Help, math problems, three teams A, B, and C play a soccer match

C drew 0:0 and won 2:0.

Idea: B loses 0:2, it must be lost to C, because team A has a total of 0 goals.

Since there is one game for every two teams, one team plays two games.

So a 1-0 win for Team B is a win over A.

The first team has scored 0 goals in total and has a draw.

So Team A vs. Team C is a 0:0 draw.

I don't know if the landlord understands

Team B defeated Team A 1:0 and lost Team C 0:2.

Team A lost to Team B 0:1 and drew 0:0 with Team C.

Team C drew 0:0 with Team A and won 2:0 against Team B.

Team C has the best record.

Team C drew 0:0 with A and won 2:0 against B.

Because Team A has a draw and B does not, the draw is between C and A.

Team B loses 0:2 and A doesn't score, so C:B is 2:0

A: 1 draw, 1 loss.

B 1 win 1 loss.

Third? Victory? Flat? Lose.

Solution: When A vs. B, B wins.

A vs. C, A and C.

So: when B vs C, B loses, C wins.

So it comes to C with 2 goals.

Derive it for you.

First, draw three kinds of arrangement: A, B, A, C, and B.

First of all, because Team A scored 0, Team B will not lose to Team A.

That is, team B loses to team C and wins team A, and B and C 0:2 A and B 0:1 Secondly, team A has a draw.

So A-C 0:0

From this, it can be seen that A C is 0:0 A and B is 0:1

Win and draw.

A loses to a draw.

B Loses and wins.

C wins and draws.

So, C is one win and one draw.

Read a lot of books!

A has 1 point, B has 3 points, C has 4 points: win and draw.

C: B 2:0

A: C 0:0

It's simple. Just make a table.

B wins C, wins by 1 goal in this game, plus loses to A by 2 goals in the last game, so 1-2 = -1, so there is a goal difference of -1.

C wins A, wins by 1 goal in this game, plus loses by 1 goal to B in the last game, so 1-1 = 0, so there are 0 goal difference.

A wins B, wins by 2 goals in this game, and then loses to C by 1 goal, so 2-1=1, so there is 1 goal difference.

So, the final ranking is:

1 A Goal difference is 1

2 C Goal difference is 0

3 B Goal difference is -1

Finally, how to teach the owner the easiest way to see the goal difference, you first look at the number of goals scored by each team, and then look at the number of goals conceded, and finally subtract the number of goals conceded is the team's goal difference, and the team with the most goal difference ranks high. For example, A, scored 4 goals in two games and conceded 3 goals, using 4 goals minus 3 goals conceded, equals 1, so A's goal difference is 1. And so on and so forth.

1A, 2C, 3B.

A scored 4 goals and conceded 3 goals to win by one.

C scored 4 goals and conceded 4 goals with a goal difference of 0.

B scored 4 goals and conceded 5 goals Goal difference -1.

The general rule is to compare the points first, then compare the relationship between winning and losing, and then compare the number of goals to earn the winning goal, and finally compare the number of goals 1, the three teams have the same points, and they have each other's wins and losses, so look at the winning ball and compete for the winning goal: A+1 B-1 C0

A first 2, C and B ratio.

Points are the same: B wins C 3; 2 Therefore B is the second, C is the third.

You're asking the point, what is the proportion?

Team B has to play: 4-1=3 (field) with ruler

3 4 2 = 6 (field).

Answer: Team B has to play 3 games, a total of 6 games Therefore, the answer is: 3, 6

1. If A wins x and loses (3-x), and D wins m and loses (3-m), then A, B and C all win x and lose (3-x). The number of wins adds up to the number of games lost, so x+x+x+m=(3-x)+(3-x)+(3-x)+(3-m).m=6-3x, m

It is easy to lose and verify that only m=3 is an integer solution, so Ding won three games.

2. There are a total of 6 ball games, 6 pairs of winners and losers. Because there are as many games won and lost as many games, there will only be a solution if three teams win each game. The field laughs at the spring god is decided, and there is nothing at least not at least.

A wins B, B wins C, C wins A, and then A, B and C all dig up and win Ding, the total number of games is 6, and the number of wins is

Therefore, the trapped yard Ding wins 0

Let's assume that the score of the three games is: Min Ruler.

A: B A: B

A: C C: D

B: C E: F

According to your conditions.

Goals scored: A+C=5

Number of goals scored in B: b+e=3

Number of goals conceded by B: a+f=3

C Goals: d+f=2

C conceded goals: c+e=5

According to the last condition.

A and C both score That is, both c and d are greater than the bury roll is equal to 1, less than or equal to 2 (d + f = 2) according to d + f = 2

Assuming the first case d=1, f=1 can be deduced from a=2, b=1, c=3, d=1, e=2, f=1

The scores of the three games were 2:1, 3:1, and 2:1

The answer is 3 and 1.

Assuming the second case d=2, f=0 can be deduced from a=3 b=2 c=2 d=2 e=5 f=0

The scores in the three games were 3:2, 2:2, and 5:0

However, the condition for the limit is that there is no draw, so this assumption is not valid.

To sum up, the answer is 3:1

The answer is that A and C each scored 2 goals. As can be seen from the question, the number of goals conceded by A is 2, so the score of the three games is: A 2-2 C. A 3-0 B. B 3-0 C.

The number of balls A and C is 3 and 1 respectively.

The score of A and B is A1:B1, the score of A and C is A2:C1, and the score of B and C is B2:C2.

From the question, it can be seen that (1)a1+a2=5, (2)b1+b2=3, (3)c1+c2=2, (4)a2+b2=5, (5)a1+c2=3.

From (1)-(5), (6)a2-c2=2

Add it to (3) to get A2+C1=4, that is, the goals of A and C in this game are 4, and there is no draw, and C has a total of 2 goals. The result was 3:1, and the scores of the three games were 2:1, 3:1, and 2:1.

Solution: Suppose the scores of the three games are:

A: B A: B

A: C C: D

B: C E: F

According to your conditions.

Goals scored: A+C=5

Number of goals scored in B: b+e=3

Number of goals conceded by B: a+f=3

C Goals: d+f=2

C conceded goals: c+e=5

According to the last condition.

This means that both C and D are greater than or equal to 1, and D is less than or equal to 2 (D+F=2) according to D+F=2

Assuming the first case d=1, f=1 can be deduced from a=2, b=1, c=3, d=1, e=2, f=1

The scores of the three games were 2:1, 3:1, and 2:1

The answer is 3 and 1.

Assuming the second case d=2, f=0 can be deduced from a=3 b=2 c=2 d=2 e=5 f=0

The score of the three games is 3:2 2:2 5:0, but the qualifier is that there is no draw, so this assumption is not valid, and the answer is 3:1

So the answer is: 3, 1

3：1。The results of the matches set A vs B, A vs C, and B vs C are:

a:b,c:d,e:

f。According to the above conditions, it can be obtained: a+c=5, b+e=3, a+f=3, d+f=2, c+e=5.

From the first formula, we can get a=5-c. From the fourth formula, we can get d = 2-f, f = 3-a, then d = a-1, then d = 5-c-1 = 4-c. When C = 4 and D = 0, it is not eligible for both teams to score; When c=3, d=1;When c=2 and d=2, it does not meet the conditions for no draw in the game; When c = 1 and d = 3, it is not eligible for the number of goals in C to be 2.

So the score of both teams is 1-1.

Hello: Team A has played 3 games, which means that Team A has played 1 game with B, C and D, Team D has played 1 game, Zhaoyuan has played with A, and Team B has played 2 games, one is the same A, and the other can only be the same C.

Therefore: C played one game with B, and accompanied by the same match A, a total of 2 games.