Knowing that the difference between the solution of the equation for x 2x 3 x k and the solution of

11 answers

Anonymous users2024-02-15

Let the solution of Equation 1 be a, then the solution of Equation 2 is (a+6) or (a-6)a, 2a+3=a+k, (a+6)-3=5kk=a+3, (a+6)-3=5(a+3), a=-3, k=0 two, 2a+3=a+k, (a-6)-3=5kk=a+3, (a-6)-3=5(a+3), a=-6, k=-3
Anonymous users2024-02-14

2x+3=x+k

x=k-3x-3=5k

x=5k+3

When the solution of Equation 1 is greater than the solution of Equation 2:

k-3-6=5k+3

4k=12k=-3

When the solution of Equation 1 is less than the solution of Equation 2:

5k+3-6=k-3

4k=0k=0

To sum up: k = 0 or -3
Anonymous users2024-02-13

Let x of 2x+3=x+k be x1, then x1=k-3 is simplified, and x2=5k+3 is the same

According to the title, x1-x2=6

i.e. (k-3)-(5k+3)=6

The solution yields k = -3

Verification) is brought into the original formula to obtain x1=-6

x2=-12

So k=-3 is true!
Anonymous users2024-02-12

2x+3=x+k

Move the item and merge it, and you have to pay tribute to filial piety.

x=k-3x-3=5k

Move the item, got. x=5k+3

The sum of the solution of 2x+3=x+k and the solution of high deficiency x-3=5k is 6; x=5k+3,x=k-3

Bright draft 5k+3+k-3=6

6k=6k=1
Anonymous users2024-02-11

According to the question, 2x+3=x+k, then x=, then x=5k+3So, k-3+5k+3=6, gets: k=1

Inspection: 2x+3=x+1 launches which x=-2

x-3=5 launch x=8

Correct lead code hail sun.
Anonymous users2024-02-10

2x+3=x+k

Positive slide high handicap x=k-3

x-3=5k

x=3+5k

The difference between the two rulers is 6

k-3-(3+5k)=6

4k=12k=-3
Anonymous users2024-02-09

Solve the equation 2x+3=x+k to get x=k-3

The solution x+3=5k has to be cautious and suspect that the modulus is slow and the wisdom x=5k-3, so k-3+5k-3=0

The solution is k=1
Anonymous users2024-02-08

3x+6=0

3x=-6x=-2

The first person to enter the Sui Annihilation in the guess mountain 3x+2k=2

6+2k=2

2k=8k=4
Anonymous users2024-02-07

4x+3k=2x+24x-2x=2-3k2x=2-3kx=1-3k+22x+k=5x+Because the equation for the vanity branch x 4x+3k=2x+2 and the equation difference sensitivity 2x+k=5x+ are the same, 1-3k 2=k 3-5 61+5 6=k 3+3k wither, then 211 6=11k 6k=1 is solved as x=1-3k 2=1-3 2=-1 2....
Anonymous users2024-02-06

2 kx+3 3=5 2x+3 6-1 2 4(kx+3) =5(2x+3)-3 4kx+12=10x+15-3 4kx+12=10x+12 4kx-10x=0 x(4k-10)=0 When 4k-10=0, the middle return x is not sold like a hungry number of oaks. Then: 4k-10=0 k=5 2
Anonymous users2024-02-05

Solving the first equation x=1 is substituted into solving the second equation k=1