c Where is the error 20

Updated on technology 2024-02-09
5 answers
  1. Anonymous users2024-02-05

    Note that this is C, not C++

    scanf("%d",&a[i]);i is not initialized. The default value is 0??It's been a long time since I've done C.

    for(i=0;i<6;i++)

    for(i=6;i>0;i--) I use i for both layers of cycles, and I don't know what I want to do.

  2. Anonymous users2024-02-04

    #include""

    void main()

    int a[6]=;

    int i,temp;

    printf("Original array:");

    printf("Insertion and arrangement of data");

    printf("Enter an integer:");

    scanf("%d",&a[6-1]);

    for(i=0;i<5;i++)

    for(int j=0;j<5-i;j++)if(a[j]>a[j+1])

    temp=a[j];

    a[j]=a[j+1];

    a[j+1]=temp;

    printf("The array elements are arranged as:");

    for(i=0;i<6;i++)

    printf("%6d",a[i]);

    printf("");

  3. Anonymous users2024-02-03

    This program will report an error because it is not allowed to define a variable with the same name as an externally defined constant in the main function. You can change the variable name inside main to something else, or delete it.

    Yes, inside main there is a new pi variable that has the same name as the global constant pi, but it is not a constant, and it can be modified, which will cause the program to be incorrect.

    The solution is to use a different name for the pi variable in main to avoid name conflicts, e.g

    #include

    const double global_pi=;

    int main(){

    double local_pi=;

    double area;

    double r=;

    area=local_pi*r*r;

    printf("The area is: %2f",area);

    return 0;

  4. Anonymous users2024-02-02

    The C++ procedure for the corrected high-precision division is as follows (see figure, see note for changes) <>

  5. Anonymous users2024-02-01

    Do you understand the logic of division? Don't rush to write**, use pen and paper to think clearly about the logic first.

    for(i=0;i<=100;i++)

    a=a*10;Take this sentence as an example, a=a*10, you didn't remove the integer part of a b, right? So the result must have been wrong.

    s+=char(a/b+'0');

    a=a%b;

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