divide by 1 10000 = 400m [actual distance between two places].

400 times 1 8000 = 20cm [distance on the figure].

When solving this type of problem, the most important thing is to calculate the actual distance and thus find the distance on the graph.

2 .3000 multiplied by 16=48000{Books} [Total number of books] The method is similar to the above.

48,000 divided by {16-4} = 4,000 {volumes} [how many copies should be bound per day four days in advance].

3.9 11-2 3 yields a share of 15 tons. 5 33 is obtained, and then 15 divided by 5 33 = 99 [book] fraction corresponding amount divided by fraction = unit one quantity.

When solving this kind of problem, the most important thing is to find out the corresponding quantity of the fraction and its corresponding fraction, and then you can find the total number and thus solve the problem.

x4/80000=

x16 (16-4) = 4000 copies 3, A is x, B is (11 9) x

x:(11x/9-15)=3:2

x = 27 tons.

B is 33 tons.

1. On the map with a scale of 1:10000, the distance between A and B is 4cm, and the real distance between A and B is 4*10000=40000cm, so that on the map with a scale of 1:8000, the distance between A and B is 40000 8000=5cm

2. By "the printing house binds a batch of maps, if 3000 copies are bound every day, and the binding is completed in 16 days", the total number of maps obtained is 3000 * 16 = 48000 volumes, if you want to bind four days in advance, that is to say, you should bind 48000 12 = 4000 copies per day.

3. You can first set up the original warehouse A to store 9x tons of grain, then warehouse B to store 11x tons of grain, "after transporting 15 tons from warehouse B, the tonnage ratio of grain in warehouse A and B is 3:2", and the equation (9x) (11x-15) = 3 2 is obtained, and x=3 is calculated, that is, the original A has 9x=9*3=27 tons of grain.

1. 4x10000/8000=5cm

2. 3000x16/12=4000

3.3:2=9:6 So 15 5=3 3x9=27 So A had 27 tons.

8000 10000 cm.

16 12 = 4000 volumes.

3. Suppose that A has 9x tons of grain and B has 11x tons of grain. Then 9x:11x-15=3:2 gives x=3

It turned out that A had 9 3 = 27 tons of grain stockpile.

（1）:10000x4=40000cm

40000÷8000＝5cm

2): 3000x16=48000 (volume) 16—4=12 (day) 48000 12 4000 (volume).

3): A originally had 45 tons of grain in stock.

1:10000=4: Distance Distance=40000 cm 1:80000=Distance: 4000 Distance=Centimeters.