Why does 2NaHSO4 Ba OH2 2H2O BaSO4 precipitate Na2SO4 react Na2SO4

Some reaction products are related to the amount of reactants. This equation can be written like you do, and it shows that NaHSO4 is an excess and Ba(OH)2 is an underabundance. That is to say, there is more acid and less alkali, of course, the product is acidic or the solution environment is acidic, and the alkali cannot exist in the acidic solution.

If the base is excessive, then leave it at that: NaHSO4 + BA(OH)2 = H2O + BASO4 (precipitate) + NaOH and its product is alkaline or the solution environment is alkaline.

It's probably the second year of high school, and you have to learn a chapter called "ion reaction", which is dedicated to the reaction of various ions and whether various ions can coexist in solution, which reactants are excessive, and what is generated.

I think you have already learned about redox reactions, you can balance the reaction equation of iron and nitric acid by yourself, what is produced by iron overload, and how to balance; What is produced by an overdose of nitric acid and how to trim. Later you will have to learn about the presence of both products, and you will have to calculate the amount of each substance. Study hard, come on!

Because NaHSO4 is ionized in water to produce Na+, H+, [SO4]2-, there is no NaOH because H+ reacts with OH- to form H2O.

NaHSO4 ionization produces Na ions, H ions, SO4 ions, Ba(OH)2 ionization produces BA ions, OH ions, so H ions and OH ions form H2O, Ba ions and SO4 ions form BaSO4, Na+, SO42- still exist in ionic form.

Acid-base neutralization should produce salts.

In fact, ionic reactions are written as ionic equations more clearly and accurately, because they exist in the form of ions instead of molecules in the solution, and there is no such thing as Na2SO4 in the solution, only Na+, [SO4]2-, and they do not participate in the above reaction.

So the above equation can be written.

h++oh-=h2o, isn't it very simple and clear.

oh in ba(oh)2 - as long as h+, the others are distributed by themselves.

When NaHSO4 (sodium bisulfate) reacts with Ba(OH)2 (hydrogen collapse barium oxide), the resulting products are Na2SO4 (sodium sulfate) and BA(HSO4)2 (barium bisulfate) instead of NaOH (sodium hydroxide).

The equation for the reaction is as follows:

nahso4 + ba(oh)2 → na2so4 + ba(hso4)2

This is because in the reaction, an acid-base reaction occurs between sodium bisulfate (NaHSO4) and barium hydroxide (Ba(OH)2). In the acid-base neutralization reaction, the hydroxide ion (OH-) is derived from barium hydroxide, which replaces the hydrogen ion (H+) in sodium bisulfate. This causes the hydrogen ions in the sodium bisulfate and the hydroxide ions in the hydroxide macrobarium to combine to form two products, Ba(HSO4)2 and Na2SO4.

Ba(HSO4)2 can be broken down into BASO4 (barium sulfate) and H2SO4 (sulfuric acid).

In summary, the products formed by the reaction of NaHSO4 with Ba(OH)2 are Na2SO4 and BA(HSO4)2 instead of NaOH.

NaHSO4 reacts with Ba(OH)2.

1.When the amount ratio of NaHSO4 and Ba(OH)2 substances = 2:1.

2nahso4 + ba(oh)2 = na2so4 + baso4 + 2h2o

Ion 2H+ +SO42- +Ba2+ +2Oh- =BaSO4 + 2H2O

2.When the amount ratio of NaHSO4 and Ba(OH)2 substances = 1:1

nahso4 + ba(oh)2 = baso4 + naoh + h2o

Ion H+ +SO42- +Ba2+ +OH- =BaSO4 + H2O

When NaHSO4:BA(OH)2=1:1, the reaction formula is NAHso4+BA(OH)2=BASO4+NAOH+H2O

When NaHSO4:Ba(OH)2=2:1, the reaction formula is 2NaHSO4+BA(OH)2=BASO4+Na2SO4+2H2O

If ba(oh)2 is sufficient:

NaHSO4 +BA(OH)2 ==BASo4 precipitate + NaOH +H2O

If Ba(OH)2 is small.

2NaHSO4 +BA(OH)2 ==BASO4 precipitate +Na2SO4 +2H2O

Sulfur dioxide and saturated barium nitrate form precipitates, which are not essentially weak acids to strong acids.

The reaction process is actually like this: SO2 and water react to form H2SO3The reaction takes place in solution, so there are H+, H+ and NO3- which oxidizes it to sulfuric acid, and SO42- and BA2+ form a precipitate.

i.e. 3SO2 + 2NO3- +3BA2+ +2H2O = 3BASO4 +2NO + 4H+

Nothing to do with saturation. The general ionic reaction has nothing to do with saturation, about the strong acid to make weak acid, it can be explained by chemical equilibrium, it is estimated that you have not learned, take a look at it first, understand: the more acidic acid can produce the less acidic acid, because the ionization degree of the stronger acid in the aqueous solution is greater than the weaker acid, and the hydrogen ions produced by ionization can be combined with the acid root ions of the weaker acid to form the weaker acid molecules that are difficult to ionize "free" from the system, resulting in the chemical balance moving in the direction of generating weaker acid.

Weak acids cannot cause the equilibrium to move in reverse.

Sulfur dioxide corresponds to a weak acid and cannot metacompose with strong salts.

It undergoes a redox reaction with barium sulfate, which is produced from barium nitrate. Sulfur dioxide can provide acidity, which is equivalent to the oxidizing nitric acid that produces oxidizing sulfur dioxide to obtain sulfate.

Sulfur dioxide dissolved in water will have hydrogen ions, and the nitrate ions and hydrogen ions in barium nitrate will oxidize sulfur dioxide together to form sulfate and then combine with barium ions to form precipitate.

Because the SO42- precipitation is complete, the stoichiometric number of Ba(OH)2 is 2

In this way, 4 mol of OH- is provided, which exactly converts NH4+ to NH3 and Al3+ to AL(OH)3

The ionic equation is.

nh4+ +al3+ +2 so42- +2 ba2+ +4 oh- = al(oh)3↓ +nh3↑ +h2o + 2 baso4↓

The chemical equation is.

nh4al(so4)2 + 2 ba(oh)2 = al(oh)3↓ +nh3↑ +h2o + 2 baso4↓