Can 2Na2O2 2CO2 2Na2CO3 O2 undergo centering reaction? I will definitely answer in detail, thank you

No 2Na2O(-1)2+2Co(-2)2====2Na2Co(-2)3+O(0)2 According to the principle of non-crossing, two of the four -1s become -2 and the other two sides become -2

Note: The answer is a reference to someone else.

The reaction mechanism of CO2 and Na2O2 can be proved by tracer atom analysis.

NA2O2+C18O2+H218O=2NA2C18O3+2H2O+O2Some students think that water participates in the reaction and accelerates the chemical reaction rate, and the quality and properties of the reaction itself have not changed, so water is the catalyst of the reaction. Analysis: In the presence of water, the reaction can be regarded as the metathesis reaction of Na2O2 and H2CO3 first, and the generated H2O2 is then separated to release O2 Na2O2 + H2C18O3 = Na2C18O3 + H2O2 and then 2H2O2 = 2H2O+O2, and the analysis of these two steps of the reaction can find that the generated water is not the water that participates in the reaction, so the water cannot be regarded as the catalyst of the reaction.

When calculating the reaction of a certain amount of Na2O2 with a mixture of CO2 and H2O, the problem of the sequence relationship can be regarded as the reaction of Na2O2 with CO2 first, and then with H2O after the CO2 reaction is complete, but the actual situation is much more complicated.

Let carbon monoxide and methane be mg

Then the oxygen consumption of carbon monoxide is (m 56)*32=32m 56, and the oxygen consumption of methane is (m 16)*32*2=64m 1664m 16, which is greater than 32m 56

Methane is oxygen intensive.

It is a redox reaction.

Redox reaction concept.

The essence of the reaction is that there is a change in the oxidation number, that is, there is a transfer of electrons. The oxidation number is increased, that is, the electron loss of the half reaction is the oxidation reaction.

The oxidation number decreases, and the reaction to obtain electrons is a reduction reaction. The substances with an increased oxidation number reduce each other and are oxidized by themselves, so they are called reducing agents, and their products are called oxidation products; The substance with a reduced oxidation number oxidizes the other party and is reduced by itself, so it is called an oxidant, and its product is called a reduction product.

Before and after the reaction, there are trillion potato cracking elements that have valence.

Lifting. 2Na2O2+2CO2=2Na2CO3+O2, in this reaction, Na2O2 is the oxygen element.

The valency is -1 valence, in which half of the oxygen-group occlusion valency changes from -1 to 0 valence in O2, and the other half changes from -1 valence to -2 valence in Na2CO3.

First of all, I'll fix the equation for you.

2co+o2=2co2

1.Substance reactions: Carbon monoxide reacts with oxygen to produce carbon dioxide.

2.Microscopic significance: Two carbon monoxide molecules and one oxygen molecule react to produce two carbon dioxide molecules.

3.Macro significance: The production of two volumes of carbon dioxide consumes two volumes of carbon monoxide and one volume of oxygen.

There is a two-wire bridge that can be seen that 2mol of sodium peroxide reacts and transfers 2mol of electrons.

The valency of oxygen is partially increased, and the valency of some is decreased.

Please adopt it promptly if you understand!! Good luck with your studies!!

The valency of O in Na2O2 is an increase and a decrease.

What is a self-weight fraction of 80%.

See figure. The oxygen in Na2O2 is -1 valence, which becomes -2 valence (Na2CO3) and 0 valence (O2) after the reactionAn oxygen atom gets an electron from -1 to -2 valence; An oxygen atom loses one electron from -1 to 0 valence.

An oxygen molecule has two oxygen atoms and loses 2 electrons. At this time, try to take the coefficient of Na2O2 as 2, so that the coefficient of Na2CO3 is also 2 (calculated as sodium); Then the coefficient of CO2 is also 2 (calculated by C), and then the coefficient of O2 is calculated to be 1

Option A can be passed through the valency analysis of oxygen elements, all the oxygen in CO2 is transferred to sodium carbonate and there are still two missing, and the 4mol oxygen atom in 2mol of sodium peroxide has 2mol of valency increased to generate oxygen; There is a decrease in the valency of 2mol transferred to sodium carbonate.