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Anonymous users2024-02-05f(x)=x+a x g(x)=x-lnx xe[1,e] f(x1)>=g(x2) That is, f(x) must be greater than or equal to the maximum value of g(x) is the minimum value of f(x) and greater than or equal to the maximum value of g(x).
xe[1,e], g'(x)=1-1 x >=0 1>=1 x x>=1 is incremental.
Therefore, xe[1,e] is increased, and the maximum value is g(e)=e-lne=e-1
So: f(x)>=e-1 xe[1,e].
f'(x)=1-a x 2>0 a x 2<1 x 2>a, x>root a or x<-root a is incremental, and x 2 root a is incremental. xe[0, root number a] is minus.
When x = root number a, take the minimum value.
If: root number ae[1,e]ae[1,root e], the minimum value is f(root number a) = root number a + root number a = 2 root number a> = e-1
a>=1 (e-1) 2 is synthesized to a[1, root number e].
When the root number a>e, it is subtracted, and the minimum value is f(e)=e+a e>e-1 a e>-1 -e-e so a>e also holds.
When the root number a<1, it is incremental, and the minimum value is f(1)=1+a 1>e-1 a>e-2 i.e.e.: ae[e-2,1].
In summary: a>=e-1 a>=e ae[e-2,1].
That is: a>=e-1 or e-2<=a<=1
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Anonymous users2024-02-04It should be the wrong question, but the one on the Internet is right, because if you follow the original topic, you have to do all kinds of discussions on A, which is very complicated, and the fill-in-the-blank question will not be purple
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Anonymous users2024-02-03I'll give you the answer first, and if you want the process, find me alone.
The radius r 2 = (5 + 5 (1 2)) 2 and the surface area is 4 r 2 = 2(5 + 5 (1 2))*
Note: Pi 5 (1 2) means that the object is trapped in the root of the Jane Huai No. 5).
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Anonymous users2024-02-02Solution: Let point C be polluted by source A as Ka x 2, and point C as be polluted by source B as Kb (18-x) 2, where k is the proportionality coefficient and k 0
Thus the degree of contamination at point C y=ka x 2 +kb (18-x) 2
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Anonymous users2024-02-011. p = (c31 times c21 times c11) c63 =3 102, the possible values of x are
When x = 2, p1 = 1 c63 = 1 20
When x=3, p2=1-p1 =19 20 (1-probability when you don't get 3) can draw your own distribution column.
ex=2x1 20+3x19 20=59 203, to make y 6, then there must be 3, so (c31 times c21 times c11 + c32 times c31 + c33) c63 = 4 5
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Anonymous users2024-01-311. p=3 10 take one each.
2. The possible value of x is
When x = 2, p1 = 1 c63 = 1 20
When x=3, p2=1-p1 =19 20 (1-probability when you don't get 3) can draw your own distribution column.
ex=2x1 20+3x19 20=59 203, to make y 6, then there must be 3, so (c31 times c21 times c11 + c32 times c31 + c33 + c31 times c22) c63 = 19 20
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Anonymous users2024-01-30The radius of the ball is 3
The radius of the regular tetrahedral outer catch is 3 4 of the height of the regular tetrahedron (this is basic common sense), so the height of the regular tetrahedron is 4
The side length of the regular tetrahedron is 24 under the root number
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Anonymous users2024-01-29You .........Are you sure you are looking for the volume of the sphere?
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Anonymous users2024-01-28The volume of the ball??
The formula for the area of the ball is s=4 (r 2).
s=36π,r=3
v=(4/3)π(r^3)
The volume should be 36
Your answer to that isn't the volume of the ball.
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Anonymous users2024-01-27If you approve of me, please click "For satisfactory answer", thank you!
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Anonymous users2024-01-26Less than 50,000, so the 10,000 digits can only be 1-4, and there are no repeating digits, and even numbers can only be 2 or 4
The 10,000 digits are 1 or 3, the single digit can be 2 or 4, c<2, 1> c<2, 1> p<3, 3>=24
The 10,000 digits are 2 or 4, and the single digit can only be 4 or 2, c<2,1> c<1,1> p<3,3>=12
So there is a total of 24 + 12 = 36
This can be solved using inequalities.
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I also thought about this problem when I was in high school, first of all, the front multiple-choice questions should be done quickly, the method should be used flexibly, and it is not necessary to do the whole process, you can use a special method to bring in the method and a series of quick practices, and then fill in the blanks as much as possible, basically send points in front, there are two difficult points in the back, the first 2 questions of the big topic are very basic to ensure that they are all right, and the big questions behind should have the concept of step-by-step scoring, don't look at the type of question that you have not seen it and feel that it is difficult to have no confidence, the first few steps can still be scored, The next few steps are written to where it counts, and this is a score. In general, we should pay attention to the foundation, ensure that the basic score is not lost, the time should be allocated well, if the level of multiple-choice questions is good in 30 minutes, generally, about 40, fill-in-the-blank questions should have 30 minutes to do, and then there is about an hour, the first 2 big questions are 15 minutes, and the rest of the time try to do the rest of the questions! >>>More
3 people spent a total of 9*3 27 yuan; The 2 yuan taken by the waiter is actually 3*9=27 yuan; The boss received 25 yuan, and the waiter took 2 yuan and earned 25 yuan + 2 yuan 27 yuan, so for the customer, they paid 9 yuan for the accommodation, so 3 x 9 yuan = 27 yuan + returned) 3 yuan = 30 yuan; For the boss (paid by the customer) 30 yuan - the waiter hid it) 2 yuan - (returned by the waiter) 3 yuan = (actual income) 25 yuan; For the waiter (paid by the customer) 30 yuan - (returned to the customer) 3 yuan - (handed over to the boss) 25 yuan = (the waiter hid) 2 yuan expenditure There is no problem with income.
25-2)/(25+1)=(60-2)(t+1)t=
95-5) (100-0) = (32-5) (t-0) t = 30 degrees Celsius. >>>More