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+3 valence should be considered when coexisting with highly oxidizing substances or in the form of water and ions, such as iron and nitric acid, and potassium permanganate are +3 valence, and the passivation of iron and concentrated sulfuric acid is due to the existence of a dense oxide film on the surface of iron, preventing the reaction from proceeding further, and in fact iron sulfate is generated.
The water and ions of ferric iron are unstable and can be oxidized by oxygen in the air, and the most stable ferric ferric is (NH4)2Fe(SO4), the legendary molar salt.
Of course, if there is a reducing agent in the system, 2-valent iron can be stable, for example, there is elemental iron in the system.
Elemental iron is 0 valence, elemental iron and weak oxidants produce low-valent +2 iron, such as iron and hydrochloric acid, sulfur powder reaction to form +2 iron compounds, and strong oxidants to form **+3 iron, such as chlorine reaction to form ferric chloride;
From the point of view of the law of redox, +2 valence iron has reducibility, and in case of strong oxidation, it will be converted into +3 iron, such as divalent iron is easily oxidized to trivalent iron in the air. +3 ferric iron is oxidizing, and its oxidation is between bromine and iodine.
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If the title does not indicate that there is a surplus of oxygen, iron oxide is generally 2-valent.
In the case of substitution, it is 2-valent first, and sometimes when other substances are added, the valence of iron increases, such as Cl2 is introduced into the solution of FeCl2, and iron rises to 3-valent.
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Divalent iron is rarely found in nature, for example, FeSo4 is slowly converted to Fe2(SO4)3In the displacement reaction, usually the iron is +2. This question is a high temperature, so it needs special treatment.
Chemistry is not physical mathematics, and many reactions need to be treated differently, and cannot be taken for granted by experience or formulas.
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Wrong. Fe3O4 is formed at high temperatures, which is the exception of high temperatures.
You can ignore the answer upstairs, and a few levels really don't dare to compliment it (except for the pasting technique).
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The answer is A, the solid is all dissolved and pure, indicating that there is no Cu left in it, two situations: 1), Cu, Fe2O3, and the amount of the substance is exactly 1:1 to completely react (trick:
Cu reacts with Fe3+ to form Cu2+ and Fe2+, which is equivalent to taking out an O from Fe2O3 to Cu to form CuO, exactly 1:1).The mass of the mixture of the two is that the amount of the two substances is found to be the amount of the material that needs to be consumed by the simple sail H2SO4 is, and the ratio of the amount of the substances of V= 2) Cu and Fe2O3 is less than 1:
1, there is Fe3+ in the solution, take the limit, all are Fe2O3, the amount of Fe2O3 is the amount of the substance of Fe2O3, the amount of the substance of H2SO4 is , V = >, so the maximum value of V is.
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The mass ratio you are to the drops, the amount of the substance is 2 moles per liter.
Let the amount of copper in the mixture be x, and the amount of iron oxide is yfe2o3 + 3h2so4 = fe2(so4)3 + 3h2oy 3y y
Cu+Fe2(SO4)3=CuSO4+2FeSo4y y Because copper has a surplus, the system of equations:
64x+160y=
y=x-8/64
The solution is x=,y=, then mcu=, mfe2o3=16g, nh2so4=so (1)mcu:mfe2o3=9:10 (2)c(h2so4)=
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From the meaning of the title, the mass of iron oxide in the mixture can be known (, and then according to the conservation of the elements, all iron oxide is generated into iron sulfate, and the amount of the original sulfuric acid can be found
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There are 25g of copper oxide added: copper oxide reacts with dilute sulfuric acid to form copper sulfate, and copper precipitates after adding iron powder, which is 20g of solid obtained by filtration, where the copper comes from the previous copper oxide, and the mass fraction of copper in copper oxide is 80%, so the quality of copper oxide:
20÷80%=25g
Iron is added to copper sulfate to produce only ferrous sulfate:
cuso4+fe=feso4+cu
x 25g so 152 x = 64 25g solution to x= ferrous sulfate mass is.
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Copper, ferrous sulfate, because a certain amount of dilute sulfuric acid is added to the mixture of copper oxide and iron powder, the reaction will generate copper sulfate and ferrous sulfate, and the insoluble matter will be removed, but at the moment we do not know what the insoluble matter is, we need to see the following content, adding iron sheets to the filtrate has no reaction, indicating that there is definitely no copper sulfate in the solution, because if there is copper sulfate, the iron sheet will replace the copper in the copper sulfate, and red copper will appear on the iron sheet, in the metal activity order table, The metal in front can displace the metal in the back from its salt solution, and the iron in front of the copper can replace the copper from the copper sulfate, so the solute in the filtrate is ferrous sulfate.
By the way, I will tell you the order table of metal activity, which you will use in this kind of question in the future; Potassium, calcium, sodium, magnesium, aluminum, zinc, iron, tin, lead, [hydrogen] [here hydrogen is not a metal, it is a demarcation point, the metal before it can replace hydrogen from acid, and after it cannot], copper, mercury, silver, platinum, gold.
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fe+cuso4=feso4+cu
fe+h2so4=feso4+h2↑
Fe2O3+3H2SO4=FE2 (split number SO4) 3+3H2O2FE (brigade head or which OH) 3+3H2SO4=FE2(SO4)3+6H2O
That's all.
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Iron oxide and hydrochloric acid react to form iron chloride and water, iron and hydrochloric acid react to form ferrous chloride and water, copper oxide and hydrochloric acid react to form copper chloride and water, iron and copper chloride react to form ferrous chloride and copper, and iron and ferric chloride to form ferrous chloride. These are several reactions that can occur, so there may be iron in the filtered residue, and there will definitely be copper. It can be seen from the concentration of hydrogen ions in the filtrate that it is acidic, so there can be no iron in the residue, because the iron will continue to react with hydrochloric acid, then the solution will be neutral, which is obviously not true, so the iron is insufficient, and the residual solid must be only copper.
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Fe + Cu 2 + = Fe2+ + Cu Since there is H+ in the solution, there can be no Fe, iron oxide, copper oxide, because these three have to react with H+ Since there is a solid remainder, it can only be copper that does not react with H+.
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Because "insert another piece of iron into the filtrate to observe any changes", choose B
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A does not necessarily have a complete reaction to iron.
b correct c may have sulfuric acid residue and iron reaction.
dCopper has a greater relative atomic mass than iron.
Everything reacts at the same time.
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