The neutralization reaction occurs in the dilute solution of strong acid and strong alkali, and 57 3

The concept should first be clarified, the essence of the neutralization reaction is the reaction of hydrogen ions and hydroxide ions to form water, and the concept of neutralization heat is the heat emitted by the reaction of 1 mole of hydrogen ions and 1 mole of hydroxide ions to form one mole of water.

As long as 1 mole of water is generated, the heat emitted is definitely released, and when it comes to the formation of weak electrolytes, hydrolysis is mentioned. Hydrolysis is the reverse reaction of the neutralization reaction, so hydrolysis is endothermic. However, in any case, when the acid-base reaction, the neutralization reaction and the hydrolysis reaction are in the same process, so when 1 mole of water is generated, the heat released must be.

It is important to understand the concepts in chemistry.

H+(AQ) +OH-(AQ) = H2O(L), the change H = The above thermochemical equation refers to the fact that H+ aqueous solution and OH- aqueous solution only generate 1mol of liquid water, which is exothermic.

The neutralization reaction of strong acid and strong alkali dilute solution to produce salt and water generally conforms to the above thermochemical equations.

But there is one exception, Ba(OH)2+H2SO4, which also generates BaSO4 precipitation, and Ba(OH)2+H2SO4 BASO4+2H2O, which releases more heat ratio, because the generation of BaSO4 is also an exothermic process.

So the change h<

Of course not. If the electrolyte is generated, it will be less than that.

Because of the heat of water desorption.

Pick B. Because concentrated sulfuric acid is added to barium sulfate, it will definitely be exothermic, so its h is very small than dilute sulfuric acid and dilute nitric acid, and it is coarse, but because dilute sulfuric acid will react with barium hydroxide to generate water and barium sulfate precipitation, due to precipitation, there is not only h (aq) oh (aq) h2o(l); H also has the heat of reaction to generate precipitate, so the h of dilute sulfuric acid is smaller than that of dilute nitric acid. Therefore, choose B

If the amount of NaOH of the same substance is reacted with dilute acetic acid, concentrated sulfuric acid, dilute nitric acid to form the amount of water of the same substance, the same amount of heat should be released without considering the heat of dissolution of the substance and the ionization heat absorption of the weak electrolyte.

However, in the actual reaction, concentrated H2SO4 is exothermic when dissolved in water, and the total heat released increases, and acetic acid is a weak acid, which proceeds with the reaction. Acetic acid continues to ionize, and ionization has to absorb heat, so it is less exothermic when neutralized. This question asks about the relationship between the heat of reaction, the more heat released by the reaction, the smaller the h value, and the d term is correct.

Dilute acetic acid ionization consumes energy, so exothermic is less than.

The dilution of concentrated sulfuric acid should be exothermic, so the exothermic is greater than.

Dilute nitric acid is exactly.

Since exothermia is indicated by a negative sign, the more exothermic it is, the smaller the h valueAnswerd

The thermochemical equation is: H++OH-=H2O

Dilute sulfuric acid is a dibasic strong acid; 1 mol of sulphuric acid can provide 2mol of H+ and is therefore exothermic.

The thermochemical equation is: H++OH-=H2O dilute sulfuric acid is a dibasic strong acid; 1mol sulfuric acid can provide 2molh+ of disadvantages, because the rent is only to be able to release heat.

Dilute acetic acid is a weak acid, and the hydrolysis is incomplete, so the complete reaction requires the consumption of a part of the hydrolysis of concentrated sulfuric acid to be diluted first, and then completely reacted, while the dilution of concentrated sulfuric acid will release a large amount of hot dilute nitric acid, which is a normal reaction.

Note that since h is a negative value when radiating heat, therefore, the h with less exothermic is larger earthlinye answer, please adopt if you are satisfied, thank you for this is the support and motivation for the answerer.

Concentrated sulfuric acid is added to barium sulfate, which will be exothermic, so its h is smaller than dilute sulfuric acid and dilute nitric acid, but because dilute sulfuric acid will react with barium hydroxide to form water and barium sulfate precipitation, that is, there is a reaction heat generated by barium sulfate precipitation, so the h of dilute sulfuric acid is smaller than dilute nitric acid. So choose B

It should be h1< h2= h3, and the answer is as follows:

Because it happens to be a complete reaction, the number of hydroxides involved in the reaction is the same, and the heat of neutralization is the same.

And because dilute sulfuric acid and dilute nitric acid are dissolved in water and do not release heat, while concentrated sulfuric acid is dissolved in water and releases a large amount of heat, the thermal effect of the reaction increases.

Whereas, the thermal effect of the exothermic reaction is negative.

H1< h2= h3.

There's something wrong with this option, right?

The most exothermic is , because in addition to the heat of neutralization, the dissolution of concentrated sulfuric acid must also be equally exothermic.

So the absolute value of h |△h1| ＞h2| = |△h3|Exothermic reaction, h 0, so the greater the absolute value, the smaller the value h1 h2 = h3

Pick B. Because concentrated sulfuric acid is added to barium sulfate, it will definitely be exothermic, so its h is very small than dilute sulfuric acid and dilute nitric acid, but because dilute sulfuric acid will react with barium hydroxide to form water and barium sulfate precipitation, due to the precipitation, there is not only h (aq) oh (aq) h2o(l); H, and the heat of reaction to form precipitate, so the h of dilute sulfuric acid is smaller than that of dilute nitric acid. Therefore, choose B

Because the concentrated sulfuric acid is dissolved and exothermic, H1 is the largest, because it happens to be completely reacted, so the solution after the reaction of 2 and 3 is neutral, so H2=H3 so choose C

There is one mol of hydroxide

The addition of concentrated sulfuric acid will dilute it, it will be exothermic and there will also be heat of reaction.

2 ,3 The added hydrogen ions are equal and the heat of reaction is also equal Only the heat of reaction c is selected

NaOH solid, there is heat of hydration, so it is the most exothermic;

dilute naoh, exothermic happens to be ;

Dilute NH3·H2O, weak base, can not completely neutralize the reaction, and the heat release is the least.

So choose b (pay attention to the symbol, the enthalpy change should be compared with the symbol ratio).