What can be observed by putting Na2O2 into the FeCl2 solution

Phenomenon: There are bubbles generated, a large amount of heat is released, and white precipitates are produced in the solution, and then the color quickly becomes darker, and when it is standing, it gradually changes from gray-green to reddish-brown precipitate.

Reaction principle: 2Na2O2 + 2H2O = 4NaOH + O2 (G) NaOH + FeCl2 = NaCl + Fe (OH) 2 (colloid) Fe (OH) 2 + O2 = Fe (OH) 3 (colloid) sodium peroxide into the solution, first react with water to generate sodium hydroxide and hydrogen peroxide, hydrogen peroxide is unstable, decomposes to produce water and oxygen, this new oxygen oxygen atoms.

The oxidizing capacity is strong, but even in the absence of oxygen atoms, the dissolved oxygen in the water is enough to oxidize Fe(OH)2.

The white precipitate is Fe(Oh)2 and gray-green is an intermediate of Fe(Oh)2 and Fe(Oh)3, which is formed by the combination of 5 to 11 Fe(Oh)2 and Fe(Oh)3.

The reddish-brown precipitate is Fe(OH)3

Typing is so hard, and for me, who took the college entrance examination this year, I am still very happy to be able to help some people.

There are bubbles that produce [O2], white precipitates that produce [Fe(Oh)2], and then quickly turn into reddish-brown precipitates [Fe(Oh)3].

The equation is referenced below.

2Na2O2+2H2O=4NaOH+O2 (gas) NaOH+FeCl2=NaCl+Fe(OH)2 (precipitation) Fe(OH)2+O2=Fe(OH)3

A little oxygen is always dissolved in water, and Fe(OH)2 is highly susceptible to oxidation.

I wish you an upward movement every day.

Wrong wrong. It is a reddish-brown precipitate that is formed at the beginning. And gas.

Absolutely. Because I've done that. Also missed.

There is absolutely no white precipitate formation. Fe(OH)2 will not be generated. Fe(OH)3 will be generated directly.

Because Na2O2 has strong oxidizing properties. If you go down, Fe2+ will become Fe3+. Be careful.

Sodium peroxide is put into the solution and first reacts with water to form sodium hydroxide and hydrogen peroxide, and hydrogen peroxide reacts with ferrous ions to form ferric ions and water. Brownish-yellow is the color of the ferric ion solution.

I wish you an upward movement every day.

First, Na2O2 reacts with water:

2Na2O2 + 2H2O = 4NaOH + O2 Phenomenon 》The pale yellow solid dissolves, and bubbles emerge and release heat.

NaOH then reacts with FeCl2:

1) 2NaOH + FeCl2 = Fe(Oh)2 + 2NaClFe(Oh)2 is oxidized by water with oxygen in the air.

2) 4Fe(OH)2 + O2 + 2H2O = 4Fe(OH)3 phenomenon" has gray-white precipitation, then the color quickly turns gray-green, and finally turns into reddish-brown precipitation.

1. There are a large number of colorless bubbles.

2. The light green color of the solution fades to generate a reddish-brown precipitate.

There is reddish-brown precipitate Fe(OH)3 formation, and there are bubble formations.

A reddish-brown precipitate Fe(OH)3 precipitate is generated.

There are bubbles generated.

A red sedimentation (Fe(OH)3) is generated, and gas is emitted.

Reddish-brown precipitate.

There are bubbles generated.

Answer]: FE2+

Ni2+ and CO2+

The salt solution is added to NaOH to form the phase-sensitive hydroxide Fe(OH)2Ni(OH)2

and Co(OH)2

But Fe(OH)2

It is easily oxidized by oxygen in the air, and changes from gray-green to reddish-brown Fe(OH)34Fe(OH)2O22H2

o===4fe(oh)3

co(oh)2

They are also easily oxidized by air, turning from pink to brownish-black Co(OH)34Co(OH)2O22H2

o===4co(oh)3

and Ni(OH)2

It is not oxidized by air, and the canon still exists in the form of light green Ni(OH)2.

Write the chemical equation for this reaction as follows:

10cl2+20naoh=16nacl+naclo+3naclo3+10h2o

Reduced chlorine: 16NaCl

Oxidized chlorine: naclo + 3naclo3 = 4cl Therefore, the ratio of the amount of reduced chlorine to the oxidized chlorine element = 4:1 gives a satisfactory ......It's not easy to type.

According to baiclo- vs. clo3

The ratio of concentrations is 1:3, from DUCL to.

zhiclo-, lose dao1 electricity.

The endon, from Cl to ClO3, loses 5 electrons, and loses a total of 1+3 accommodating 5=16 electrons; From Cl to Cl-, 1 electron is obtained, and 16 atoms are needed to obtain 16 electrons, so the ratio of the amount of reduced chlorine to the oxidized chlorine = 16: (1 + 3) = 4: 1

Therefore, d

4fei2+5cl2=2fecl3 +4i2+2fecl2

Because chlorine is introduced to react with iodine ions first, and after the iodine ion reaction, chlorine reacts with ferrous ions, so the equation is like this, 2 of the 4 Fe2+ ions are oxidized to +3 valence Fe3+, and 2 are still +2 valence.

1. Yes, because NaOH generates NaHCO3 after adding excess CO2, and then adding equal moles of NaOH can generate Na2CO3 and H2O

Device B should be saturated saturated saline, which is used to absorb HCl gas volatilized by hydrochloric acid.

(2) The reagent used in device A is limestone and hydrochloric acid solution, can soda ash be used instead of limestone?

The reason is that the reaction between soda ash and hydrochloric acid is too fast, which is not conducive to the absorption of CO2 (3) The reagent used in device B is saturated NaHCO3 solution, and the effect is to remove HCl gas

First of all, Na2O2 becomes NaOH and H2O2 when exposed to water, and then H2O2 will react with Fe2+, or decompose by itself, if Fe2+ is excessive and Na2O2 is added very slowly, there will be no oxygen production, and the generated Fe3+ is orange-yellow.

Due to the presence of strong bases, Fe3+ will become Fe(OH)3, colloidal or precipitate.

There is gas formation, which produces white precipitate, which quickly turns gray-green, and finally turns reddish-brown 2Na2O2+2H2O=4NaOH+O2

2NaOH+FeCl2=Fe(OH)2+2NaCl4Fe(OH)2+O2+2H2O=4Fe(OH)3 will definitely produce oxygen.

If you think that there is no oxygen, it can only be explained in this way, after the above three reactions are added to give 4Na2O2 + 6H2O + 4FeCl2 = 4Fe (OH) 3 + O2 + 8NaC, there is still oxygen in the end.

The light green solution fades in color, producing gas and generating a large number of white precipitates, which quickly turn gray-green and eventually reddish-brown.

2Na2O2+2H2O=4NaOH+O2 2NaOH+FeCl2=Fe(OH)2 +2NaCl4Fe(OH)2+O2+2H2O=4Fe(OH)3 against the view of the first floor, there will be no ...... of Fe3+

It reacts with water to form gas, and then precipitates.

2na2o2+2h2o=4naoh+o2,2naoh+fecl2=fe(oh)2+2nacl

Phenomenon: Violent reaction, producing colorless and odorless gas, and producing reddish-brown precipitate.

2na2o2+2h2o=4naoh+o2

3NaOH + FeCl3 = Fe(OH)3 (precipitate) + 3NaCl

Phenomenon: The light yellow solid is dissolved, bubbles are generated, and white precipitates are produced in the solution, and then the color quickly changes to gray-green, and finally to reddish-brown.

Hope it helps.

There is gas generation, 2Na2O2+2H2O=4NaOH+O2

A reddish-brown precipitate is generated, 3NaOH + FeCl3 = Fe(OH)3 + 3NaCl

Equation 2Na2O2+2H2O=4NaOH+O2

3naoh+fecl3=fe(oh)3↓+3nacl

Therefore, the phenomenon is exothermic, producing a large number of colorless and odorless bubbles, producing reddish-brown precipitates, and the yellow color of the solution fades away.