Is buoyancy related to the large volume of liquid being dislodged or the buoyancy of an object float

The cause of buoyancy can be analyzed by an object submerged in a regular cube in a liquid. The object of total immersion is subjected to the pressure of liquids in all directions, and it increases with depth. So the six sides of this cube are subjected to the pressure of the liquid.

Because the forces acting on the left and right sides are equal in size and at the same depth in the liquid, the pressure on the two sides is equal and the direction is opposite, and the two forces are balanced with each other. In the same way, the pressure acting on the front and rear sides is also balanced against each other. However, because the depth of the upper and lower faces in the liquid is not the same, the pressure is not equal.

The pressure above is small, the pressure below is strong, and the upward pressure below is greater than the downward pressure on the top. The pressure difference between the liquid and the object is the buoyancy of the liquid against the object. This force is equal to the weight of the liquid that is dislodged by the object.

When the top interface of a buoy does not touch the liquid, only the pressure acting upward on the bottom interface will produce buoyancy. As for an object located on the bottom surface of the container, and in close contact with the bottom surface of the container, then it can only be subjected to the liquid pressure acting downward on the surface of the object, so the object is not affected by buoyancy, this phenomenon is not much, because as long as there is a thin liquid film between it, the pressure can be transmitted, and the bottom surface has upward pressure, and the upper and lower surfaces of the object have a pressure difference, and the object will be subject to buoyancy.

The magnitude of the buoyancy is equal to the mass of the water discharged.

So whoever drains more receives more.

According to Archimedes' principle, the buoyancy of an object in a liquid is the weight of the object discharging water, and according to the information you provide, then it can be determined that the buoyancy of the object behind it is up to.

For a floating object, buoyancy is equal to gravity because it is at rest, and when it is suspended (only relative to floating), buoyancy is equal to gravity.

In general, when submerged, buoyancy is equal to the gravitational force exerted by the part of the water that the object distributes.

Experience the "greater the volume of liquid discharged from an object, the greater the buoyancy experienced".

f float = vg v is the volume of drained water.

1) The relationship between buoyancy and immersion depth, the volume of the row is the same, and the immersion depth is also the same; (2) The density of the liquid, the volume of the discharged liquid must be controlled;

Therefore, therefore, the density of the liquid is different, the depth of immersion in the liquid is different, so the relationship between the size of buoyancy and the volume of the liquid discharged, therefore, the relationship between the size of buoyancy and the density of the liquid, should be selected;

2) The density of medium and liquid remains unchanged;

8**The relationship between the amount of buoyancy and the gravitational force on which the liquid is discharged.

According to the buoyancy formula f=pvg, buoyancy is only related to the density p of the liquid discharged per mu, the volume v of the liquid discharged and the acceleration of gravity g (constant).

So the larger the volume of the object draining water, the greater the buoyancy of the bright key, and that's right.

The denser the object, the more buoyant it is, which is wrong.