Looking at the numbers in the table below, what rows and columns does the number 2012 appear in?

is line 252, third column, with a minus sign. 2012÷8=251……4. Since the first column is the same as the previous row, it is located in the third column.

Solution: 1. First of all, don't look at the symbol in front of the number: the first line can be .

Then move the 8 down and put it in column 5 of the second row. Then put 8+2=10 in the fourth column of the second row, and 10+2=12 in the third column of the second row, so that the second row can be in order.

2. Then move 16 down and put it in the first column of the third row, and then add 2 to each column in turn. You can get a third act. In the same way, the fourth line is the same as the second line.

3. Finally, it can be seen that the difference between each line is 8, so there is 2012 (divided) 8=251 and 4. So 2012 in the third column of line 252. Judging symbols can see that the odd number column is a negative sign, and the even number column is a positive sign.

is line 252, third column, with a minus sign.

Should be. Line 503, column 5, preceded by a "-" sign.

Summary. 12, 67, 1516, a combination of each layer, the difference between the two numbers is eight.

In the following number table + count from left to right, the 3rd number in row 10 is 53, and in what row is 2022?

Hello dear, it is a pleasure to tutor your studies. You can provide your eggplant chart in detail, and then judge it according to the actual situation, and find the 2022 bit.

Now the condition of the problem is to count from left to right, the tenth row, the third number is 53, this is a regular problem, I hope to wait patiently for a while, this needs to be calculated.

That 2022 is in the first few rows.

The first 53 will already be counted.

Thanks, sorry for the trouble.

The third number in the tenth row, from left to right, is 48

Yes 53 Terms, odd numbers, even numbers are different permutations, I mainly want to know how many rows 2022 is in.

53 is not right.

Yes 48, you can consider holding down one side to analyze, I am analyzing according to the left.

12, 67, 1516, a combination of each layer, the difference between the two numbers is eight.

I said the opposite. I'm from the left to the right.

It should be from left to right.

That should be analyzed from the left.

How to calculate that in 2022.

In line 64. The 59th number.

1006 4=251 surplus 2

It should be in line 252 and the even number of lines should be reversed, so it should be in the fourth column.

2012 is the 1006th number to appear, and even numbers are negative, so it is preceded by a negative sign.

ps:It's done according to what you gave**,It seems that the ** you gave** is a little strange.,How to arrange 4 numbers in 5 columns,

Line 503, column 5, preceded by a "-" sign.

Solution: The first number in row n in this table is 2 (n-1) There are 2n-1 numbers in row n, which in turn form a series of equal differences with a tolerance of 1

1) From the general term formula of the equal difference series, the last number in the nth row of this table is 2 (n-1) + (2 (1-1)-1) 1=2 n-1;

2) According to the summing formula of the equal difference series, the sum of the numbers in row n of this table is [2 (n-1)+(2 n-1)] 2 (n-1) 2=2 (2n-2)+2 (2n-3)-2(n-2), 3) let 2012 be in the nth row of this number table

Z2 (n-1) 2012 2 n-1

n=11

Therefore, 2012 is in line 11 of this table

Let 2012 be the m number in row 11 of the table, and the first number in line 11 is 2 10, so 2012 is the 989th number in line 11

75 in 45 rows.

It can be observed that the last number of the nth row of the cavity orange is the square dust circle of n.

Because 2011 is between 44 squared and 45 squared.

So 2011 is located on line 45.

Because the last digit of line 44 is 44 squared, 1936, 2011 is at number 2011-1936=75.

As can be seen from the figure, a(1,1)=1, a(2,2)=3, a(3,3)=7, a(4,4)=13, a(5,5)=21

a(n,n)=n*(n-1)+1, let n*(n-1)+1 =2011, find n is approximately equal to 45, and calculate a(45,45)=45*44+1=1981

2011-1981=30,45-30=15,a(45,15)=2011

According to the inscription, the first number in the kth row of the matrix is k, and there are 2k-1 numbers in this row, forming an equal difference series with a tolerance of 1

The last item in line k is ak

k+（2k-2）×1=3k-2

When 2012 first appears, k is the smallest integer satisfying the inequality 2012 3k-2, which is solved to get k 2014

The smallest integer solution for k is 672

A6722014, line 672, column 1343.

2012 is the third-to-last item from line 672, which is column 1341.

So the answer is: 672 1341