I m going to hire a high math teacher, and I m going to ask for a high school math teacher

I can teach you that I can't find your space.

Summary. Please describe your problem more specifically, you can use ** and other forms, and talk to the teacher in detail, so that the teacher can better help you.

Please describe your problem more specifically, you can use ** and other forms, and talk to the teacher in detail, so that the teacher can better help you.

Hello, dear, you can send out the question <>

Dear, you can send out the question when you have time, so that the teacher can answer it.

First, the 4th power of 2 is equal to the 2nd power of 4.

Then f(x)=2 x -x

The derivative yields f'(x)=ln2 *2 x -2x The source is hail f'(4) = 16 ln2 -8ln2 is approximately equal to, i.e., f'(4) >0

and the second derivative f''x)=(ln2)² 2^x -2，f''(4) >02 x increases monotonically, so that the second derivative is everstable at 0

That is, after x>4, the derivative of a bend segment increases monotonically.

Then after hail sail x>4, the first derivative is everover to 0, and the function f(x) increases monotonically.

So when we get x>4, f(x) > 0

Proved 2 x >x

When x belongs to [1,2], (x) needs to be solved in segments, the first being (0,1) and the second being (1,x), i.e.

x)＝∫dt+∫2dt

1+2x-1

2x。

Segmentation function segmentation processing.

For reference, please smile.

Note x [1,2], so it must be split into two segments and added.

First of all, y=ln x (x>0) is an increasing curve, i.e., the greater the x, the greater the overall value.

Because ln2 is smaller than the root number 2 and less than 2, you can immediately come out with this property of incrementing, and the size of the following three is less than the sign at a time.

Then it should also be noted that ln2 is less than 1, so ln(ln2) is less than 0, and then ln, the root number 2 can be simplified, it is equal to one-half ln2, and then the square of ln2 can be seen as ln2 multiplied by ln2, so just compare the size of ln2 with one-half, and then you can look at the half as ln root number under e, so ln2 is compared with ln root number e, obviously the root number e is less than 2, so the square of ln2 is larger than the logarithm of log with e as the base root number and 2 But ln2 is less than 1, so after the square is definitely smaller than the original, so the end result is.

in（in2）< log takes e as the base of the logarithm of the root number 2< (in2) squares the < in2, you can write it down on paper step by step according to what I said above.

Opposing events.

Successive cases of the same color, divided into two categories, the probability of which is different.

Two types of probability and 8 20=

So the answer is.

The probability of being both red is 2 5 times 1 4 = 1 10

The probability of being black is 3 5 times 2 4 = 3 10

The probability of both being red plus the probability of being both black is 2 5

Solution: According to the characteristics of the odd function, f(x)=-f(-x), then f(-x)=-f(x).

4x+1 so when x<0 there is.

f(x)=-4(-x)+1

4x+1 so f(x)=

- The dividing line is answered so well, of course, it's a cute girl paper.

Solution: According to the characteristics of the odd function, there is f(x)=-f(-x), so f(-x)=-f(x)-4x+1

f(x)=-4(-x)+1=4x+1

What do you want to ask, is it math or what, and then I just, I don't know a little bit about math, so I don't know a little bit about math, and then I'm trying to study it.

Choose B, find the eigenroot according to the formula, and set it.