-
Anonymous users2024-02-15b Hello owner of the second floor! Let me explain it to you. First of all, I'm sure you should know that the length of the latitudes on Earth is getting smaller and smaller from the equator to the poles.
So, at this point, A walks the shortest distance, and conversely, B walks the longest distance. And the title says "and arrive at the same time," so it can be explained mathematically: to arrive in the same time, the longer the journey, the faster the speed.
Remember, not "A"! He asked about "speed", not time. Got it?
-
Anonymous users2024-02-14Suppose that A, B, and C sit on the length of the parallels a, b, and c, respectively. Example diagrams are important,>
The distances traveled by A, B and C are:
A: (5 360) A
B: (5 360) b
C: (5 360) c
Because B is at the equator, and the equator is the longest parallel, so B>A, B>C travel to the destination for the same time, and the longest distance traveled in a certain period of time runs the fastest, so in the end it is B that has the largest speed. The answer is B B.
-
Anonymous users2024-02-13It is A, according to the length of time, it should be the shortest A, second to C, and the longest B, which can be understood simply in this way, the earth is a circle of o degrees, that is, at the equator, the line is the longest, and the shorter it is at the poles, and it can also be understood that the radius at the equator is the largest, and at 60n, the radius is the shortest, so the length of the arc is the shortest.
-
Anonymous users2024-02-12The speed of choosing a A ship is the slowest. The longer the latitude, the shorter the length of the high latitude, the same span of 5° longitude, and the length of the actual excavation at 60°n is only half of the length of the equator.
-
Anonymous users2024-02-11The circumference of the equator on the globe, from the equator to the poles, the latitude gradually shortens, to the poles only shrink to a point, so the three ships at A, B, and C set off for the 180° meridian when they pointed to the mountain, and arrived at the same time, and the slowest speed was A at 60°N
Therefore, a
-
Anonymous users2024-02-10A C distance: s1 = 160-40 = 120km
B-C distance: s2=160-0=160km
Ship speed: V1=S1 T1=120 6=20km H Speed Boat Speed: V2=S2 T2=160 (5-1)=40km H4-1=3h
When the two ships were 30 kilometers apart, the ship traveled for t hours.
20t-[40(t-1)-40]=30
t=Ship distance from port C: S1-TV1=
-
Anonymous users2024-02-09Establish; The distance traveled by ship B is x, and the distance traveled by ship A is x+12 solution; (2x+12)÷78=8
2x+12=624
2x=612x=306
A is B is.
-
Anonymous users2024-02-08If the speed of ship A is x km h, then the speed of ship B is 78-x km h8x-8(78-x)=12
16x=636
x=78-x=
The speed of ship A, the speed of the repentant limb of ship B.
-
Anonymous users2024-02-07Let the speed of A be x km/h, then the velocity of B is (78-x) km/h.
According to the inscription, after 8 hours, A walked 12 kilometers more than B.
8x-8(78-x)=12
x= kilometers per hour.
kilometers per hour.
A speed km h B speed km h.
-
Anonymous users2024-02-06Solution: If the speed of ship A is x kilometers per hour, then the speed of ship B is 78-x kilometers per hour 8x-8*(78-x)=12
If the solution is x=, then the speed of ship B is 78-x=kilometers hours Answer: The speed of ship A is kilometers per hour, then the speed of ship B is kilometers hours, if you don't understand anything about this question, you can ask, if you are satisfied, please click on the upper right corner to praise and "adopt as a satisfactory answer".
Your adoption is the driving force for my service.
Good luck with your studies!
This is an old logical question.
It's not a programming problem. >>>More
At first glance, it looks like a child asking exam questions! No one can answer for you without a diagram! The dairy industry is generally in the suburbs of the city, the fishery is in the seaside, lake or riverside area with water, and the forest and fruit industry is generally in the low mountainous or hilly areas!
A, B and C completed a project together, completed all 1 5 in 3 days, and then A rested for 3 days, B rested for 2 days, and C did not rest, if A's workload in one day is 3 times that of C's workload in one day, and B's workload in one day is 4 times that of C's workload in one day, then how many days does this work be completed from the beginning? >>>More
Analysis: According to the title, as shown in the figure below, when A walks to B, B walks to D, and C goes to C, A is 3 kilometers faster than B, and B is 2 kilometers faster than C, so DB is 3 parts, and CD is 2 parts, B takes 10 minutes to walk 3 parts, and C takes 20 minutes to walk 5 parts, so the speed ratio of B and C is 6:5; >>>More
This case mainly involves the following key issues: first, where should the contract be left if one of the parties to the contract dies, second, whether the rural land contract can be subcontracted and what conditions and regulations are required, and third, the ownership of the ancillary facilities on the land after the land contract. First, according to the legislative spirit of the Contract Law, if the legal heirs of one party deceased and the other party to the contract agree, the subject of the contract may be changed to continue to perform, and secondly, the rural land contract can be subcontracted, but it must be subcontracted within the scope specified in the original contract, and finally, the appurtenances on the land are only subcontracted together with the subject matter of the contract, that is, the use and transfer of its ownership has not changed.