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Anonymous users2024-02-15org 0000h
main:mov dptr,#0ff20hmov a,#03h
movx @dptr,a
mov 2ah,#1fh
mov p1,#0ch
mov r7,#19h
prg1: lcall delay1
djnz r7,prg1
mov p1,#0ah
mov r7,#05h
prg2: lcall delay1
djnz r7, prg2
mov p1,#21h
mov 2ah,#1fh
mov r7, #19h
pgr3: lcall delay1
djnz r7,pgr3
mov p1,#11h
mov r7,#05h
pgr4: lcall delay1
djnz r7, pgr4
ajmp main
delay1:dec 2ah
mov a,2ah
mov b,#0ah
div ab
mov dptr,#tab
movc a,@a+dptr
mov r2,a
mov a, b
mov dptr ,#tab
movc a,@a+dptr
mov r1,a
mov r6,#64h
loop: mov a,r2
mov r4,#02h
lcall display
mov a,r1
mov r4,#01h
lcall display
djnz r6,loop
rettab: db 0c0h,0f9h,0a4h,0b0h,99hdb 92h,82h,0f8h,80h,90hdisplay:mov r0,#0d0h
mov r5,a
display1:mov a,r5
mov dptr,#0ff22h
movx @dptr,a
mov dptr,#0ff21h
mov a,r4
movx @dptr,a
djnz r0,display1
retend
Similar to your title, you can refer to it if you look at it.
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Anonymous users2024-02-14It's just 20 points too little, and other people are going to die.
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Anonymous users2024-02-13This is the problem of the timer, not the problem of the counter, and the biggest gain is to practice the timing control, because the core of the microcontroller is to output the control signal, and the core of the control signal is to output the control signal according to the established timing.
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Anonymous users2024-02-12It's the problem with counters. Countdown, how many seconds this light is on, how many seconds the next light is on. Or make a variable, the initial value can be set by yourself.
Hello: I wrote the program:
#include >>>More
Hardware--- 8051 microcontroller.
The workload is too much, and my graduation project is to use a single-chip microcomputer to control lighting. >>>More
Isn't this thing just a digital tube displaying 16 digits? Prompt you 16 times to get there, let go after you think to press the stop button. If so, the procedure is available for reference: >>>More
;When debugging, you need to change the Chinese punctuation marks to English punctuation marks, otherwise the out of memory prompt message will appear. >>>More