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Anonymous users2024-02-16The dilution factor of the pesticide is equal to the concentration of the pesticide divided by the concentration of the pesticide used, for example, the pesticide is 20% wettable powder, and the field concentration is 20%. Note:
When the dilution factor is less than 100, the water addition factor is equal to the dilution factor minus 1, and when the dilution factor is greater than 100, the water addition factor is equal to the dilution factor.
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Anonymous users2024-02-15Suppose the pesticide density is 1 gram ml.
A bucket of water is 30 catties, and a bucket of water is 10 ml.
The calculation process is as follows:
1：（1500-1）=x：（30×500）1499x=15000
x≈15000÷1500
x = 10 (ml).
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Anonymous users2024-02-14In a word: "Concentration divided by dilute minus 1", for example, 15 degrees of stone sulfur mixture should be diluted to 3 degrees, used to spray tree trunks in early spring, 15 3 5 1 4 (that is, a pound of 15 degrees of stock solution plus 4 pounds of water, it becomes a 3 degree dilution. ）；2 10 dimethoate, to be prepared in thousandths) concentration, 20 0 1 200 1 199, with 199 pounds of water per catty.
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Anonymous users2024-02-13According to the volume, suppose there is 1 liter of pesticide, add 1 liter of water to dilute 1 times, and so on.
If the amount concentration (c) and density (p) of the substance before and after dilution are known, the liquid concentration can be calculated using a formula, and the dilution factor can be calculated according to the ratio of concentrations.
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Anonymous users2024-02-12Dilution factor 500 pesticide volume = water consumption (catty) pesticide dilution factor is actually a simple statement, omit a lot of words, take 1500 times the dosage as an example, I extend it, in fact, this is a sentence: dilute 1 ml of pesticide 1500 times; The milliliter is a unit of volume, and 1500 times is 1500ml; 1500 ml of water needs to be added; Convert the relationship according to the density, volume and mass of water; The mass of 1ml of water is 1g; Then the mass of 1500ml of water is 1500g1 kg = 500g, 1500 500 = 3 kg; That's 3 catties of water! In other words, it is 1ml of pesticide, diluted with 3 catties of water!
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Anonymous users2024-02-11Suppose the pesticide density is 1 gram ml.
A bucket of water is 30 catties, and a bucket of water is 10 ml.
The calculation process is as follows:
1：（1500-1）=x：（30×500）1499x=15000
x≈15000÷1500
x = 10 (ml).
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Anonymous users2024-02-101).Dilution factor plus water calculation:
500 ml * 1000 2000 = liters * 1000 2000500 1000 liters (i.e. the total amount varies between 500 liters and 1000 liters.)
The amount of water added is: 500 liters 1000 liters.
liters (or kilograms).
2).Calculation of potassium dihydrogen phosphate water addition:
2% phosphate fertilizer + 98% water = 100% phosphate fertilizer aqueous solution.
For example: 2 pounds ......98 pounds .........100 pounds.
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Anonymous users2024-02-09Pesticide dilution conversion method!
First of all, pesticide pollution directly endangers people's health, such as eating vegetables and fruits with high pesticide residues; >>>More
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If the amount of pesticide per mu is known, the amount of water is generally 40 60 kg: if 200 grams or milliliters of a certain pesticide are needed per mu, only 200 grams of pesticide mixed with water about 50 kg can be sprayed; If only the dilution factor is known, when the multiples are greater than 100, the amount of water is equal to the number of pesticides multiplied by the dilution factor, and when the multiples are less than or equal to 100, the amount of water is equal to the dilution factor minus 1 and then multiplied by the number of pesticides. If the dilution factor is 500 kilograms of pesticides, the amount of water is equal to 500 * kilograms, and if the dilution factor is 50 and the pesticide is 1 kilogram, the amount of water is equal to (50-1) * 1 = 49 kilograms. >>>More
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