Knowing that the solution of the equation 5a x 3 about x is negative, find the range of values of a

Solve the equation first to get x=-3-5a

If x is negative, then x < 0, i.e. -(3+5a)<0

The result of the solution is a >

5a+x=-3

Move the term to get x=-3-5a

Because the solution is negative.

So -3-5a<0

According to the property of inequality 2, add 3 to both sides at the same time to obtain.

3-5a+3<0+3

then -5a<3

According to the property of inequality 2, both sides are multiplied by -1 at the same time.

5ax-(-1)>3x(-1)

then -5a<3

According to the property of inequality 2, both sides are multiplied by 1 5 at the same time.

5ax1/5>-3x1/5

then a>-3 5

The solution of the equation 5a+x=-3x=-5a-3 and the equation 5a+x=-3 is negative, so -5a-3<0a>-3 5

x-a=3 converts to: x=3+a

From the solution of the equation about x x-a=3 is negative, we get x 0, so bypass, 3+a 0 can get: a -3

Therefore, the value range of a is a -3

x=(2-4a) 3;

2-4a)/3＜0;

4a＞2;a＞1/2;

If you don't understand what you have to do in this question, you can chase Kai and ask,

Unblock the family chaos ax+3=x

i.e. (a-1) x = -3

The solution from the equation ax+3=x is the number of negative spike yards.

i.e. x 0 and car (a-1) x = -3 0

i.e. A-1 0

i.e. a 1

3x - 2a - 3) = 5x + 3a + 6)5x - 3x = -2a + 3 - 3a - 62x = -5a - 3

x = (-5a -3)/2

Because the solution is negative.

So (-5a -3) 2 < 0

So a > 3 5

3x - 2a - 3) = 5x + 3a + 6)5x - 3x = -2a + 3 - 3a - 62x = -5a - 3

x = (-5a -3)/2

Because the solution is negative.

So (-5a -3) 2 < 0

So a > 3 5

Hope it helps!

I hope you make progress in your studies!

First of all, there seems to be a problem with the problem, about the equation of y... Non-positive number", right, and then the second equation is followed by a half y, I will take it for the time being, and the answer is as follows:

From the first equation x=4a+1 0, then a -1 4;

From the second equation y=10a-18 0, then a 9 5;

To sum up, get -1 4 a 9 5.

To solve this problem, first express the unknown number x with the formula containing a, so that x < 0, that is, the solution of the equation is negative.

Then we can solve this inequality about a.

Here's how: x a=3

x=3+a makes x=3+a<0

a<-3

So: when a<-3, the solution of the equation x a=3 for x is negative.