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An object traveling at the speed of light will have its mass become infinite, so it will not be able to travel at the speed of light. If it can really travel at the speed of light, then the object can travel through time and space, because its mass and the mass and energy of the object on the earth are not on the same order, so it will travel through another time and space. This plane should be a high-dimensional space-time.
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Theoretical basis: the principle of relativity + the principle of invariance of the speed of light = time contraction.
Trains moving at speed v travel 1-(v c)2 times slower than those of people standing still on Earth.
c is the speed of light), if you set v=, substituting, get about a multiple. This means that 300 years of a train on Earth = 3 years of a train at 99% of the speed of light.
To put it simply, according to the special theory of relativity, the faster the speed, the shorter the time it travels, and thus the "crossing" is generated. Because it took 3 years for the light-speed train to return to Earth, but 300 years have passed on Earth. And the second question, as far as I've learned, is that the speed of the train has nothing to do with the earth.
The answers of the two friends upstairs have many nouns that people have heard for the first time.
Feel free to ask.
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Einstein's theory of relativity defines the speed of light as the highest velocity in a three-dimensional body, if an object is close to the speed of light or equal to greater than the speed of light, it will pass through the space and enter the corresponding second speed of light space (that is, there is a space, the speed of light is n times the speed of light in the current space), and when the object slows down, the object will return to the first speed of light time.
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The key to this problem is to find the angular velocity of the satellite.
During the same period of time, the Earth rotated at a certain angle, the train drove at a certain angle, and the satellites themselves rotated at a certain angle.
So the angular velocity of the satellite should be the sum of the angles of the three and divide by time, which is =(2 t t0+vt r+2 vt s) t=2 t0+v r+2 s
It's the same two people.
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When I see this question, I think of geosynchronous satellites such as gmm (r+h)2 m4 2(r+h) t, the difference is that this question has more "train travel distance s" and says that t is not to, you can think about it according to my ideas.
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The radian traveled by the train = arc length radius = s r
The angular velocity of the Earth's rotation = 2 to
The time of elapsed is s v
The radian of the earth's forward rotation = the angular velocity of the earth's rotation * elapsed time = 2 s The radian of the TOV train + the radian of the earth's forward rotation + the radius of the earth's rotation (2) is the radian of the satellite.
s/r+2πs/tov+2π
So the angular velocity of the satellite = the radian time of the satellite's motion.
s/r+2πs/tov+2π)/(s/v)=v/r+2π/to+2πv/s
Set angular velocity w, height h
w^2m(r+h)=gmm/(r+h)^2(r+h)^3=gm/w^2
Balanced according to near-earth gravity.
gmm/r^2=gm
Therefore gm = gr 2
So (r+h) 3=gr 2 w 2
r+h)^3=gr^2/(v/r+2π/to+2πv/s)^2(r+h)^3=g[r/(v/r+2π/to+2πv/s)]^2r+h=g^(1/3)*[r/(v/r+2π/to+2πv/s)]^2/3)
h=g^(1/3)*[r/(v/r+2π/to+2πv/s)]^2/3) -r
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I tell you, time is relative. The time of a train traveling at the speed of light is infinitely magnified compared to us at normal speed. So the train we see is almost standing still. It can even be understood as transparent. Because the train and we are not in the same dimension.
Time is a system, a dimension, and a frame of reference.
If the frame of reference changes, the meaning of time changes.
Just like a tortoise, it lives several times longer than us compared to us, and relative to the sun, moon and stars, it is in the blink of an eye.
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The theory of relativity, as the name suggests, first of all, our time slows down relative to them, and they see that our movements are slow, which is a melancholy light to their eyes, and time becomes longer in their eyes, and high school will also learn that there is a kind of slowness, shortening, and mass increase. The shortening of the moving scale and the slowing down of the clock are both the same principle, both because of the speed of light relative to our speed. High school physics textbooks have a shallow introduction that you can take a look at.
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The whole train is moving, of course, all at the speed of light, playing poker, if you can see clearly, you have to maintain the same speed, then it is meaningless, in fact, don't talk about the speed of light, that is, the gravitational acceleration generated by about ten times the speed of sound will crush most people.
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It is the change of time caused by the movement of the train, probably to make people understand the problem better, and it will always be said that the train is inside.
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Let the angular velocity of the satellite be , and within the time t=sv of the train travel distance, the satellite passes directly above the train again
So the angle at which the satellite is turned is t=2 tt
The VTR provides centripetal force based on the gravitational force.
gmmr+h)
mω2r+h)
According to Huang Chai trembling hunger gold substitution gm=gr2
Solution: Spike return h=3gr
tvr2πvs
r Answer: The height of the satellite from the hole to the ground is 3gr
tvr2πvsr.
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The question of relativity, the cubic m s of c = what is this stuff?
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C is a god horse? The younger brother of the speed of light? Sonic brother?
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