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1.If a car travels from A to B and increases its speed by 20, it can arrive 1 hour earlier than the original time. From this sentence, we know that if the speed becomes 1+20% times the original, then 1 hour earlier.
The speed becomes doubled, then the time is 1 of the original time. So the time used less is (1-5 6)=1 6Now we know that 1 hour less means that it will take 1 (1 6) = 6 hours to travel at the original speed.
2.If you increase your speed by 25 after driving 120 kilometers at your original speed, you will arrive 40 minutes early.
Here the driver divides the total distance into two sections, first studying the second section.
According to the same method as before, the speed is increased by 25%, that is, the speed is times the original, then the time used less is 1- 1 1 5, it is known that 40 minutes are less, that is, 2 3 hours, then according to the original speed, it takes (2 3) (1 5) = 10 3 hours to travel this next distance.
In the first step, we calculated that according to the original speed, it would take 6 hours to travel the whole distance, and now it will take 10 3 hours to travel the next part of the journey at the original speed, so it will take 6 10 3 = 8 3 hours to travel the first 120 kilometers, so the speed of the car is 120 (8 3) = 45 kilometers per hour.
It takes 6 hours to cover the entire distance, so the total distance is 45*6=270 km.
Seek satisfaction.
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Set: The distance between the two places is x km. Solution: x 60-6=x 80+3 Multiply both sides by 240 to get :
4x-1440=3x+720 x=2160 (km) Answer: The distance between the two places is 2160 km.
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It takes x hours to arrive on time.
From the meaning of the question, it can be seen that (x+6) 60=(x-3) 80 is solved to x=30
Then the distance between the two places is (30+6) 60=2160 (km).
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80 (6+3)=720 km 80-60=20 km.
720 20 = 36 hours.
The distance between A and B: 60 36 = 2160 km.
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The two places are located at a distance of x kilometers.
x/60-6=x/80+3
x/240=9
x=2160
The distance between the two places is 2,160 kilometers.
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Again, you asked: It would have taken x hours. 60(x+6)=80(x-8) 60x+360=80x-640 20x=1000 x=5 x=5 60(5+6)=660 Answer:
A and B are 660 kilometers apart.
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It is known that the completed line is 4/5 Then, what remains is 1 (let the total distance be 1) minus 4/5 = 1/5.
Because the title says, "Of the remaining distance, 7 10 is uphill and the rest is downhill", then the downhill road is 1 (let the remaining distance be 1) minus 7 10 equals 3 10. The title also says". It is known that the downhill road is 3 km", then 3000 divided by "3 10" (3 10 is the ratio of the downhill road) is equal to 10000 (that is, the rest of the road is 10000) as stated above":
The completed line is 4/5 Then, the rest is 1 (let the total distance be 1) minus 4/5 = 1/5" then. We can divide 10,000 by 1 5 to find the distance between A and B, which are 50,000 kilometers apart.
Solution: Let the total distance be 1
Unfinished: 1 - 4 5 = 1 5
Downhill: 1-7 10 = 3 10
3000 divided by 3 10 = 10000
10,000 divided by 1 5 = 50,000
A: --
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The remaining distance is 1-4 5 = 1 5, the remaining distance is 3 (1-7 10) = 10 (km), and the total distance = 10 (1 5) = 50 (km).
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80 (6+3)=720 km Traveling at 80 km/h will take as much time as 60 km/h will result in 720 km/h.
Because there are many trips per hour: 80-60 = 20 km.
The distance between A and B: 60 36 = 2160 km.
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80 (6+3)=720 km 80-60=20 km.
720 20 = 36 hours.
The distance between A and B: 60 36 = 2160 km.
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Total length of road ==
500x30=15000 meters.
Midpoint Roll Pants Wild is.
7500 meters.
It takes 15 minutes.
Because parking is 5 minutes.
There are 10 minutes left.
7500 10==750 m min.
For the rest of the journey, you must travel 750 meters per minute.
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The time it takes for the motorcycle to cover half the distance is 90 (65-40), then the full distance is 90 (65-40) 65 2=468
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1/2-1/3=1/6
A and B are 360 kilometers apart.
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Let A and B be x kilometers apart.
1/3*x+60=1/2*x
x=360
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If A and B are separated by xkm, then there is.
1/2-1/3)x=60
Solution x 360
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If A and B are separated by x kilometers, then x 3 + 60 = x 2 solution x = 360 km.
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1 3 is 2 3 of 1 2, so the speed when returning is 66% faster than the speed when going
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Because the distances are equal, so:
2v1=v1:v2=3:5
v2=(5/3)v1
That's a two-thirds improvement.
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Suppose the distance between A and B is s, and the percentage increase in the velocity at return is the velocity at the time of departure , then:
s/ - s/2s/2
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You seek first to know, time t1:2 t2:1,2 the distance is the same... Speaking of which, you should know how to solve it yourself.
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That's a two-thirds increase, or about 66 percent
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