The electric day and light capacity in use are used as lamps and electric converters

The circuit can change the power of the electric daily series method and the daily electricity becomes the medium inductance capacitance rate point pressure and bright without light, and the work can be lit daily. The number of associations can be used as photoelectric high to capacitance due to light due to light.

In the slowdown light movement is in the slow town. point, high wiring current, impulse disturbance to the glow combustion electricity as flow pressure lamp to will be electrodynamic due to electricity, slow heat subtown 0 and electric electricity slices sufficient, main, intertouch electricity extinguished. That is, the work point is consumed and used as a starter.

When filling the electricity part, the loss is the electricity, and the piece, the electric production, the current of one with the road anti-two charges, and the optical flow expansion is low. After receiving the lamp electric bending lamp, the lamp is not, the lamp is connected, the wire is touched and reduced, the lamp is broken, the flow 0 is connected to the day by the introduction of the form in the pass pre-made piece of the dimension in the rapid heat number plus the strong light, the joint heat and the flu lamp is the glow to flow through, the system makes the gap Jin Hui small start strike an electric into the limiter by the high, the electric gas point electric bomb and, Yu, make the electric shock, the sense of the broken road, the lamp v cause.

Mercury to light two strings of town segment by the beginning of the bend of the double small good, line compatible start about the arc with the same pressure one, the pulse of the electric gold (when touching the daylight device is not opened) the genus gold to thermoelectric heat flow gold should be when the road when the machine potential flow cold sense extinguished one plus after the inter-series rate of 1 wire when the rear wearer belongs to the rear device electric sheet second group, pressure production. : Low to electricity, the two wires of the wire have a dry can be a very daily work to touch the feeling. Add.

The town phase lamp tube lamp is connected and lowered, but the lamp is easy to expand. The joint road is angry.

For inductive ballasted fluorescent lamps, the power factor will be improved when the capacitors are paralleled, and the line losses will be reduced due to the reduction of current.

The working voltage of the fluorescent lamp is about 100V, and the ballast plays the role of limiting the current, and plays the role of arc maintenance and starting.

Starter: Heats the filament to make it easy to emit electrons, vaporizes part of the mercury, and when it is disconnected, the ballast self-inductive potential breaks through the lamp. The starter is mainly composed of bimetal sheets, the gap between the contact points is small, and when the circuit is turned on, the supply voltage is enough to cause a glow discharge through the filling gas.

Due to the different thermal expansion of the two metals, the slowly heated contact pieces produce relative bending, and after a second or two, when the contact pieces touch each other, a series circuit is formed through the ballast and the filament, so that a fairly strong current (preheating current) heats the filament rapidly. After the metal sheet is contacted, the glow discharge is extinguished, the metal sheet begins to cool, the contact point springs open, and the series circuit is interrupted, because the ballast is a high inductive reactance circuit, an induced electromotive force is generated, and a high-voltage pulse is generated between the two filaments of the lamp, and the lamp is ignited. The capacitance in the starter reduces the interference to the radio receiver when the fluorescent lamp is activated.

The function of the shunt capacitor in the fluorescent lamp circuit is to improve the power factor of the inductive ballast, which is an effective energy-saving measure.

The power factor of the fluorescent lamp is very low, about , consume a certain amount of reactive current in the grid (reactive energy is not charged), and the total current will increase after superimposing with the active current, and the wire loss will increase. The shunt capacitor can release the reactive current after charging and discharging, reducing the reactive current transmitted by the power grid.

The fluorescent lamp ballast is an inductive load, and the capacitance is added to improve the power factor of the fluorescent lamp.

The capacitor and ballast set are combined into a high-frequency oscillation, so that the lamp can be lit.

Reduce interference with electrical equipment.

First, find the current: l=40 110=

Then find the apparent power s=220*

Power factor cos = 40 80 =

Inductive reactance XL = 150

Inductance l=

Impedance Z = R + L = (300 + 20) +314 1, Current i = 220

2、ur1= ur2=

Because these two voltages differ by nearly 90 degrees, the supply voltage is equal to the vector sum of the two voltages rather than the algebraic sum.

3、p=q=s=√

cosφ=p/s=

4. Make a vector diagram, draw a line horizontally for current i, make a section of ur1 = unit in the same direction, then make 20 units forward, and then make a unit 90 degrees up. Wiring the origin to this endpoint is the supply voltage.

Fluorescent lamp inductive ballasts have a very obvious disadvantage as a driving circuit, that is, they have a hysteresis power factor of approx. The integration of low power factor appliances in the grid is considered disadvantageous because:

The power consumption is the product of the power factor cos and the RMS of voltage and current. As a result, a low power factor unnecessarily increases the demand for power supply (VA).

Since the grid voltage is fixed, when the power consumption is the same and the power factor is low load on the line, the current will inevitably increase, which reduces the payload of the configured cables and distribution equipment.

Low power factor loads waste energy and increase the burden on users ineffectively.

In order to improve the power factor of the inductor ballast circuit, a suitable capacitor can be connected in parallel to the AC power supply to correct the power factor. Such a ballast circuit is called capacitance power factor compensation, and the schematic diagram is shown in Figure 12-3-23.

In the figure, (b) is the current and voltage when the capacitor is not connected, (a) is the schematic diagram of the parallel capacitor, (c) is the improvement of the power factor after the capacitor is connected**: the current IC over the power supply voltage V0 flowing through the capacitor is 90°, if the appropriate capacitor is selected, so that the phase of the IC and IL synthetic current IO and VO is basically the same, then the IO is reduced to increase the number of power factors.

Because of the "phase" relationship, the power consumed by the capacitor is wasted by the original lamp; Therefore, the reading of the power meter and the current of the fluorescent lamp branch remain unchanged, while the power factor increases.

The power factor of an electrical device is determined by its nature and cannot be changed. After parallel compensation, the power factor of the fluorescent lamp is not increased, but the power factor of the two together is relatively high.

The power factor of the lamp is determined by the fixed inductance of the lamp, and the shunt capacitance is the power factor that compensates for this parallel circuit.

Because there is a ballast in the fluorescent lamp circuit, it is an inductor and belongs to the energy storage element. In an AC circuit, the inductor exchanges energy with the power supply. Because the magnitude and direction of the alternating current are constantly changing, the power supply energy enters the inductor for a while and is converted into the magnetic field energy of the inductor; After a while, the energy of the inductor is released into the power supply.

In this way, the current (or voltage) from the power supply to the fluorescent lamp can be understood as having two parts, one part is to supply power to the lamp to make it shine; Part of it is exchanged with the ballast. That is to say, the current of the power supply is not all converted into the light energy of the lamp, so the power factor of the fluorescent lamp is low. After the capacitor is connected in parallel, the capacitor is also a kind of energy storage element, which must also be constantly charged and discharged to exchange energy.

However, the capacitance happens to be complementary to the inductance, when one is charged, the other is discharged, and their current and voltage phase relationships are just opposite. Therefore, after the capacitor is connected in parallel, the current that originally exchanged energy between the power supply and the ballast is changed to the current between the capacitor and the inductor, and they charge and discharge each other, so the total current of the power supply is reduced. If the capacitor is selected appropriately and complements the inductor, then the total current of the power supply is equal to the lamp current, the power supply only provides the energy consumed by the lamp, and the power factor can be equal to or close to equal to 1.

This is when the efficiency of the circuit is at its highest.

The shunt capacitor must be selected appropriately, if it is not suitable, it may increase the current and reduce the efficiency.

Before it gets smaller, it's called apparent current, and when it gets smaller, it's the effective current.

Summary. How to connect the one-to-two ballast? One-in-two ballast wiring**.

There are two terminals at each end of the fluorescent lamp, which connect the two ends of the internal filament, one lamp has four wires, and two lamps have eight wires.

One to two ballasts is actually equivalent to two ballasts encapsulated together, the seven terminals are connected inside the ballast two of the two ballasted filament wires into one, and the eight terminals are independent wires. When connecting, separate the two wires connected to the lamp at the seven-terminal line, and connect them according to the diagram on the shell of the eight-terminal ballast.

Pay attention to the annotation on the diagram, the four wires connected to the lamp tube can not be mixed; Similarly, the two wires connected to the lamp can not be mixed at one end.

The power supply is on the other side, and the L and N on that side are connected to the live wire and neutral wire of the 220V power supply, and there are seven terminals on this side, and the connection method is as follows:

For lamp 1, one set of filaments (two pins at one end) is connected to 1 and 2, and another set of filaments (two pins at the other end) is connected to 3 and 4

For lamp tube 2, one set of filaments (two pins at one end) is connected to 4 and 5, and another set of filaments (two pins at the other end) is connected to 6 and 7

How to connect the fluorescent lamp with two electronic ballasts? 4 lamp legs for a total of 7 lines. The power input is at the other end.

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How to connect the fluorescent lamp with two electronic ballasts? 4 lamp legs for a total of 7 lines. The power input is at the other end.

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How to connect the one-to-two ballast? One-in-two ballast wiring**.

There are two terminals at each end of the fluorescent lamp, which connect the two ends of the internal filament, one lamp has four wires, and two lamps have eight wires.

One to two ballasts is actually equivalent to two ballasts encapsulated together, the seven terminals are connected inside the ballast two of the two ballasted filament wires into one, and the eight terminals are independent wires. When connecting, separate the two wires connected to the lamp at the seven-terminal line, and connect them according to the diagram on the shell of the eight-terminal ballast.

Pay attention to the annotation on the diagram, the four wires connected to the lamp tube can not be mixed; Similarly, the two wires connected to the lamp can not be mixed at one end.

The power supply is on the other side, and the L and N on that side are connected to the live wire and neutral wire of the 220V power supply, and there are seven terminals on this side, and the connection method is as follows:

For lamp 1, one set of filaments (two pins at one end) is connected to 1 and 2, and another set of filaments (two pins at the other end) is connected to 3 and 4

For lamp tube 2, one set of filaments (two pins at one end) is connected to 4 and 5, and another set of filaments (two pins at the other end) is connected to 6 and 7

Fluorescent lamp (ballast type), the lamp tube and the ballast are connected in series. The starter is connected in parallel with the lamp. Since the starter only works at the moment of start-up, it can be regarded as an open circuit when it is working normally.

A ballast is a reactor, that is, an inductor. Its function is to limit the operating current flowing through the lamp.

After the fluorescent tube is activated, the lamp has the characteristics of negative resistance (negative resistance, the voltage at both ends of the lamp decreases when the current increases), so the inductive reactance of the ballast must be used to limit the working current.