The function f x 1 defines the domain as 2,3 and finds the domain of f 1 x 2

Solution: The domain is defined by the function f(x+1) as [-2,3], therefore: -2<=x<=3 -1<=x+1<=4

That is, f(x) defines the domain as [-1,4], which in turn makes -1<=1 x+2<=4 x<=-1 3 or x>=1 2

So the function f(1 x+2) defines the domain as (- 1 3]u[1 2,+ I hope it can help you o( o

The function f(x+1) defines the domain.

is [-2,3], i.e. -2 x 3

1≤x+1≤4

So -1 1 x +2 4

1.1 x +2 -1 1 x +3 0 (3x+1) x 0 to get x -1 3 or x>0

2. 1/x +2≤4 1/x -2≤0 (-2x+1)/x≤0 (2x-1)/x≥0

Solve x<0 or x 1 2

In summary: x -1 3 or x 1 2

This is the defined domain you are looking for.

The function f(x+1) defines the domain as [-2,3], then there is -1 x+1 4

So -1 1 x +2 4 => x 1 3 , x 0;x 0, x 1 2, the intersection of the three obtains: x 1 3 or x 1 2.

Therefore, the answer to this question should be: x 1 3 or x 1 2.

The domain of the solution is defined by the function f(x+1) as follows: [Zaowei-2,3], that is, the range of x is [-2,3], so the range of x+1 is [-1,4], so the range of f is [-1,4], so in the function f(2x 2 2), the range of 2x 2 2 is [-1,4], i.e., -1, 2x 2, 2 4, i.e., 1 2 x 2, 3, i.e., 2 2 x 3, or - 3 x - 2 2....

The domain of the solution is defined by f(x+1) as [1,3], i.e., x belongs to [1,3], i.e., 1 pin chain x 3

i.e. 2 x+1 4

That is, the range of action of f is [2,4].

i.e. known by the function y=f(2x).

2≤2x≤4

Namely. 1≤x≤2

That is, the definition of the function f(2x) is the vertical forest domain [1,2].

It is known that the domain of the function f(x+1) is [-2,3] then -2 x 3 -1 x+1 Lu Yu 4 then -1 2x+1 4 is -1 x 3 2 The domain of f(2x+1) is [-1,3 2] I hope it can help you, thank you

f(x +1) defines the slag side domain as [-1,1], so the domain of the sue beam destruction of u=x 2+1 is [1,2], that is, the definition domain of f(x) is [1,2], and from 3x+1 [1,2], we get x [0,1 3], so the definition domain of f(3x+1) is [0,1 3].

Since f(x) is defined in the domain of [-1,2), 0<=|x|<2, so f(|x|) is defined as (-2,2).

x Respectfully [-1,2].

x^2-3∈[-3,1]

x-2∈[-3,1]

x∈[-1,3]

Therefore, the definition of f(x-2) is hidden in the old hall [-1,3].

Summary. Let 1 3x+1 2, and find the domain of the definition of f(3x+1).

Knowing that the domain of f(x ++1) is [-1,1], find the domain of the functions f(x) and f(3x+1).

Can you post the ** of the question?

Okay, Roger.

f(x) defines the domain as [1,2].

So the f(x) domain is the one-to-two-closed interval.

Let 1 3x+1 2, and find the domain of the definition of f(3x+1).

That is, the zero to one-third closed range.

Take a look, I hope the answer is helpful to you.