Primary 6 math problems Application problems about inequality groups There should be a process for s

Column inequality solves practical problems, and it is a new hot spot for propositions in the high school entrance examination. Practical problems are closely related to our lives, especially resource and environmental issues, which are the focus of the proposition. The key to solving this kind of problem is to find the equality and inequality relations in the practical problem, and list the equations and inequalities.

Here are some examples of solutions to such problems. ``

1.The main types of inequalities and inequalities are multiple-choice questions, fill-in-the-blank questions, calculation questions, and solution questions. 2.

The main knowledge points examined in the content of inequalities and inequality groups are: the basic properties of inequalities, the solution set of solving a unary one-time inequality and representing the inequality on the number line, solving an inequality group composed of two unary one-dimensional inequalities and using the number line to determine the solution set, and the simple application of inequality and inequality groups.

1.The knowledge points examined in this part of equations and inequalities mainly include: listing equations according to the quantitative relationship in specific problems, solving and testing, estimating the solution of equations, solving unary equations, simple binary linear equations, fractional equations that can be turned into unary linear equations, unary quadratic equations with simple coefficients, the meaning and basic properties of inequalities, solving unary inequalities and representing the solution set on the number axis, solving the unary primary inequality group and using the number axis to determine the solution set of the inequality group, and solving simple application problems.

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Inequality group ???

I'm in the first year of junior high school now, and elementary school students can't understand it at all, and there are some knowledge that I learned in the first year of junior high school, and few elementary school students can come up with the difficulty of the other kind of application questions.

This is not beyond elementary school.

AhhAsked by: Best Fool - Assistant Level 2.

9 Cavity 9036 18 What is the difference minus by the front shirt businessman? 8.6 times the sum of a certain number and 4 is equal to, find a certain number. (Equation Solution).

1.Analysis, comprehension, application problems, finding out logical relationships, building mathematical models 2Turn logical relationships into inequalities.

3.Solve the inequality, find the intersection, and get the solution of the group of inequalities.

4.Test the solution set to remove solutions that don't fit the real problem.

5.Give an answer.

set unknowns; find the equivalence relationship; Column inequality groups; solution inequality group; Answer.

If there are x children, it will be based on"Each person gets four lollipops, leaving 26", for a total of 4x+26 lollipops.

If each person gets five lollipops, then the last child gets more than 2 pieces, but not enough 5 pieces, which means that there are x-1 people who get five pieces, then the last person gets 4x+26-5(x-1)=31-x pieces, so 2 31-x 5, solve the inequality, get 26 x 29, and since the number of people is an integer, x can only take 27 or 28

When there are 27 people, there are 4 27 + 26 = 134 lollipops.

When there are 28 people, there are 4 28 + 26 = 138 lollipops.

1: Solution, let the number in the two-digit digit be x, and the number in the ten-digit digit is y, then the two-digit number = 10x+y

25<10x+y<44

Because y-x=3, so x=y-3, substituting the above inequality, gets.

25<10（y-3)+y<44

25<11y-30<44

55<11y<74

5y=6 so x=y-3=3, two-digit = 10x+y=362: by A is uncomfortable to do one less per day, A does 100 this week, 5 working days a week, you can get: A does 100 5 = 20 per day, this is in an uncomfortable situation, under normal circumstances, A does 20 + 1 = 21 per day, because two workers make a certain amount of nets every day, so A and B are the same, under normal circumstances, B also does 21 per day, and B makes a total of more than 100 per day, and does it every day (21 + 1 =22), the total amount of work done in 5 days = 22 * 5 = 110, more than 100, so A and B have to do 21 each day.

1 First of all, less than 44 and greater than 25 can be judged that the ten digits of this number are 2, 3, 4, and the single digit is greater than the ten digits of 3, this condition is more critical, then you can get that this number is 25 (greater than 25), 36, 47 (less than 44), then the answer is 36.

2 A is uncomfortable to do one less every day, A does 100 this week, 5 working days a week, you can know that A does 20 a day, this is in an uncomfortable situation, under normal circumstances, A does 21 a day, two workers make a certain amount of nets every day, this sentence shows that A and B are the same, well, this is known, B does 21 a day, B makes a total of more than 100, 5 days a day (21 + 1 = 22), of course it will be more than 100, so A and B each do 21 a day.

1, let the single digit be a, then the ten digit is a+3, this number is 10 (a+3) + a = 11a + 3, there are 25 11a + 3 44, the solution is a = 3, then this 2 digits are 36, 2, A is now 100 5 = 20 per day, then A originally did 21 per day, B did 21 per day

1.Solution: Let the single digit be x, then this two-digit number can be expressed as x+10 (x-3), which can be solved by the inequality 25, 5< x<6 and 8 11 gives x=6, which is 36< p>

Let the ten digits be x and the single digit be (x+3).

The 25 10(x+3)+x 44 solution gives these two answers.

If there is a x person production table, then there are 84 x people producing chairs.

If it is required to be completed at least one day in advance, it can be produced in up to 5 days, and the inequality group can be listed by the question.

x 5) 12 720 5, solution, x 6084-x) 4 24 720 5, solution, x 60so, x 60

84－x＝24

So, 60 people should be arranged to produce the tables and 24 people to produce the chairs.

Number of people producing tables: 720 5 12 = 12 (group) 12 5 = 60 (people).

Number of chairs produced: 720 5 24 = 6 (group) 6 4 = 24 (people).

Solution: Set up group X to produce tables and group Y to produce chairs, then it can be obtained from the title:

5x+4y=84

12x>=720,6y>=720

The solution is x=8 and y=11

A: 8 sets of production tables and 11 sets of production chairs are used.

1. If the room on the first floor is A, then the second floor is (A 2). According to the inscription: 5a< 62, 6a> 62, a< 12 before the solution, a>10 after the solution, 10 < 10 a<12, a is an integer, so a 11.

2. Let Xiao Ming win the x plate, Xiao Liang is 9 x disk, and there is x> 3 (9-x) to get x>27 4 (that is, 6 and 3/4).

The last set has a high score for the small brightness, and the inequality is x< 3 (10 x) to get x<30 4 (i.e. 7 and 2/4), 6 and 1/4< x < 7 and 1/4, x is an integer, so x 7.

It is completely necessary to analyze according to the topic, 1. Determine what are the known and unknown quantities;

2. Set the key unknowns and try to represent the relevant unknowns;

3. List the inequalities or equations between the known and the unknown according to the size relationship described in the question, 4. Translate the conditions into mathematical equations and inequalities as much as possible;

5. Solve and inspect together.

The same is true for fractional equations, except that in the columnar process, the unknown number appears in the denominator.

Pay attention to the test of fractional equations (necessary).