Ask a few simple math questions for the first year of high school, and by the way, find someone who

1.Solution: According to the meaning of the question, m=log2(36) n=log3(36), so (1 m) + (1 n).

1 log2(36))+1 log3(36)) is used to convert the bottom formula, then = (log3(2) log3(36)) + log3(3) log3(36))).

log3(2*3)/2log3(6)

2.Solution: Original formula = LG4 + LG5 * LG (5 * 4) + (LG5) squared.

lg5(lg(5*4)+lg5)+lg4

1) Use the formula 1 m+1 n=1 log36,2 +1 log36,3=(log2,6+log3,6) log36,m=1 2

2) lg4+lg5lg20+(lg5)^2 = 2lg2+lg5(lg5*4)+(lg5)^2

2lg2+2(lg5)^2+2lg2*lg52lg2+(lg5)^2+(1-lg2)^2+2lg2*lg5(lg5)^2+(lg2)^2+1+2lg2*lg5(lg5+lg2)^2+1

Math words are too hard to type, it's really troublesome, I hope it helps!

Summary. Hello.

There are some high school math questions I want to ask, is there a teacher who is better at math? Thank you.

Hello. What are the problems?

You can take a picture of your question and send it to me and I'll show it to you.

I don't understand what the score of 8:8 means, isn't it 11 points per game, so why is 2*8 16 more than 11 points, I don't understand why there is such a score.

Wait a minute, I'll look at the question first.

That is true. His 11-point scale does not mean that there are 11 points in total, but that which side gets 11 points first determines which side wins.

At that time, I watched the shirt when I was either celebrating or also around me, and then I checked, and their so-called 11 points is whoever takes the first 11 points to win the game. That's 8:8 means they played a total of 16 rounds, and then one person won eight games each, scoring eight points each.

Ask for a custom message] Hello.

1) Let a(x1,y1), b(x2,y2), and the left focal point (-c, 0), then the straight line l:y=x+c

From the meaning of the title. af2|+|bf2|=2|ab|，|af1|+|af2|=2a，①

bf1|+|bf2|=2a，②

Gotta |af1|+|bf1|）+af2|+|bf2|) = 4a, i.e. |ab|+2|ab|=4a，a=1，|ab|=4a 3 =4 3 ．

2) Pa=PB,(x1+1)2+y12=(x2+1)2+yy22, (x1+1)2-(x2+1)2+y12-y22=0(x1-x2)(x1+x2+2)+(y1-y2)(y1+y2)=0 Substituting y=x+c, get.

x1-x2）（x1+x2+2）+[x1+c）-（x2+c）][x1+c）+（x2+c）]=0，x1-x2）（x1+x2+2）+（x1-x2）（x1+x2+2c）=0

x1-x2)[2(x1+x2)+2+2c]=0 x1≠x2, i.e. x1-x2≠0

2（x1+x2）+2+2c=0

x1+x2+1+c=0

That is, (-2a2c 2a2-c2 )+1+c=0, e=c a = 2 2, that is, a2=2c2 is substituted into the above formula, and it is obtained.

c=3∴a2=18，b2=9

The elliptic equation is x2 18 +y2 9 = 1

It should be like this:

1)|af2|，|ab|，|bf2|into a series of equal differences, so 2|ab|=|af2|+|bf2|, so 3|ab|=|af2|+|bf2|+|ab|=|af2|+|bf2|+|af1|+|bf1|=4a=4, so |ab|=4/3

(1)|af2|，|ab|，|bf2|into a series of equal differences, so 2|ab|=|af2|+|bf2|, so 3|ab|=|af2|+|bf2|+|ab|=|af2|+|bf2|+|af1|+|bf1|=4a=4, so |ab|=4/3

Take a nap in the space to learn about the Smurfs handed over.

2.Is there a mistake in writing the root number 3 a a? If that's the case, non-p is a complement of root number 3 a.

3.{1,a+b,a}={0,b a,b}, there is a 0 on the right, look at the left, only a+b=0,b=1,a=-1,b-a=2

There's something missing. x 2-x-6>0, 5.?? Topic.

mx 2-6mx+m+8>=0 constant establishment.

m>0,△<0

The solution is 0m=0 constant.

m<0 is not true. So 0 "m<1

1. If the total cost of purchasing 8000 components is y, then.

y＝2×。x＝8000／n，y＝500n＋8000／n＝500（16／n＋n）≥500×2√（16n·n）＝4000

Therefore, when n 4, the total cost is the least, that is, it is advisable to buy goods four times a year.

2. When a >1, loga[(1 a-2)x+1]>0, then (1 a-2)x+1>1, then the coefficient of the primary function (1 a-2)x+1 is negative, and it is a subtraction function in the definition domain, and its minimum value is taken when x=2.

So only 2(1 a-2)+1>1, so 00, then 0<(1 a-2)x+1<1, and the one-time function (1 a-2)x+1 is monotonic in the defined domain, and its maximum value must be taken at the endpoint.

So only 0<(1 a-2)+1<1, and 0<2(1 a-2)+1<1, the solution: 1 2

1.f(-x)-g(-x)=x +x and because f(-x)=-f(x) g(-x)=g(x) so f(x)+g(x)=-x -x is added to the original formula to give 2f(x)=-2x, so f(x)=x

2.Let x=y=0 so f(0)=2f(0) so f(0)=0

Let y=-x get 0=f(0)=f(x)+f(-x) get f(x)=-f(-x) so it's an odd function.

That is, Evergrande is equal to 0 under the root number

If m=0, then the root number = 8, which is true.

m is not equal to 0 and is a quadratic function.

If the quadratic function is equal to 0, the opening is upward.

So a>0

and the minimum value is greater than or equal to 0

So the intersection point with the x-axis is 0 or 1.

So the discriminant formula is less than or equal to 0

So 36m -4m -32m <=0

m(m-1)<=0

So 0 so 0<=m<=1