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Anonymous users2024-02-151 x^2-6x+5=0
2 x^2+4x-5=0
3 4x^2-12x+5=0
4 x^2+4x+4=0
5 2x^2-5x+2=0
6 x^2+6x-7=0
7 x^2+3x-4=0
8 x^2+5x-6=0
9 a^2-5a+6=0
10 c^2+3c-4=0
11 2x^2+5x-3=0
12 x^2-6x+8=0
13 x^2-4x-5=0
14 x^2-8x+15=0
15 7x^2-8x+1=0
16 4x^2-4x-3=0
17 x^2-6x+8=0
18 x^2-2x-8=0
19 x^2+2x-8=0
20 4x^2-12x-7=0
Sorry only found these sorry.
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Anonymous users2024-02-14Because there is a quadratic side, the method of screenshots is used.
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Anonymous users2024-02-13（1）1/25（x ² 1）=
2）（2x²+2）-（
3）50(x+1)+(x+1)(x+
4) (40-3x square) (30-2) = 198 * 2 (5) 6x square - 170 + 804 = 0
6): 30 2x square 20 2 551 (7) 3x*5=8
8）16+8x=40
9)51y-y=100 (I hope the landlord will do it, this is very easy to do) (10)85y+1=-86
11）(3x+1)^2=7
12）9x^2-24x+16=11
13） (x+3)(x-6)=-8
14）2x^2+3x=0
15) 6x 2+5x-50=0 (elective) (16) (y+ 2) 2-2-4=0
17）x+1-1)(x+1-2)=0.
18）(x+3a)(x-a)=0.
19）x²+8x+16=9
20) x -5 = 4 or x -5 = -4
21）6x^2+x-2=0
22）x²+2x=3x-x²+1
23）x ^2－6x+9 =0
24）7x^2 －4x－3 =0
25) 9 to the fourth power of 25x - 1 25 = 65 (26) a to the fourth power - 81 = 52
27）(a²+9)(a²-9)=0
28）（m²-1）x²+m x -5=0（29）（3x+1）(x-1)=(4x-1)(x-1)（30）x²+x-1=0
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Anonymous users2024-02-12The system of equations for x,y x+y=3;
2x+my=n；
a1=1,b1=1,c1=3；
a2=2,b2=m,c2=n；
There is a unique set of solutions, a1 a2≠b1 b2, i.e. 1 2≠1 m--- m≠2;
There are an infinite number of solutions, a1 a2=b1 b2=c1 c2, i.e. b2=m=2, c2=n=6;
No solution: a1 a2=b1 b2≠c1 c2, i.e. b2=m=2, c2=n≠6;
A is 27 years old, B is 18 years old, and the calculation method is as follows
Let the age of A be x and the age of B be y, according to the title, there is the following equation: lack of hail noise.
y=2*(y-(x-y))；
x+(x+(x-y))=63；
Solve the system of equations and get the result x=27, y=18
o(∩_o~
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