The equation for x is known to be x m2 x 2m1 0

=(m+2) 2-4(2m-1)=m 2-4m+8=(m-2) 2+4 Evergrande is 0

Therefore there must be two unequal real roots.

By the Vedic theorem.

x1+x2=-(m+2)

And x1 and x2 are inverse numbers to each other, so x1+x2=0 so m+2=0

m=-2 becomes the original equation.

x^2-5=0

x= root number 5

=（m+2）²-4（2m-1）=m²-4m+8=（m-2）²+4＞0；Therefore there must be two unequal real roots.

If they are opposites, then x1+x2=-b 2a=-(m+2) 2=0;m=-2 can be obtained, and the original equation is x -5=0 to obtain x= root number 5

x²-(m+2)x+(2m-1)=0

-(m+2))²4(2m-1)

m²+4m+4-8m+4

m²-4m+4+4

m-2)²+4

The equation has two unequal real roots.

1²-(m+2)*1+(2m-1)=0

m-2=0m=2

x²-4x+3=0

x-1)(x-3)=0

x1=1x2=3

Another root of the equation: x=3

is a right-angled side, and the hypotenuse is long: (1 +3 )= 10The circumference of a right-angled triangle: 1+3+ 10=4+10

Discriminant formula by root: (m+2) -4 1 (2m-1)=m +4m+4-8m+4=(m-2) +4>0

So the equation has two unequal real roots.

The two are opposites, i.e. m+2=0 and m=-2

When m=1, the roots of two unequal positive integers are.

You are welcome to ask.

Since the equation has two unequal real roots, it requires δ 0, which is (m+2) -4m 2 0, which is simplified to (m-2) 0, so m 2.

It is known that the equation about x mx -(3m-1)x+2m-2=0 If the equation about x mx -(3m-1)x+2m-2=0 passes through the origin (0,0), when the line y=x+b and the function image have only two focal points, find the range of b mx - (3m-1)x+2m-2=0 through the origin (0,0) 2m-2=0 m=1 x -2x=0 and substitute y=x+b into x -2x=0 to get (x+b) -2(x+b)=0x +(2b-2)x+b -2b=0 has two intersections (2b-2) -4(b -2b)>0 4b -8b+4-4b +8b>04>0 b takes any real number.

Judgment.

When m is taken as a value, the equation has two real roots, which is given by [2(m+1)] 4m ; Get m -1 2

Take m=1, then the equation.

is x -4x+1=0

Solution: x=2 3

x²-2(m+1)m+m²=0

Equations do not have real roots.

So the discriminant formula is less than 0

4(m+1)²-4m²<0

8m+4<0

m<-1/2

Let m=4x-10x+16=0

x-2)(x-8)=0

x1=2,x2=8

x1-x2)²=(-6)²=36

1) The root number in the solution of the square orange is (m+2) -4(2m-1)=(m-2) +4>0, so the equation has two real roots of unequal bent cultures.

2) Bring 1 in and get m = 2

There is another root that is x=4

So the circumference of the triangle is 1+4 + root number 17 or 1+4 + root number 15

When we know what the value of the equation for x is (2m-1)x -mx+(m+2)=0(1)m, this equation is a one-dimensional equation, and the root of this equation is 2m-1=0;

m=1/2;

x/2+5/2=0;

x=5;2) When m is the value, this equation is a one-dimensional quadratic equation, and the quadratic coefficient, the primary term coefficient and the constant term of this equation are obtained.

It must be a process, in a hurry!!

2m-1≠0;

m≠1/2;

The quadratic coefficient of this equation is 2m-1, and the coefficient of the primary term is -m;

constant term m+2;

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(1) 2m-1=0 and m is not equal to 0

Get m=, m=5

2) 2m-1 is not equal to zero.

The coefficient of quadratic term is 2m-1

Primary term coefficient - m

The constant term m+1

(1)m= x=5

2) When m is not equal to, it is a quadratic equation with a quadratic term coefficient of 2m-1, a primary term coefficient of -m, and a constant term m+2

Solution: 1) The equation has two real roots, i.e. =(2m+1) -4m 0m -1 4

2) When m=2, the equation x -(2m+1)x+m =0 is reduced to the equation x -5x+4=0

x-5/2）²=9/4

x1=1，x2=7

Discriminant = (m+2) -4(2m-1).

m²+4m+4-8m+4

m²-4m+4+4

m-2)²+4≥4>0

So the equation has two unequal real roots.

The opposite number is x1+x2=0

Vedic theorem. x1+x2=-(m+2)=0

m=-2 is now x -5=0

x²=5x=-√5,x=√5