192 168 4 1, find the network address, broadcast address, subnet mask, valid IP address.

Network address. Broadcast address.

Subnet mask. A valid IP address.

Subnet mask.

This won't help you, I'm really sorry!

Landlord,None of the topics are like this.,IP address.。

Must be masked with a subnet.

Broadcast address, subnet mask, valid IP address.

2. A standard Class C address, find the network address, broadcast address, subnet mask, and valid IP address.

Otherwise, the subnet mask is simply uncomputable if there are no other conditions.

The conventional method is to convert the host address and subnet mask into binary numbers, and the network address can be obtained after logic and operation. In fact, if you think about it carefully, you can get another method: the mask contains 256 - 224 = 32 IP addresses (including network addresses and broadcast addresses).

Then a network address with such a mask must be a multiple of 32. The network address is the beginning of the subnet IP address, the broadcast address is the end, and the usable host address is in this range, so it is slightly less than 137 and is only 128 in multiples of 32.

The last 192 of the subnet mask is replaced with binary, which is 11000000, that is, the first 26 of the IP address are the network number, the last 6 are the host number, the network number is the network address, the host number is all 0, and the broadcast address host number is all 1, that is, the network address broadcast address.

128=10000000b,191=10111111b）

72 binary 01001000, subnet mask 192 binary 11000000, result 01000000, this is the network address, that is, the broadcast address host bit is all 1, and the next 6 bits are the host bit. 01111111, ie.

Summary. Conversion process:1

Calculate the IP address and subnet mask to obtain the network address: Broadcast address: Turn the rightmost binary number of each group of binary numbers in the subnet mask into 1, and the rightmost binary number of each group of binary numbers in the IP address is calculated with it to obtain the broadcast address

Number of subnets: Add 1 to 2 n in the subnet mask from the first 0 on the left to 0 on the far right, that is, 2 nCIDR Range:

The number of subnets is 16, so the number of hosts is 2 14 - 2 = 16382 (where 2 is the broadcast address and the network address).

Find the IP as the network address, host address, broadcast address, number of subnets, network range and number of hosts for the sub-town Xianji network mask.

Hello, dear, it's a pleasure to serve you! Network Address: Host Address: Pure Broadcast Address: Number of Commands: 128 Network Segment Range: -Number of Hosts: 2 18-2=262142

Is there a conversion process?

Broadcast address: Turn the rightmost binary number of each group of binary numbers in the subnet mask into 1, and the rightmost binary number of each group of binary numbers in the IP address is calculated with it to obtain the broadcast address: Number of subnets

Add one to the number of bright 1s in the subnet mask from the first 0 on the left to 0 on the far right, that is, 2 n, so the number of subnets is 164CIDR Block Range: The minimum network address destruction bandwidth is as follows

The maximum network address is 16, so the range of network segments is as follows: The number of hosts is 16, so the number of hosts is 2 14 - 2 = 16382 (where 2 is the broadcast address and the network address).

By analyzing the subnet mask, it can be concluded that the third byte of the subnet mask is 10101000, which is converted to a decimal number of 168. Therefore, the address range of this outcry subnet starts from 168. Based on the subnet mask, the IP address is divided into two parts: the network address and the host address

Segment address range and number of hosts available. The subnet mask of the CIDR block where the IP address is located is the broadcast address, the network segment address range is 62, and the number of available hosts is 62 (excluding the network address and the broadcast address, that is, 62=2 6-2). <

If the IP address is set to, write the subnet mask, broadcast address, and network of the CIDR block where the IP address is located.

Segment address range and number of hosts available. The subnet mask of the CIDR block where the IP address is located is the broadcast address, the network segment address range is 62, and the number of available hosts is 62 (excluding the network address and the broadcast address, that is, 62=2 6-2). <

Here are the related extensions, I hope you find it helpful! ~<

If you want to know more about the network where the IP address resides, you can calculate the network address, host address range, and number of available hosts based on the IP address and subnet mask. The specific calculation method is as follows:1

2.The network address is calculated, that is, the IP address and subnet mask are bitwise and arithmetically calculated. (IP Address) (Subnet Mask) (Network Address) Therefore, the network address where the IP address is located is calculated to calculate the host address range, that is, the network address and the subnet mask are inverted bitwise, and then the result is bitwise and calculated with the IP address.

Host address mask: Host address mask negation (network address) (host address mask negation) (minimum of host address range) (maximum of host address range) Therefore, the host address range in which the IP address address is located calculates the number of available hosts, i.e., the number of IP addresses in the host address range. Number of hosts available = 62 - 2 = 60 Therefore, the number of hosts available in the network where the IP address is located is 60.

Existing IP addresses, subnet masks, number of hosts, number of available hosts, and broadcast.

Hello! Pro-<>

Based on the IP address and subnet mask given, we can calculate the number of hosts, the number of available hosts, and the broadcast address for that network. First of all, according to the subnet mask, we can determine that the network address is and the broadcast address is. Secondly, since the subnet mask is, that is, the first 24 bits are network bits and the last 8 bits are host bits, the number of hosts in the network is 2 8-2 = 254 (minus network addresses and broadcast addresses), and the number of available hosts is 254.

Summary. Hello, write binary.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

Brother, you write it in this form.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

To divide two subnets, write the subnet number, subnet mask, broadcast address, and host address range.

Summary. 1.The network bit is 27, and the host bit is 32-27 = 5

So the subnet mask is.

2.Convert the decimal of an IP address to binary

PS: The network address binary is the IP address binary with all host bits as 0, so only the last 8 bits are converted.

PS: The broadcast address binary is the IP address binary and all host bits are 1, so only the last 8 bits are converted.

3.Therefore, the maximum number of hosts that can be accommodated in the subnet is 32.

The number of hosts that can be accommodated is 32-2=30.

The IP address and subnet mask are converted to binary and then the result of the phase and operation is converted to decimal to get the network number.

Straight answer. Hurry up.

Velocity. 1.The network bit is 27, and the host bit is 32-27=5, so the subnet mask is Convert the decimal of the IP address to binary" The network address is the beginning of the subnet address, and the host bits are all 0:

Convert the binary of the network address to decimal :: The binary of the network address is the binary of the ip address and all the host bits are 0, so just convert the last 8-bit broadcast address to be the end of the subnet address, and the host bits are all 1: convert the binary of the broadcast address to decimal ::

The broadcast address binary is the IP address binary with all host bits as 1, so only the last 8 bits are converted to 3Therefore, the maximum number of hosts that can be accommodated in the subnet is 32, and the number of hosts that can be accommodated is 32-2=30 4How many subnets does the network address have:

2 8 32 = 8 ——— Copyright Notice: This article is the original article of CSDN blogger Jiaqi V, following the CC BY-SA copyright agreement, **Please attach the original source link and this statement. Link to original article.

I hope I can help you and wish you a happy life <>

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Are you sure?

Uh-huh, dear, I hope I can help you, and I wish you a happy life<>

If you have any questions, you can come to consult, if not, I hope you can give a like, thank you.