Why does H2O2 H2SO4 Cu react

Concentrated hydrogen peroxide is very oxidizing and will directly oxidize copper element.

Reason: Hydrogen peroxide contains a large number of original oxygen atoms [O], which has strong oxidation, which makes Cu oxidize and form various oxides of copper.

Equation: Cu+H2O2=Cuo

H2O then dilute sulfuric acid reacts with copper oxide:

h2so4+cuo=cuso4+h2o

So H2O2, Cu, H2SO4 can react together.

Hydrogen peroxide: The chemical formula of hydrogen peroxide is HO, commonly known as hydrogen peroxide. The appearance is a colorless transparent liquid, which is a strong oxidant, and its aqueous solution is suitable for medical wound disinfection, environmental disinfection and food disinfection.

In general, it will decompose into water and oxygen, but the decomposition rate is extremely slow, and the way to speed up the reaction is to add a catalyst - manganese dioxide or irradiate it with short-wave rays.

Copper sulfate: Copper sulfate (chemical formula: CuSO4), which is a white or off-white powder.

Its aqueous solution is weakly acidic and blue. Copper sulphate is an important raw material for the preparation of other copper-containing compounds. Bordeaux liquid can be obtained by mixing with lime milk, which is used as a fungicide.

At the same time, copper sulfate is also the electrolyte used in electrolytic refining of copper.

The common form of copper sulfate is crystalline, copper monohydrate sulfate tetrahydrate ([Cu(H2O)4]SO4·H2O, copper sulfate pentahydrate), which is a blue solid (crystal). Its aqueous solution is blue due to the hydrated copper ions, so anhydrous copper sulfate is often used in laboratories to test the presence of water.

The essence of the reaction is carried out in two steps.

The first step is hydrogen peroxide.

Copper oxide is first formed on the surface of the copper.

As follows: Cu + H2O2 = Cuo + H2O In the second step, copper oxide reacts with dilute sulfuric acid to obtain copper sulfate.

and water: cuo + h2so4 = cuso4 + h2o So, combine the above two formulas into one, i.e.:

cu + h2o2 + h2so4 = cuso4 + 2h2o

Cu2+ +==Cu(OH)2 is dissolved +2NH4+

In excess, Cu(OH)2 dissolves and dissolves the extermination limb excavation.

cu2+ +==cu(nh3)4]2+ +4h2o

The essence of this reaction is carried out in two steps.

In the first step, hydrogen peroxide first forms copper oxide on the surface of the copper, as follows:

Cu + H2O2 = Cuo + H2O In the second step, copper oxide reacts with dilute sulfuric acid to obtain copper sulfate and water:

cuo + h2so4 = cuso4 + h2o So, combine the above two formulas into one, i.e.:

cu + h2o2 + h2so4 = cuso4 + 2h2o

Crazy line...Hydrogen peroxide oxidizes copper to copper oxide, which reacts with dilute sulfuric acid to form copper sulfate....That's just putting the two reactions together....o～o

Mr. into a light blue basic copper sulfate precipitate.

2[cu(nh3)4]2+ +6h+ +so4)2- +2h2o = cu2(oh)2so4↓ +8(nh4)+

In secondary school, it can also be considered that the blue Cu(OH)2[Cu(NH3)4]2+ +2H+ +2H2O = Cu(OH)2 +4(NH4)+

When excess H2SO4 is added, the pellet dissolves into a blue solution Cu2(OH)2SO4 + H2SO4 = 2CuSO4 + 2H2O

cu(oh)2 + h2so4 = cuso4 + 2h2o

Copper is a transition metal, with strong coordination (coordination number 4), Cu 2+ often exists in the form of complex ions in solution, showing different colors.

In the aqueous solution, copper ions and water form [Cu(H2O)4]2+, which appears blue, that is, the blue color of soluble copper salts is the color of complex ions formed by copper ions and water.

In the higher concentration of CuCl2 solution, copper ions and chloride ions form tetrachloro-copper complex ions [CuCl4]2-, the color of the complex ion is yellow, and a part of the copper ions in the solution form blue [Cu(H2O)4]2+, and the mixed color of yellow and blue is green, so the very dilute CuCl2 solution is blue, and the concentrated CuCl2 solution is green.

Answer]: NH3 is a strong ligand, and Cu2+ solution forms a culaminocomplex ion [Cu(NH3)4]2+, which is dark blue.

The addition of dilute H2SO4 neutralizes NH3 and turns [Cu(NH3)4]2+ back to blue Cu2+.

Cu2+ +4NH3 = reversible = [Cu(NH3)4]2+

cu(nh3)4]^2+ +4h+ == cu^2+ +4nh4+

Phenomenon]: The solution turns dark blue to light.

Metathesis reaction undergoes to form water and copper sulfate.

It cannot react because the activity of copper is weaker than that of hydrogen, and the activity of reacting with sulfuric acid must be greater than that of hydrogen.

Upstairs is incorrect, the second reaction source is present when Fe3+ catalyzes the decomposition of H2O2 into BAI.

The equation duh2o2 + 2fe3+ =o2 + 2fe2+ +2h+h2o2 + 2fe2+ +2h+ =2fe3+ +2h2o together is 2h2o2=2h2o+o2, which is equivalent to fe3+ does not participate in the anti-DAO response, which plays a catalytic role.

As for the situation you are talking about.

H2O2 will preferentially react with Fe2+ (because Fe2+ is more reducible than H2O2, so it reacts preferentially), oxidize Fe2+ to Fe3+ (the product is water, no impurities will be introduced), and then it will be decomposed under the catalysis of FeCl3 (this can also prevent the introduction of impurities, because the product is water and oxygen), so a small amount of FeCl2 in FeCl3 can be removed by adding a slightly excess of H2O2

2Fe2 H2O2 2H2Fe3 2H2O only this reaction occurs, and this (2Fe3 H2O2 2Fe2 O2 2H) does not react to the counter-dedication.

Oxidation of Fe2 with H2O2 produces water without introducing new impurities.

It will not be reduced back to bai, the second reaction does not exist at all, the oxidation of zhih2o2 is stronger than that of the trivalent DAO iron ion version, the trivalent iron ion can only catalyze the decomposition of hydrogen peroxide, and is not enough to oxidize hydrogen peroxide, of course, it is not excluded that these two micro reactions exist at the same time in the catalytic process, but from a macroscopic point of view, the final result of the reaction is that the ferrous ions are oxidized, and the ferric ions will not be reduced.