Why ethanol can discolor KMnO4 solution

Potassium permanganate is oxidizing and can oxidize ethanol to acetaldehyde or acetic acid.

Thus losing the permanganate and losing the purplish red color.

It is related to the reducibility of the hydroxyl group, and the aldehyde group is also reducible, so it is possible to oxidize to acetic acid.

The reason why potassium permanganate solution appears purplish-red is because the permanganate is purplish-red.

While ethanol is reducible, potassium permanganate has strong oxidation, so that redox reactions can occur. The permanganate is reduced, so the solution fades.

5ch3ch2oh + 4kmno4 + 6h2so4 = 2k2so4 + 4mnso4 + 5ch3cooh + 11h2o

Because purple is the color of permanganate, it is almost colorless in divalent manganese solution.

1. Ethanol can fade acidic KMNO solution. Because ethanol is reducible and acidic KMNO is strongly oxidizing, the two react to fade acidic KMNO.

The equation for the reaction of ethanol with acidic KMNO hail solution is given below.

5c₂h₆o+4kmno₄+6h₂so₄=5c₂h₄o₂+2k₂so₄+4mnso₄+11h₂o

2. Ethanol cannot fade bromine water, because although bromine water is an oxidation leakage detection agent, the oxidizing wax search is weak and cannot oxidize ethanol, so bromine water will not fade.

The answer is: Yes, hydrogen peroxide can discolor acidic KMno4 solutions. In chemistry, "OOH" can represent a number of different compounds, such as hydroxyl radicals (OH) or hydrogen peroxide (H2O2).

Here I assume that you are referring to hydrogen peroxide. Acidic KMno4 solution is an oxidizing agent commonly used for the oxidation of organic compounds. Hydrogen peroxide is a reducing agent that reacts with oxidants and reduces them.

Therefore, when hydrogen peroxide is mixed with an acidic KMno4 solution, it can reduce KMnO4 and cause it to fade.

1. Ethanol can fade acidic KMNO solution. Because ethanol is reducible and acidic KMNO is strongly oxidizing, the two react to fade acidic KMNO.

The equation for the reaction of ethanol with an acidic KMno solution is given below.

5c₂h₆o+4kmno₄+6h₂so₄=5c₂h₄o₂+2k₂so₄+4mnso₄+11h₂o

2. Ethanol cannot fade bromine water, because although bromine water is an oxidizing agent, it has weak oxidation and cannot oxidize ethanol, so bromine water will not fade.

Ethanol is reducible and can discolor oxidants, acids, potassium permanganate, or bromine.

Yes, potassium permanganate is oxidizing and ethanol is reducing, and oxidizing ethanol to aldehyde will then oxidize to acetic acid, which itself is reduced to manganese dioxide.

Hello, ethanol can react with acidic potassium permanganate solution to directly oxidize to form acetic acid (CH3COOH), the reaction equation is as follows:

4kmno4

5ch3ch2oh

6h2so4

5ch3cooh

4mnso4

2k2so4

OK. Ethanol can also be oxidized by potassium permanganate, while potassium permanganate changes from purplish-red to colorless.

The organic matter that fades the acidic potassium permanganate solution is:

1) unsaturated hydrocarbons; For example, hydrocarbons that contain carbon-carbon double bonds or carbon-carbon triple bonds.

2) homologues of benzene; Toluene, xylene, ethylbenzene, etc.

3) derivatives of unsaturated hydrocarbons; Some halogenated hydrocarbons containing carbon-carbon double bonds or carbon-carbon triple bonds.

4) some alcoholic organic compounds; For example, propylene alcohol.

5) Organic matter containing aldehyde groups: aldehyde, formic acid, formate, formate;

6) Petroleum products (pyrolysis gas, cracked gas, cracked oil);

7) Natural rubber.

Because there are no hydrogen atoms on the middle 2 carbon atoms, the oxidation reaction of ortho-carbon removing h atoms to form c=o cannot occur. So.

The acidic KMNO4 solution does not fade.

Option B polyethylene: (CH2-CH2)N

We can see that the double bond in polyethylene opens to form a long carbon-carbon single bond, in which no double bond is present, so the acidic potassium permanganate cannot be discolored.

Polyethylene. d should be 1,3-butadiene. It is thought that except for B, they all contain double bonds, which are easily oxidized by potassium permanganate.

The substances that can discolor the potassium permanganate solution are:

reacts with unsaturated hydrocarbons such as olefins, alkynes, and diolefins to fade the potassium permanganate solution;

It reacts with benzene congeners (toluene, ethylbenzene, xylene, etc.) to discolor the acidic potassium permanganate solution.

A redox reaction occurs with phenol to discolor the potassium permanganate solution.

Redox reaction occurs with aldehydes and other aldehyde organic matter, which fades the potassium permanganate solution.

It reacts with inorganic reducing agents with reducing properties (such as H2S, SO2, FeSO4, Ki, HCl, etc.) to fade the potassium permanganate solution.

The substances that can make bromine water fade or change color and the relevant chemical reaction principles are:

Unsaturated hydrocarbons such as olefins, alkynes, and diolefins react to fade bromine water.

ch2=ch2+br2——→ch2br-ch2br

ch≡ch+br2——→chbr=chbr

or CH+2BR2 – CHBR2-CHBR2

ch2=ch-ch=ch2+br2——→ch2br-ch=ch-ch2br

or ch2=ch-ch=ch2+br2-ch2-ch-chbr-ch=ch2).

It reacts with phenol to form a white precipitate.

It reacts with aldehydes and other aldehyde substances to fade bromine water.

ch3cho+br2+h2o=ch3cooh+2hbr

Mixed with benzene, toluene, carbon tetrachloride and other organic solutions, the bromine water fades due to extraction, and the organic solvent dissolves the bromine orange (or brownish-red).

React with alkaline solutions (such as NaOH solution, Na2CO3 solution, etc.) to fade bromine water.

BR2+2NAOH=NABR+NABro+H2O (or 3BR2+6NAOH=5NABr+NAB3+3H2O).

br2+na2co3=nabr+nabro+co2

It reacts with strong inorganic reducing agents (such as H2S, SO2, Ki and FeSO4, etc.) to discolor bromine water.

BR2+H2S = 2HBR+S (light yellow precipitate).

br2+so2+2h2o=2hbr+h2so4

3br2+6feso4=2fe2(so4)3+2febr3

BR2+2Ki = 2KBR+I2 (the solution turns brown).

If you can't discolor bromine water, but you can discolor an acidic KMNO4 solution, see here.