Hurry!! Come and solve the super difficult elementary school questions!

Updated on educate 2024-06-08
19 answers
  1. Anonymous users2024-02-11

    Simple, first of all, take point B as a reference, when the bus arrives at B, the truck leaves B 18km, when the passenger car leaves B 22km, the truck arrives at B, indicating that the ratio of the speed of the truck to the passenger car is 22:18, and then this is a simple problem.

    It's easy to use equations, and it's okay to have none.

    If you can use the equation to let the distance from a to b be x, then x:(x-18)=(x+22): if x is not, use the velocity ratio to calculate it

  2. Anonymous users2024-02-10

    Elementary school questions, I don't know if this method can be understood.

    Let the distance of AB be S, the speed of the truck is V cargo, and the speed of the passenger car is V passenger.

    According to "when the bus arrives at place B, the truck is 18 kilometers away from the friend in place B".

    Make use of time equality to list equations.

    S V Passenger (S-18) V Cargo.

    According to "by the time the truck arrived at point B, the bus had exceeded 22 kilometers from point B".

    This means that the truck traveled 18 kilometers and the passenger car traveled 22 kilometers.

    Make use of time equality to list equations.

    18 V cargo 22 V passengers.

    Derive s 99

  3. Anonymous users2024-02-09

    Let AB be separated by S, the speed of the truck is V, and the passenger car is V.

    The equation can be multiplied by the equation v * (s v passenger) = s-18 (1) * * denotes multiplication.

    V passenger*(s v cargo) = s+22 (2).

    1)*(2) gives 4s=18*22

    s = 99a and b are 99 km apart.

  4. Anonymous users2024-02-08

    From the second sentence: v passenger v cargo = 11:9, let v passenger = 11a, then v cargo = 9a, from the first sentence, let ab be long x km, then: x-(x 11a)*9a = 18, solution: x = 99 km.

  5. Anonymous users2024-02-07

    I told you that the area you are looking for will change, not a fixed value, so you can't find it. In the figure below, although the area of ABC is not 75 square centimeters, it is AA'BC, that is, the area of ABC is equal to A'BC, other things being equal, the area and the variation:

  6. Anonymous users2024-02-06

    Fortunately, I didn't have this question in elementary school, otherwise I wouldn't have been able to pass the exam in junior high school.

    Think about it later when you squat in the toilet

  7. Anonymous users2024-02-05

    Ask your mom and dad or the teacher and they won't tell you about it??? Give me points!

  8. Anonymous users2024-02-04

    Do all elementary school students learn this kind of problem now?

  9. Anonymous users2024-02-03

    Elementary school learning this? Poor baby, I'll help you ask.

  10. Anonymous users2024-02-02

    Fart, schoolchildren learn this?

  11. Anonymous users2024-02-01

    Solution: Because the time is the same, the speed ratio is equal to the distance traveled.

    So when A arrives at place B, B has gone through 2 3

    AB distance between two changes to lead ground: 60 (1-2 3) = 180 km.

    A and B travel a total of 180 2 = 90 kilometers in 1 hour.

    A's speed: 90 3 (3+2) = 54 km/h.

    B's speed: 90-54 = 36 km/h.

    A: A's velocity is 54 km/h, and B's nucleation velocity is 36km/h.

  12. Anonymous users2024-01-31

    Calculate the distance between the two places first:

    The speed ratio of the two is 3:2, so when they meet, A repairs 3 5, and B repairs 2 5;When A goes to the second place where the infiltration calendar is not followed by 2 5 to place B, B goes to the following line: 2 5 2 3=4 15;Messy 1-4 15-2 5=15 15-4 15-6 15=5 15=1 3, this 1 3 is 60 kilometers, then 60 1 3=60 3 1=180 (kilometers) These 180 kilometers are the distance between the two places.

    Recalculate the speed:

    A: 180 3 5 2=108 2=54 (km);

    B: 180 2 5 2 = 72 2 = 36 (km).

    Check: (54+36) 2=180. A: The speed of A is 54 kilometers per hour, and the speed of B is 36 kilometers per hour.

  13. Anonymous users2024-01-30

    The speed of setting up the house is 3x, and B is 2x, then the total distance is 2*5x=10x, and within two hours, A has walked 6x, B has walked 4x, and the time taken by A to He Schindler B is 4x 3x=4 3 hours.

    Then B walked 2x*4 3=8 3x during this time, so.

    6x-8 3x=10 3x=60, so x=18, so A's velocity is 3x=54

    B's velocity is 2x=36

  14. Anonymous users2024-01-29

    1.(1) 100 million person-times, 35 million person-times.

    2) 1124+5015 61.39 million person-times.

    3) Billion. x=700*

    kg = (ton 778,330,000 km = (100 million km.)

    Dear,* Please ask if you don't understand, satisfied, thank you!

  15. Anonymous users2024-01-28

    Solution: Set the purchase price to X yuan.

    1+20%)x=60

    Solution: x=50

    When the profit percentage is reduced to 10%, the selling price is:

    A: When the profit percentage is reduced to 10%, the selling price is 55 yuan.

    Solution: The purchase price is: 60 (1+20%)=50

    When the profit percentage is reduced to 10%, the selling price is:

    A: When the profit percentage is reduced to 10%, the selling price is 55 yuan.

  16. Anonymous users2024-01-27

    Set: The original price is x

    60-x)/x=20%x=50

    When the profit percentage is reduced to 10%, the selling price is 55

  17. Anonymous users2024-01-26

    The process is as follows:

    This method uses trigonometric functions!

    The area of the shaded part in the upper right corner is the solution idea:

    s upper right shade = s abc - s red block = s abc - (s sector obc-s obc).

    Solution process: simple calculation of ac=5,bc=2 5(ACB is a right angle) tan = 5 (2 5) = ,

    S sector obc = 5 (2 2 ) = 25 s obc = 2 5 2 5 2 = 10

    s△abc=√5×2√5÷2=5

    So, S shadow abc = 5 - (25 -10) = 15-25 = s shadow = (10 10 - 5) 3 4) + s shadow abcs shadow = 75-75 4+

    s shade = 90-75

    Attach a screenshot of the answer, I'm afraid the phone looks garbled. Satisfied.

  18. Anonymous users2024-01-25

    The area of the triangle minus the area of a circle.

  19. Anonymous users2024-01-24

    Let the velocity of A be x and the velocity of B y. Distance s.

    2(x+y)=s

    x+y=s/2

    s=36

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