Primary 5 math problems, no equations to solve travel problems

Updated on educate 2024-02-12
6 answers
  1. Anonymous users2024-02-06

    The first time they met, the two sides walked a distance between A and B, and at this time they were 50 meters away from A, indicating that Jiajia walked 50 meters.

    The second time they met, the two sides walked 2 more distances between A and B (counting the first time, a total of 3). Now let's turn to the question of timing. If you say that two people walk the distance between two A and B, it is not twice the time taken to walk the distance between one A and B, because their speed is the same.

    Then during this time, Jiajia should have traveled twice as far as the last time. It should be 50*2=100 meters.

    Look at the circuit diagram you drew again. In fact, this 100 meters is composed of 2 sections. One is the distance between A and B minus 50 meters, and the other is the section where the meeting point is 19 meters away from B.

    So now subtract 19 meters to get the first meeting point, the distance to place B. i.e. 100-19 = 81 meters.

    Coupled with the original 50 meters, it will be 50 + 81 = 131 meters apart from each other

  2. Anonymous users2024-02-05

    When they met for the first time, the two sides walked a distance between A and B, and at this time, Jiajia walked 50 meters.

    When they met in the second time, the two sides walked two more distances between A and B, and at this time, Jiajia should have walked another 100 meters.

    From 50 meters away from place A to place B back, and then walk to 19 meters away from place B, a total of 100 meters, then from 50 meters away from place A to place B.

    100-19 = 81 meters.

    A to B total.

    50 + 81 = 131 meters.

    It would be very concise if you could draw a line segment diagram. It is more cumbersome to say in words.

  3. Anonymous users2024-02-04

    430 4-(90 2)=40 (kmh). B speed is 40 km/h.

    2: 2 encounters and a total of 2 full journeys of Yuanqing, with a distance difference of 1 km. The first encounter is a total of 1 full course. The distance difference is 1 2 = km. Speed difference = 1 km.

    Speed sum = 8 km/h when the small orange wheel is held.

    Xiao Ming = (16 + 1) 2 = kilometers Hours... Tong blind. Velocity.

  4. Anonymous users2024-02-03

    Suppose the speed of the second truck is x kilometers per hour.

    180÷30-2=180÷x

    6-2=180÷x

    180÷x=4

    x=180÷4

    x = 45 km.

  5. Anonymous users2024-02-02

    When two numbers are subtracted, the number that was not copied incorrectly is subtracted, and the decimal point is shifted to the left by one place, that is, it is reduced by ten times, and after subtraction, it is nine times the number that was correct before the supererror. Just divide it by nine more:

    So the other number is.

    That is, the two numbers are the sum respectively.

  6. Anonymous users2024-02-01

    1.Solution:

    Set: The average weight of a basket of bananas is x kg.

    Then there is: 6x+6 15=210

    Solution: x=20

    A: The average weight of a basket of bananas is 20 kilograms.

    2.Solution: Set: The price of each pencil is X yuan.

    Then there is: x+2x=

    Solution: x = A: The price of each pencil is yuan.

    3.Solution: 1) 4x+

    It can be reduced to: solution: x = 196/35

    2) It can be turned into:

    Solution: x = 16/5

    3)2x+3x+5x=32

    Simplified: 10x=32

    Solution: x=4)6x-3x-x=

    Simplified to: 2x=

    Solution: x=4Solution: Set up x trees in the fifth grade.

    Then there is: x+75=

    Solution: x=150

    Tree planting in the sixth grade: 150 + 75 = 225 (trees).

    A: 150 trees were planted in the fifth grade and 225 trees were planted in the sixth grade.

    5.Solution: Let's say there are x cards.

    Then there is: x+2x+3x=96

    Solution: x=16

    Bright and bright cards: 2 16 = 32 (cards).

    Strong and strong cards: 3 16 = 48 (cards).

    Answer: There are 32 cards, 32 cards for Liangliang, and 48 cards for Qiangqiang.

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