How to do this question needs a detailed answer, please, it is urgently needed

First, this is simple, the sales volume is fixed to 4 possibilities, then the natural purchase is also 4 possibilities, then the actual possibility is 16 kinds.

Profit Incoming volume market 50

100 per field

Find 150 and 200 100

I can't expect to be on the picture.,I can only make this ** like this.

Second, the optimist should be able to sell 150 or 200, only between 150 and 200, which only consider 150 and 200 The expectation is the same as 300. The suggestion is to choose 150 for the plan, after all, 50 and 100 sales may not be negligible.

Pessimists should be able to sell 50 or 100, only between 150 and 200, both of which only consider 50 and 100 and expect the same 100. The suggestion is to choose 100, after all, 150 and 200 sales may not be negligible. In this way, the turnover will be higher.

Those who wait for the possibility are to choose according to the expected value, and it is obvious that they have chosen between 100 and 150.

3. Regret matrix, sorry I don't understand this concept very well. If it is understood to reduce the risk of loss, then 50 and 100 are obviously risk-free.

I think, it's better to call me a master, I'm not myself, I will.

The volume of water in the tank plus the volume of the cube is as high as the next high box, when the maximum volume of water in the tank is exceeded, the file will overflow.

The solution is as follows: Socks return to the rock.

Because the volume of the cube is cubic decimeters, and the bottom area of the container is 4 2 = 8 square decimeters, so the water surface will rise by decimeters, because the width of the town is 2 centimeters from the top, so the overflow is decimeter, and the volume of the overflow is cubic decimeters.

The water depth in the tank is decimeter.

The water will submerge the mould stones.

Stone volume = (cubic decimeter).

The original space in the cylinder = (cubic decimeter is orange slow).

So, the water will overflow. Wu state.

The surface area of the three silver pants spelling methods is: 108 square meters of square meters, 124 square decimeters, and 132 square decimeters.

Analysis: Since apples are twice as large as pears, we can ignore buying apples for now. This makes it easier to analyze how to buy.

Since the ** of raw pears is 3 yuan, it is an odd number. To ensure that the final result is an integer 10 (70 yuan), from the perspective of the conditions set by the question, only the kilogram of raw pears is an even number to be able to form a whole 10 with the orangeThat is to say, at least 2 kilograms of raw pears should be considered at first, so without considering the premise of buying apples, there are some combinations or ways to buy:

Let's take a look at whether there is a suitable combination of 2 kg of raw pears, because the total amount is 30 kg, because I have bought 2 kg of raw pears, it cost 6 yuan, and only 28 kg of quantity remains, assuming that all are oranges, the total price is only 28 * 2 = 56 yuan, and there are 70-(56 + 6) = 8 yuan that is not used. Since each kilogram of apples needs 2 yuan more than each kilogram of oranges, as long as 4 catties of oranges are replaced with apples, you can use the extra 8 yuan. That is to say, through the above analysis, we get the first buying method:

2 kg of raw pears + 24 kg of tangerines + 4 kg of tangerine.

According to this method of the stove species, you can get the second way to buy 4 kilograms of raw pears need 12 yuan, so you also need to buy 26 kilograms, if all are oranges, only 52 yuan, there is 6 yuan left, and the conditions can be met by replacing 3 kilograms of oranges for apples. From the above calculation, it can be seen that there are the following 4 ways to buy to meet the problem.

2 (kg raw pear) + 24 (kg tangerine) + 4 (kg apple).

4 (kg of raw pears) + 23 (kg of oranges) + 3 (kg of apples).

6 (kg of raw pear) + 22 (kg of orange) + 2 (thousand grams of apple).

8 (kg raw pear) + 21 (kg tangerine) + 1 (kg apple).

At this point, it is also necessary to discuss whether buying more than 5 kilograms of apples can meet the question. Let's say now we buy 5 kilograms of apples, spend 20 yuan, and have 50 yuan. Because 1 kilogram of raw pears and 1 kilogram of oranges is exactly 5 yuan, that is to say, a combination is just 5 yuan, 50 yuan is just 10 combinations, 10 combinations are only 20 kilograms, and the sum of the number of apples in front of 5 kilograms is only 25 kilograms, which cannot meet the 30 kilogram problem.

Therefore, apples can only be bought at most 4 kilograms, and buying more apples will not meet the conditions set by the question.

In addition, if on the basis of having purchased 5 kg of apples, if we buy 2 kg of raw pears first, we have spent 26 yuan, and we have already bought 7 kg, and there are 44 yuan left, and there is still 23 kg left, and these 23 kg can only be all oranges, which needs to be used for 46 yuan. And there is only 44 yuan in hand. Funding is already insufficient.

The simple and straightforward equation is still a column equation, which can ensure the completeness of the answer.

Solution: Let's buy apples, raw pears, and oranges are x, y, and z kilograms respectively. Qi Xiang.

From the equation of the question column: 4x+3y+2z=70 x+y+z=30

4- get: y+2z=50

y=50-2z

3- get: z-x=20

x=z-20

Because x,y,z>0 and are integers.

That is, Z-20 > Z Zi Meng 0 and 50-2 Z>0

20z=21,22,23,24

Therefore, there are four ways to buy.

1）x=1，y=8，z=21

2）x=2，y=6，z=22

3）x=3，y=4，z=23

4) x=4, y=2, first bridge z=24

The calculation process is suspicious of the chain Qinsun see the figure, and the serial number is the order of counting lead.