If E pushes the ball down, then who will die

All dead,,See the following analysis Assuming that a lattice unit is 1,The circumference of the circle is,The circle rolls down due to inertia will not be affected by the notch to change the line,From the starting point of the circle,The distance from the right edge of D's head is (,Just when it touched his head, it just turned around,The gap is still facing up,So first d was headshot After a turn,The distance from the ball to the rightmost position of the strange board is,There is about 3 from the ball to the notch,So the ball will not be stuck there,Directly smashed to the Seesaw board, Although the mass of the ball on the right is light, there is a gravitational potential energy, according to the conservation of energy, it will be converted into an upward kinetic energy to the ball on the left, assuming the complete ball mass m, then the mass of the notch ball is m=8 9m, the gravitational potential energy of the ball is, 8 9m*g*3h=mgh, so the left ball will bounce up height h=24 9, which is approximately equal to, then the notch circle will naturally continue to fall, c will be over, then how high will the left ball be bounced, but not only, the notched ball continues to fall, and the energy is conserved, he will continue to convert to the ball on the left, so it should be 8 9m * g * 5h = mgh, h = 40 9 =, so the ball goes straight to a, a also died the same, because a is a slope in that position, so the ball has continued to roll and smash b as for e, he was sentenced to ** crime and immediately executed the death penalty.

Do you know what is called birth, old age, sickness and death?

The notched circle is called a circle, and the complete circle is called a circle, and each grid shown in the diagram is set to 1m.

First of all: the circumference of the circle = , now the radius of the circle is 1m, so the circumference of the circle is, the slope runway is: 5m, the starting point of the circle is about the slope, and the slope is about d away, so the total distance of the circle rolling down the slope is about 6m, and the gap is still facing up after reaching d, that is, d will definitely die.

Secondly, the slope is 135 degrees, and after reaching the slope, in addition to the head of d causing increased resistance, there is also a flat road of 1m, and the inertia will decrease; In addition, the weight of the circle on the seesaw is twice that of the circle, so when the circle rolls down and falls on the seesaw, according to Newton's second law, the circle cannot be prying.

At this point, C is in danger, B will not die, A will not die, but E is sentenced to death, life imprisonment or fixed-term imprisonment of not less than 10 years for intentional homicide in accordance with Article 232 of the Criminal Law of the People's Republic of China.

If the weight of the ball is light, both D and C will starve to death, and E will be beaten to death by AB.

If the weight of the ball is heavy, D will starve to death, A will be stoned to death, C will be beaten to death, and E will be beaten to death by B.

Hello, [Puzzle Question] If E pushes the ball down, then who will die?

It will pass over D's head, and the thorns on the plank will pass through C's body. One of the planks on the other side is concave, so the stone will be smashed in an arc to E If the force is small, it will hit B and the force will hit A.

All right. The weight of the two balls is not the same, that is to say, no one will die, if the momentum is too large, it may be B or A If you look closely, you will feel that the probability of A dying is greater, and the ball will roll down, take off along the protrusion of the right plank, rub the heavier ball, and finally fall to A.

1L is not the correct answer, the correct answer depends on the weight of the ball, D is sure to die. Others are not necessarily. See the answer page link for details.

In any case, E will be convicted of intentional injury or attempted homicide and sentenced to prison or the death penalty. If you really want to say it, you can use the hypothetical method.

It is divided into two divergences.

1.After ball 1 is pushed, it rolls back because of the gap, so E is crushed to death.

2.Ball 1 (notched) and ball 2 have the same mass and different densities or ball 1 and ball 2 have the same density and different masses.

In this case, ball 1 rolls down the slope, assuming that the gap is not in the place where D is, there are two possibilities. One is that D retracts his head and dodges ball 1, then ball 1 receives a brief impact and continues to roll. The other is that D does not retract his head, dies, and the ball continues to roll down with brief resistance.

1-1 ball 1 roll over, roll on the rocker. If the test is enough to warp the ball 2, then the nail underneath (let's say that) will hit C, and C will die. If ball 1 is unable to lift ball 2, then C has a false alarm.

Ball 1 stops rolling, and one possibility is over.

1-2 balls 2 are cocked and bounce towards E, if E dodges, Tuk is safe and sound. If it is not dodged, Ball 2 may roll down due to resistance and pass d, which is not an example here. Then hit Ball 1.

Then there are two more divergences, either ball 1 is hit and rolls to the other side, and the two sides are balanced. Either Ball 1 is hit to the other side, and Ball 2 is not fully on the end of the rocker, and it will be cocked due to the sudden change in gravity. Bounced to A's location, and A was stoned to death.

Ball 2 then hits the wall, is bounced back, hangs up the ramp and falls, killing B.

Well, that's probably it、、、

Hopefully, this assumption will help you......

It should be e, because this is a missing circle, but it will press on e's body.

Dd die, or neither.

One thing is for sure、

After pushing.

e will definitely be beaten to death.

You get a model and simulate it.

Don't you know?

If you're talking about the grid on the sphere and the slope, d is going to die.

According to the variable length of a grid quadrilateral is 1, the circumference of the sphere should be on the left and right, and the two sides of the slope triangle are , so the inclined plane is 5.

And according to the trajectory of the ball, it is impossible for D to rotate in the ball... The position on so d must die!

Let the length of each grid be 1, then the distance from D to the pillar is about 6 (proof is omitted), and the cross-sectional circumference of the pillar is about 2, which is almost, so the pillar is almost exactly a week when it rolls to the head of D, and the gap is still facing up, so D is dead.

Let's talk about C: When the stone pillar descends 3 blocks on the head of C, the potential energy is converted into kinetic energy, but because the direction of motion becomes transverse to the left when it reaches the position of D, only the gravity experienced in the longitudinal direction is downward, but because it is missing a piece, it is lighter than the stone pillar on the other side of the lever, so it will not press C.

After: The pillar flies in a parabola, may hit a small bump on the lever, and eventually crash into another pillar, and if the pillar doesn't break, both A and B will be safe.

Instead of starting from the lower midpoint of the notched ball, E pushed it a block long first.

It's d, I've seen people make models.

will die, the ball missing 1 4 rolls down from the high ground, ignoring d for the time being, and the gravitational potential energy obtained is enough to bounce the complete sphere, at this time c hangs, the bounced ball hits a, due to the slope of the height of a, it will fall back on the seesaw, and the complete sphere mass plus the gravitational potential energy will bounce the notched sphere up, knocking it to death, the sphere will roll down, it will bounce up the complete sphere again, and the force is weakened in the cycle, b will also be crushed by the complete sphere, d will be crushed to death.

First of all, let's complain about D's height. Second, all assumptions: each tick is 1 meter apart.

There is no energy loss due to friction and air resistance. ABCD does not move. The two cobblestones are of the same material.

The lever will not bend, and the right side of the lever will not die if it does not touch the ground. The ground is horizontal, and the angle at which the lever is formed by the small slope to the ground is the same as the angle at which the lever is formed by the ground (tan -1 (1 3)=. The lever does not absorb the energy of the stone ball, etc.

Theoretical Answer: D: The distance from which the stone ball rolls to D is 6.

The circumference of the stone ball. That is to say, when the stone ball reached D, it rolled a little more than a circle, and it was far less than the circle and a half that D needed to survive. d was headshot.

C: The stone ball moves horizontally from D to the right end of the lever. The velocity is parallel to the ground, and the downward velocity part when it reaches the right end of the lever is 0m s.

The rolling stone ball is lighter than the stationary stone ball, the distance from the fulcrum is equal, the moment is not enough to press the lever, and c survives. a: Calculated by converting all potential energy into kinetic energy:

mgh=。v=。The upward part is.

The flight time is t=(v-u) a=horizontal velocity, the part is the flight distance, s=ut+ t}=, and the distance between the rolling stone ball and b is, and a, so the stone ball cannot fly at b a. A, B survived.

Actual answer: Don't be stupid, E can't push the stone ball with Ben.

If E pushes the ball down, who will die?

It will pass over D's head, and the thorns on the plank will pass through C's body. One of the planks on the other side is concave, so the stone will be smashed in an arc to E If the force is small, it will hit B and the force will hit A. All right.

The weight of the two balls is not the same, which means that no one will die, if the momentum is too large, it may be B or A If you look closely, you will feel that A has a better chance of dying.

The ball will roll down, take off along the protrusion of the plank on the right, graze the heavier ball, and eventually land on A.