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It seems that some of them are out of class, and they belong to high school chemistry.
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Hello, this one can be estimated approximately.
The O content is 4 times that of H, so the H content is, so that the C, O, and H contents add up to 92%, and the remaining N accounts for 8%.
Assuming 1 n, 14 8% = 175, it does not match.
Assuming 2 n, 28 8% = 350, exactly match.
Assuming 3 n, 42 8% = 525, it can only be 2 n, and the relative molecular weight is 350
Then use 69% by 350 to calculate c is, the closest is 20 c(240) times 350 to get o is, the closest is 4 o(64) times 350 to get h is, the closest is 16 h (16) plus 2 n of 28, so the calculated relative molecular mass is 348 and then take it back for testing, c is 240 348 =
o is 64 348=
H is 16 is a quarter of O64, both in line.
The total number of atoms is 20 + 4 + 16 + 2 = 42
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The breakthrough is in n, because c accounts for 4 times and the O content is 4 times that of H, we can know that N accounts for 8%, and because the relative molecular mass is between 300 and 400, that is, the formula of N is between 24-32, and because the relative atomic mass of N is 14, we can know that there are 2 n atoms in the molecule, and then find the accurate relative molecular mass of 28 8% = 350, and then find the number of atoms of C h O.
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Actually, I'm just here to confuse experience.
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Is a% a mass score?
Then there is: the amount of NaOH substance is m*a% 40 ; The amount of H2SO4 substance is n*a% 98
Both are strong electrolytes, the reaction is complete, and the litmus is still purple after mixing, indicating that the two are just completely reacting, and the acid-base is just neutralized.
n(naoh)=2n(h2so4) →m*a%/40 = 2*n*a%/98
m = 80 98 n, i.e. m
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C, complete reaction, 98m=80n, while litmus purple, acid excess, n>m
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Solution: According to the meaning of the question, it can be seen that the substance is dissolved in 10 grams of water to become a saturated solution, and the solubility of the substance is x when t is set
100:x=10g:
Solution x=36g
The solubility of this substance is 36 grams at the time of answer.
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The answer should be C.
Grease emits the most calories per gram of oxidation, so the least amount of grease is needed when the same amount of heat is generated;
The least amount of glucose is released per gram of oxidation, so the maximum amount of glucose is needed when the same amount of heat is generated.
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You are right, don't be the answer to dance.
The same calorie 1kj is consumed separately, 1 18, 1, 1 can be compared with the size.
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It should have something to do with their relative molecular mass.
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