How is the pressure of water in a round teacup calculated? 20

Let the inner diameter of the cup be d, the height of the cup be h, and the vertical component: the vertical component of the pressure of water on the teacup is equal to the weight of the water in the cup, and the direction is vertical downward. f1=ρgh(π/4)d^2

Horizontal Component: The horizontal pressure of water on the round bottom at both ends of the teacup is f2 =(1 2) gd( 4)d 2

Cut along the longitudinal symmetrical plane of the cup, the cut section is a rectangle with length h and width d, the cut section divides the cylindrical surface of the cup into left and right halves, and the horizontal partial pressure of water on the left and right semi-cylindrical surface is.

f3 =(1/2)ρgd*dh=(1/2)ρghd^2

Because the horizontal pressure of the tea on the two bottoms of the cup is equal, on the contrary, the horizontal pressure on the two bottoms is zero on the whole. The horizontal partial pressure of tea on the two half-cylinders is also equal in magnitude, and on the contrary, the horizontal partial pressure on the two half-cylinders is zero on the whole.

Looking at the overall situation, the horizontal partial pressure of tea on the teacup is zero, and the vertical partial pressure is equal to the weight of water: f1 = gh(4)d 2.

No matter how the teacup is placed, the pressure of the water on the teacup is equal to the gravity of the water. Will it be greater than less than gravity? Impossible.

Unless it is filled with water and then hard poured in, there will be additional pressure.

The pressure at any point in the water = the density of the water * the acceleration due to gravity * the depth at which the point is located.

The pressure of the human side in the water = the average pressure at each point here * the area of this force surface.

Water has nothing to do with the bottom or the walls of the cup and other quantities, there is a formula: f = density (liquid) g (acceleration due to gravity) * h (height above the water surface).

There was a lecturer giving a lesson to the students, and everyone was listening attentively. A deep voice came from the silent classroom of Rumori Chang: "How much do you think this glass of water weighs?"

Some say 200 grams of spring tremor, others say 300 grams. "Yes, it's only two hundred grams. So, how long can you hold this glass of water in your hand?" the lecturer asked again.

Many people laughed: it's only 200 grams, what will happen if you take it for a long time!

The lecturer did not laugh, and he continued, "Take a minute, and you must think it's okay; If you take it for an hour, you may feel sore; Take a day or a week, then you may have to call an ambulance. Everyone laughed again, but this time it was an approving laugh.

The instructor continued, "Actually, this glass of water is very lightweight, but the longer you hold it, the heavier it feels. It's like putting pressure on your body, no matter whether the pressure is heavy or not, it will feel more and more heavy and unbearable as time goes by.

What we have to do is put down this glass of water and pick it up after a break, only then can we hold it longer. Therefore, the pressure we bear should be put down at the right time, take a good rest, and then pick it up again, so that we can bear it longer. ”

After speaking, the classroom burst into applause.

As society progresses, so do people. Then, the burden became heavier. It's a good idea to let go of the burden at the right time, take it easy, and pick it up again when you're in a better state.

First, find the pressure of the water on the bottom of the cup, p = density of water, p * depth of water in the cup, h * gravitational acceleration g

Then find the pressure of water on the bottom of the cup f = the pressure of water on the bottom of the cup p * the cross-sectional area s of the cup

With p=gh. This is the pressure formula.

The pressure f=ps, s is the area of the bottom of the cup.

So, the pressure of the water at the bottom of the cup is f= ghs.

The pressure on the bottom of the cup has nothing to do with the shape of the cup, but only with the area s of the bottom of the cup and the height of the water surface h.