How does android determine if the value entered in EditText is a number or a Chinese character?

XML, but you can do it in **.

To give you a way to judge the kanji, private boolean ischinese(char c) {.}

ub = ;

if (ub ==

ub ==ub ==

ub ==ub ==

ub == {

return true;

return false;

The number is judged according to the range of Unicode!

You can judge the characters directly with the ASCII code.

Get the value of the edittext input and match it with a regular expression!

First: In order to get all the data in EditText before getting the input number, check the API, there are the following methods.

Returns the parameter type, method name, and the definition of the method.

editable gettext() return the text the textview is displaying.

This method can return the text that the textview is displaying, and the type of the returned value is editable, which seems unfamiliar.

Let's take a look at the editable API, which is as follows:

Then there is a method in the charsequence.

abstract string tostring() returns a string with the same characters in the same order as in this sequence.

Then you can get a string object, and then the operation of string is not much more convenient, by taking out each character to determine whether it is a number, ** as follows:

string str=et_;

if(str != null &&"".equals(str))}

In Android, edittext can be set to android:digits, which means that only specified content can be entered.

It can also be handled in the following ways:

Add android:digith= to the xml"0123456789"Only 0-9 can be entered

in xml android:maxlength="10"The maximum number of characters is 10 characters.

Judge with regular expressions"^[0-9a-za-z]$"Can.

Get the editview string, if it doesn't work, substring, and then assign it back.

XML, but you can do it in **.

To give you a way to judge the kanji, private boolean ischinese(char c) {.}

return false;

The number is judged according to the range of Unicode!

if(current string of numbers)!=、==、>、=、<、= ;

;Convert strings to numbers.

Get the string inside.