Help with a math problem? Help with a few math problems

Updated on educate 2024-08-06
12 answers
  1. Anonymous users2024-02-15

    It takes 10 hours for a bus to go from city A to city B, so it takes 1 10 miles to complete in an hour, and it takes 15 hours for a truck to go from city B to city A, so it can be completed 1 15 miles per hour, and it can be calculated that two cars will meet at a time of 1 (1 10 + 1 15), that is, = 6 hours to meet, and when the two cars meet, the bus is 192 kilometers away from B, so this 192 kilometers is the proportion of the distance run by the truck at the time of the encounter, that is, 6 15, in other words, the truck runs 6 The distance of 15 is 192 km, so the total distance is 192 (6 15) = 480 km!

    The equation is: 1 (1 10 + 1 15) = 6 (hours) 192 (6 15) = 480 (kilometers).

    Answer; The distance between the two places is 480 kilometers.

    Shen ** points!! Hard points.

  2. Anonymous users2024-02-14

    Passenger cars travel 1 to 10 per hour for the whole journey

    Trucks travel 1 to 15 per hour for the entire journey

    They set off from both ends together, and when they got together, the two cars completed the whole journey.

    And they went all the way at a speed of (1 10 + 1 15) 1 6.

    From this, it can be concluded that they walked for 6 hours.

    At 6 hours, the bus was still 192 kilometers away from place B, and the truck traveled 192 kilometers.

    Then the speed of the truck is: 192 6 32 (kmh) because the whole journey of the truck takes 15 hours, and the speed is 32 km/h, so the whole journey is 32 15 480 (km).

  3. Anonymous users2024-02-13

    You guys are amazing.

    If I write my answers, I'll think I'm copying yours.

    All right. I can't do it here.

    A more modest compliment. You're all amazing!

  4. Anonymous users2024-02-12

    1 divided by (1/10 + 1/15) = 6 hours.

    192 divided by (10-6) = 48 km.

    48 x 10 = 480 km.

    I'll do it first, I'll divide it!

  5. Anonymous users2024-02-11

    That's it. cos[(6k+1)π/3+2x]=cos[2kπ+π/3+2x]=cos[π/3+2x]

    cos[(6k-1)π/3-2x]=cos[2kπ-π/3-2x]=cos[π/3+2x]

    f(x)=2cos(2kπ)*cos(π/3+2x)+2√3sin(π/3+2x)

    2cos(π/3+2x)+2√3sin(π/3+2x)4*sin(π/2+2x)

    4*cos(2x)

    Range: -4 f(x)4, minimum positive period: t

  6. Anonymous users2024-02-10

    Use the brackets accurately, otherwise you won't be able to understand the question.

  7. Anonymous users2024-02-09

    007 Flower Remnant Dream, Hello:

    Vector od = vector oc + vector cd = c + vector ba = c + vector bo + vector oa = c-b + a

  8. Anonymous users2024-02-08

    Since AD is parallel to BC, the vector AD is equal to BC, i.e., c-b=bc=ad, then od=ad+oa=c-b+a!

  9. Anonymous users2024-02-07

    a=od+da

    c=od+dc

    b=od+db

    db=da+dc

    a+b+c=3od+2db=od+2b

    od=a+c-b

    The picture is shown in the answer album of my space album, I hope it can help you.

  10. Anonymous users2024-02-06

    Xiaohong's house saves 12 degrees of electricity in my month compared with April, saving 5%, how many degrees of electricity does Xiaohong's family use in May?

    A cosmetic product, priced at 186 yuan, 20% cheaper than the original price, how much cheaper?

    When car A and car B travel 60% of the whole journey, and car B travels 75% of the whole journey, and the two cars are 70 kilometers apart, how many kilometers are the two kilometers apart?

  11. Anonymous users2024-02-05

    12/[186/(

    30, sell 60 on the first day, sell 60 * 60 on the second day, a total of 200 discs, sell a total of (60+72) 200 = 33 5070 (

  12. Anonymous users2024-02-04

    Question 1:

    Solution: If the electricity consumption in May is x, then the electricity consumption in April is (x-12) degree (x-12) = (1-5%) x

    x-12=95%x

    x-95%x=12

    5%x=12

    x=240 Question 2:

    Solution: Set the original price to X yuan.

    I don't have time, let the others solve the rest of the rest! Excuse me.

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