Set m 丨 k 2 2 n 丨 k 4 2 m and n The process of finding it

To determine the relationship between two sets, first look at who the elements in each set are and what they mean.

In this problem, the elements in the set all represent angles, of course, one k z is missing, and notice that the following ones are all added 2, so just look at what the previous one means: the first term in the set m (if the set is not represented by lowercase letters, develop a good habit), the previous term means k multiplied by 2

Looks at it as an integer multiple of 90°, and the former term in the set n represents an integer multiple of 45°, and obviously an integer multiple of 90° must be an integer multiple of 45°, and an integer multiple of 45° is not necessarily an integer multiple of 90°, so m is really contained in n

In addition, I think that this problem should be the relationship between the set m={ 丨 =k 2+ 4}n={ 丨 =k 4+ 2} m and n.

First, the equations in the two sets are divided (in order to become the same form): m becomes (2k+1) 4 and n becomes (k+1) 4

The former represents an odd multiple of 4, and the latter represents an integer multiple of 4, and it is clear that m is really included in n

For x m, then x=k2+ 2=(2k) 4+ 2 n, so m is included in n

Since there is element 4 in n and not in m.

So the relation between m and n is that m is contained in n

<> Hysan wandering hope is helpful to you, digging such as.

The set m=, the set p=, and the set m p are known

x -3x-28 Pi Jinwu 0

x-7）（x+4）≤0

4 x Burn or 7

2x-3|＞5

2x-3 5 or 2x-3<-5

2x>8 or 2x<-2

x>4 or x<-1

m p is -4 x<-1 and 4

Just solve the inequality. x 3x 28 (x 7)(x which rotten 3) 0, then 3 x 7, 丨2x 3 5, then 2x 3 5 or 2x 3 5, Li Yin leaks x 4 or x 1, m p {x 3 x Bobi-1, or 4 x 7}

Tong Zhao 1 3 1 28 0

Morph into Annihilation (A7) (4) 0

Solution: -4 x 7

2x-3|＞5

It's definitely worth it to get rid of.

2x-3 5 or 2x-3<-5

Solution x 4 or wheel slag x -1

So m p=

From the inequality -2 x 5 in the set n, take the integer solution, and get: x can be -1,0,1,2,3,4, so the set n=, then m n=

So the answer is:

Collected Chong Luhe m=, n=

According to the intersection of the fixed side of the Sen: the scattering band m n=

So the answer is.

Answer]: A Banquet Examination Situation] The main knowledge points examined in this question are the friends of the silver set of birds

Test-taking instructions] m n={2,4}

In set m: x=k 2 + 4

/4*(2k+1)

By k z, there is (2k+1).

In the odd set n: x=k 4 + 2

/4*(k+2)

By k z, then there is (k+2).

z is a subset of the set of integers.

then (2k+1) is included in (k+2).

then m is contained in n(c).

Solution: Choose B

Element m=k in set m=k 2+ 4=(4) (2k+1)element n=k in set n 4+ 2=(4) (k+2) Now compare 2k+1 with k+2

When k z, 2k+1 is the set of all odd numbers.

k+2 is the set of all integers.

m is a true subset of n, i.e., m is really contained in n.