There is a flock of chickens and rabbits, and the total number of legs is 2 times more than the tota

Solution: Set x chickens and rabbits.

2x＋4y=（x＋y）×2＋18

2x＋4y=2x＋2y＋18

2x＋4y-2x-2y=18

2y=18y=18÷2

y=9 rabbits have 9.

Suppose the rabbit also has 2 legs, then the number of legs is 2 times the number of heads, and now the legs are 2 times more than the head18, and the extra 18 is because the rabbit has 2 more legs than the chicken, so the number of rabbits is 18 2 = 9.

Rabbits have 4 legs, chickens have 2 legs, and the total number of legs is 2 times more than the total number of heads 18, 18 2 = 9 rabbits.

The total number of legs of a chicken is twice as large as the head of a chicken.

The total number of legs of a rabbit is four times that of a rabbit's head.

So the extra eighteen legs can be seen as the rabbit's legs are eighteen more than twice the head, and a rabbit has two more, so the number of rabbits is 18 2 = 9.

Assuming that they are all chickens, then the total number of legs is twice as much.

So 1 times more than 18 is the extra leg of the rabbit. Each rabbit has 2 more legs than a chicken.

So rabbits = 18 2 = 9 pcs.

There are x rabbits and y chickens.

4x+2y-2(x+y)=18

4x+2y-2x-2y=18

x = 9 rabbits have 9 rabbits.

Set the chicken x, the free y chicken leg is 2x, the rabbit leg is 4y, the column formula gets 2 (x + y) + 18 = 2x + 4y, and the solution is y = 9.

Set a chicken, a rabbit has b, a total of a head a + b, a foot 2a + 4b, there are 2 * (a + b) + 18 = 2a + 4b, b = 9, rabbit has 9.

There are 9 rabbits.

Explanation and analysis: There are x rabbits and y chickens;

According to the equation: 4x+2y=2(x+y)+184x+2y=2x+2y+18

4x-2x=18

x=9So, there are 9 rabbits.

Solution 2: This is a typical chicken-rabbit cage problem, and it is still obvious, and there is no stealth deformation.

A chicken: one head, two legs;

A rabbit: one head, four legs (two legs + two legs);

The number of legs is more than twice that of the head, and the excess is the number of legs of the rabbit;

So there are 9 rabbits.

This is a typical chicken-rabbit cage problem, and it is still obvious, and there is no stealth transformation.

A chicken: one head, two legs;

A rabbit: one head, four legs (two legs + two legs);

The number of legs is more than twice that of the head, and the excess is the number of legs of the rabbit;

So there are 9 rabbits.

Suppose they are all chickens, and the legs of the chickens are exactly twice the size of their heads;

Because the total number of legs in this question is more than 2 times the total number of heads18, the extra 18 legs are all rabbits;

A rabbit has two more legs than a chicken, so a rabbit has: 18 2 = 9 (only).

The total number of legs is 2 times greater than the total number of heads, and the total number of legs of chickens = twice the total number of heads.

So the extra 18 are rabbit legs.

So rabbits have 18 2 = 9 rabbits.

A rabbit has 2 times more than a chicken, so there are 18 rabbits 2 = 9.

There are 9 rabbits.

Let's say there are x chickens and y rabbits.

So 2x+4y=2x+2y+18

So y=9 means there are 9 rabbits.

The problem of chickens and rabbits in the same cage first came from Sun Tzu's arithmetic. One of the assumptions is to think of a chicken as a one-legged chicken and a rabbit as a two-legged rabbit.

Well, a rabbit has twice as many feet as a chicken. So the extra is the rabbit's leg.

A: There are 9 rabbits.

Chicken A, Rabbit B, 2A+4B=2(A+B)+182A+4B=2A+2B+18

2b=18b=9

So there are 9 rabbits.

Let's say the chicken is x and the rabbit is y

2x+4y=2(x+y)+18

2x+4y-2x-2y=18

2y=18 y=9

2x+36=2(x+18)+18

There are 9 rabbits.

The number of legs of a chicken is twice as high as the number of heads.

The number of legs of the rabbit is 2 times the number of heads + 2, 18 2 = 9, and the rabbit has 9.

According to the title, the number of rabbits is: 18 (4-2) = 9 (only).

A: There are 9 rabbits

There are x chickens and y rabbits.

2x+4y-2（x+y）=18

2y=18y=9

There are 9 rabbits.

Analysis: According to the title, assuming that all are chickens, the number of legs is exactly 2 times the number of heads; If you exchange rabbits for chickens, the number of legs is 2 times more than 2 times the total number of heads, so now it is 2 times more than 18, and the number of rabbits you can get is: 18 (4-2) = 9 (only).

Answer: According to the question, the number of rabbits is:

18 (4-2) = 9 (only).

A: There are 9 rabbits

Solution: According to the question, the pre-hidden assumption is that all are chickens, and the number of legs is exactly 2 times the number of heads; If you exchange rabbits for chickens, the number of legs will be 2 times more than 2 times the total number of rabbits, so now it is 2 times more than 18, and the number of rabbits is: 18 (4-2) = 9 (only).

According to the question, the number of rabbits is: 18 (4-2)=9 (only) Answer: There are 9 rabbits 9,

2 legs for chickens and 4 legs for rabbits.

18 (4-2) = 9, there are 9 rabbits.

Because chickens have two legs and rabbits have four legs.

So 18 more is 2 times more than a rabbit.

So there are 18 2 9 rabbits.

If all are chickens, then the total number of legs is twice the total number of silver heads.

If you add a rabbit and subtract a chicken, the total number of legs is twice the total number of heads.2 Because the total number of legs is 16 times more than twice the total number of heads.

As far as I guessed, there were 8 rabbits.