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Anonymous users2024-02-06Consider putting these 100 numbers in an array first, taking a random position one at a time (1-100 for the first time, 1-99 for the second time,..).Swapping the number of that position with the number of the last position will do the trick.
using system;
using ;
using ;
static void main(string args)int arr=new int[101];
int i;
Initialize the array.
for(i=1;i<=100;i++)
arr[i] = i;
Random numbers. random r = new random();
for (int j = 100; j >= 1; j--)int address = ,j);
int tmp = arr[address];
arr[address] = arr[j];
arr[j] = tmp;
Output. foreach (int k in arr)" ");
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Anonymous users2024-02-05Using the hash code of the guid as the seed value, there will be no duplication, ** as follows::
public class randomhelper{///
A random code (number) with a specified number of digits is generated
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Anonymous users2024-02-04It's more general!
Never repeat a 10-digit random number.
Including numbers and letters?
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Anonymous users2024-02-03Idea: You can use the method of adding time to random numbers, so that it will never be repeated.
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Anonymous users2024-02-02To achieve this, you have to understand firstrandom()
Method. In c there is a parameterless method and a parametric method:
public random();The program takes the number of milliseconds of the current date as the seed, so the seed will be different each time.
public random(int seed);A seed of a random number, and a seed corresponds to a fixed random number in a range.
What is the relationship between that kind of sub and random number?
The random function produces a pseudo-random number, which is actually a sequence generator, with a fixed algorithm, only when the seeds are different, the sequence is different, if the seed is fixed in the program, the generated random number will always be fixed.
random ro = new random(5);
int a;
a = , 20);
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