A passenger car and a truck departed from A and B at the same time, moving in opposite directions

Solution, obtain: 10% of the whole journey of the truck per hour, when the whole roadway of the truck is worn through the flat and strong and suffocated with five-eighths of the platinum, the time is: 5 8 10% = 25 4 hours.

At this time, the bus line: 25 4 80 = 500 km.

The passenger car then travels one-sixth of the whole journey to place B, and the distance between A and B: 500 (1-1 6) = 600 kilometers.

The bus then travels one-sixth of the whole journey to point B

The distance between A and B: 500 (1-1 6) = 600 km

Moving in the opposite direction in mathematics.

Two objects travel in the opposite direction from two places, and after a period of time, they will inevitably meet on the way, and this type of problem is called an encounter problem.

The encounter problem is a question that studies the relationship between the number of speeds, time, and distances. It's and a general travel problem.

The difference is that it is not the motion of one object, so the velocity it studies contains the velocity of two objects, that is, the sum of velocities.

The relational formula for the encounter problem is:

Speed and time of encounter = distance;

Distance: Speed and = time of encounter;

Distance Encounter time = speed and.

Problem solving ideas and methods] Simple problems can be directly used by formulas, and complex problems can be adapted and then used by formulas.

The above content reference: Encyclopedia - Walking in the opposite direction.

Solution: The time of the encounter is 45 2 (80-65) = 90 15 = 6 (hours).

The distance between A and B is (80+65) 6 = 145 6 = 870 (km) Satisfied, if you don't know, please ask.

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Welcome to the "Mathematics and Physics Infinity" team.

Speed difference: 80-65 = 15 km/h.

Distance: 45 2 = 90 km.

The distance between A and B: (80+65) 6=870 km.

Therefore, the distance between A and B is 870 kilometers.

The distance between A and B is 825 (km).

Let the speed of the passenger car be x km h and the speed of the truck be y km h.

3y=2x①

2y+110=2x②

②：y-110=0

y=110 generationsY=110 into

2x=3×110

x = 165 i.e., the speed of the passenger car is 165 km h, and the speed of the truck is 110 km h.

The distance between A and B is: 3 110 + 3 165 = 825 (km).

Considerations for solving equations.

1. If there is a denominator, go to the denominator first.

2. If there are parentheses, remove the brackets.

3. If you need to move the item, you will move the item.

4. Merge similar items.

5. The coefficient is reduced to 1 to obtain the value of the unknown.

6. Write "solution" at the beginning.

Let the speed of the passenger car be x km h, and the speed of the truck be y km h 3y = 2x

2y+110=2x②

y-110=0

y=110 generationsY=110 into

2x=3×110

x = 165 that is: the speed of the passenger car is 165 kilometers per hour, the speed of the truck is 110 kilometers per hour The distance between A and B is: 3 110 + 3 165 = 825 (kilometers).

Reference: A and B are 588 kilometers apart, a passenger car and a truck start from the two places at the same time, go in the opposite direction, on the way the passenger car stopped for an hour in order to let the passengers eat, and the truck also stopped for 2 hours because of car repair, and the result met 7 hours later, it is known that the passenger car travels 60 kilometers per hour, find the speed of the truck? Equation solving; Let the speed of the wagon be x...

Passenger cars and trucks depart from A and B at the same time, the speed ratio of buses and trucks is 5:7, and the last two cars meet at a distance of 30 kilometers from the midpoint.

If the total length of A and B is x kilometers, then from departure to meeting, the time taken by the passenger and the truck is equal, the passenger car is x 2-30 km, and the truck is x 2 + 30 km. The time is the same, so the distance is proportional to the speed, so.

x 2-30) 5=(x 2+30) 7

7(x/2-30)=5(x/2+30),7x/2-210=5x/2+150,x=360.

So the total length of the two places is 360 kilometers. "

Passenger cars and trucks travel in opposite directions from A and B, which seems to be a classic physics problem, but such a scene is also very common in Shengnakai. In the case of passenger cars and trucks traveling in opposite directions from A and B, where are the two cars meeting?

First of all, we need to understand the difference in speed between passenger cars and vans. The usual speed of passenger cars is between 70-120 km h, while the speed of goods vehicles is usually between 60-80 km h. So, the speed of a passenger car is a bit faster than that of a truck.

Secondly, we need to know when and where buses and vans depart. If the passenger car and the truck depart from A and B at the same time, then they will meet in the middle. However, if they do not depart at the same time or from the same place, the place where they meet will be different.

In short, passenger cars and wagons travel in opposite directions from A and B respectively, and the place where they meet depends on their speed and departure time, departure place and other factors. If you need a specific calculation, you can use a physical formula to calculate it. If you just want to understand the fundamentals of passenger cars and vans moving in opposite directions, then this should meet your needs.

Also, if you need to understand the difference between passenger cars and vans, we can briefly introduce them. A passenger car is usually a tourist vehicle that is used to transport people. Whereas, a wagon is usually a commercial vehicle that is used to transport goods.

The design and purpose of the two cars are different, so there are differences in their speed, load, etc.

Finally, we need to remind everyone that both buses and vans need to follow traffic rules and safety regulations. During driving, it is important to drive safely and not to exceed the speed limit or drive fatigue. Only in this way can the safety and smooth flow of road traffic be guaranteed. <>

Trucks and buses from A and B in the opposite direction, such a scene is certainly familiar to everyone, I believe many people have encountered this situation. So, what should be done in this situation?

First, take care to keep a safe distance. Trucks and buses are relatively large vehicles, and there needs to be enough space when driving to avoid collisions. Especially when driving on the highway, it is important to keep a safe distance to avoid danger caused by excessive speed.

Second, pay attention to traffic lights. When driving on surface roads, strictly follow the instructions of traffic lights and do not run red lights at will. If you encounter a truck and a passenger car traveling in opposite directions, wait for the signal light to pass before driving.

In addition, pay attention to the blind spots of rotten macro trucks and buses. Due to the relatively large body of these two models, the blind spot is also correspondingly larger, which is easy to cause blind spots. Therefore, you should pay attention to observation during driving and avoid driving in the blind spot to avoid accidents.

Finally, pay attention to the road surface conditions. If the road is rough or there are obstacles, drive with special caution to avoid losing control or being hit.

In short, it is a relatively common situation for trucks and buses to travel in the opposite direction from A and B, but in the process of driving, you must pay attention to safety, keep a sufficient distance, obey traffic rules, and drive carefully to avoid accidents. <>

Assuming that the speed of the passenger car is 0, then the two encounters are in place A, then the truck will run three times the distance of A and B, and similarly, the two cars will run three times the distance of A and B, and then the speed is equivalent to the sum of the speed of the passenger car and the truck, so that there is (75 + 60) * 6 3 = 270

Solution: 10% of the whole journey of the truck per hourWhen the truck is 5/8 of the way through, then the truck travel time is:

5 8 (1 10) = 25 4 hours.

A and B are two places apart:

600 km.

That is, the distance between A and B is 600 kilometers.

Passenger cars travel 80 kilometers per hour, and trucks travel 10 percent of the whole journey per hourWhen the truck travels to 5/8 of the whole journey, the passenger car can reach B by 1/6 of the whole journey, and how many kilometers are the distance between A and B?

Solution, obtain: 10% of the whole journey of the truck per hour, when the whole eighths of the whole roadway of the truck is five-eighths, the time is: 5 8 10% = 25 4 hours.

At this time, the bus line: 25 4 80 = 500 kilometers The bus then travels one-sixth of the whole journey to B, and the distance between A and B: 500 (1-1 6) = 600 kilometers.

The second encounter: the bus ran the distance = 60 * 6 = 360 and the truck ran away.

The two times they meet is the distance between 2 A and B.

Distance between A and B = (360 + 450) 2 = 810 2 = 405 meters.

Solution: (60+75)*6 (2+1).

270 km.

Answer: The key to the omitted questions is:

The first encounter: two cars walk together for a distance;

Second encounter: At least one car reached the opposite side and returned, so it was three one-way distances.

1. The speed of the truck: 60 4 5 = 48 kilometers When the whole journey is: 48 1 15 = 720 kilometers.

2. The whole process of dissolution is x kilometers.

60×4/5÷x=1/15

48÷x=1/15

x=48÷1/15

x=720

Find the factors of 60 and 75. Find out the fucking maximum number of males. Multiply 6

3 hours 20 minutes = 10 3 hours. The distance between the two places.

480 km.

Truck speed (480-120) 10 3 4 (5+4)=360 10 3 4 9

48 km h.

A passenger car and a truck are traveling in opposite directions from A and B at the same time. Passenger cars travel 80 km per hour and trucks travel 65 km per hourThe truck went 51km before the bus departed, and the two cars met at the midpoint of A and B, and the bus was gone.

. 4＋5=9

Hours) A: The truck will travel for more hours to reach the first place.