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Obviously, 101*12, the following 1*12 accounts for two digits is 12, and the front 1*12=12 advances one place, so it is 1212
The same is true for 202*12, 2*12 is 24, the 24 in the back accounts for two places, and the 24 in front is one place forward.
303*12, 3*12=36 in the back, 36 in front, 363
404*12, 4*12=48, so it's 4848
505*12, 5*12=60, so it's 6060
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This question is reasoning, not calculation, and it is very easy to do.
Question 1: 101*12=1212 Question 2: 202*12=2424 From the results, it can be seen that the first two digits and the last two digits are multiples of 12 and are the same.
That is: 1*12=12 so 101*12=12122*12=24 so 202*12=2424 and so on. 3*12=36 So 303*12=36364*12=48 So 404*12=48485*12=60 So 505*12=6060
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Owners: The game has taken the system since the final stage of the 32-team competition, with 16 teams at this time than in the last 16 games.
?Eight of the 16 teams in the final game were 16 +8 more than in the past
?Two games against four of the last eight teams in the game at this time than in the last 16 +8 +4 games.
?The last game of the four teams eliminated the time than in the last 16 +8 +4 +2 matches between the two teams Ben.
?The last match of the two teams of the team in the last 16 +8 +4 +2 +1 games (to determine the champion).
Total number of fields: 16 +8 +4 +2 +1 = 31 (field).
A: There are a total of 31 matches in the game to determine the champion.
You want to help (this question regularly, tell you a formula: total number of fields = number of teams -1, want to know how the formula can ask me too).
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That is, x0x * 12 two x*12 results are put together, the specific reason can be 12*x0x (note: not x0x*12) column vertical to know, the 0 just makes the two x*12 results can be staggered together.
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If you know the book Mathematical Quick Algorithm, you will know that the corresponding rules of this problem: 3 digits are the same at the beginning and end of the same number in the middle, multiply by two digits, and you only need to repeat it when you multiply the number to two digits. I can't remember how to write it when the number is three digits.
I watched it when I was in junior high school.
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Because there is a 0 in the middle, when the single digit is multiplied by 12, the ten digits remain unchanged after the sum is added. For example, 505*12=(500+5)*12=500*12+5*12=6000+60=6060Did you find out?
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If you know, 101*12=(100+1)*12=100*12+1*12=1212
In the same way, 202*12=2*101*12=2*1212=2424 303*12=3*101*12=2*1212=3636
I hope you understand, thank you.
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The answer to the bai case upstairs must be wrong, and the correct answer to du may be zhi204, dao, (25 first number.)
The inner 4 is 3 times different from the fourth volume 12, the seventh number is 3*5, the second number 6 is 4 times different from the fifth number 24, the eighth number is 4 * 5, the third number 7 is 5 times different from the sixth number 35, and the ninth number is 5*5
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The correct answer is:
copy20
The first number is 4 4 * 3 = 12 and the second number is 4 * 3 = 12.
The third number is 7 7 * 5 = 35
The seventh number is 15 3*5=15
The eighth number is 20 4*5=20
The ninth number is 25 5*5=25
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Is it really the answer upstairs?
I counted for a long time.
After graduating from college, I couldn't solve the problems in elementary school.
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Oh my God, I calculated it for a long time, but I didn't figure it out! You might as well find another job!
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Is this a math problem in Primary 4? More calculus than calculus.
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What to fill in next, number 122
The first number of each group is 2 to the n1st power.
If the third number is 3412, then the last two are 4520, 5630
2. Interesting math problems. The following table is filled in with the numbers. 25
20 Answer: Look at the column by column
So 6*2 (
i.e. () is 12
12 Answer: Look at the line by line:
So 10*2-7*2=(
4 i.e. () = 10
What to fill in the place of the question mark?
A: Yes 6! Subtracting the first two numbers gives you 1, and adding the last two numbers gives you 10
And the sum of the beginning and the end is 11
So it's 6
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Question 1: 11 99 = 1089, 111 999 = 110889, 1111 9999 = 11108889, what is the law of product? 11 99 = 1089 2 1 2 9, the product is 1 1, 1 0, 1 8, 1 9111 999 = 110889 3 1 3 9, the product is 2 1, 1 0, 2 8, 1 91111 9999 = 11108889 3 1 3 9, the product is 3 1, 1 0, 3 8, 1 9...
Multiply n 1s by n 9s, the product should be: n - 1 x 1, 1 x 0, n - 1 x 8, 1 x 9 e.g. 1111111 9999999 = 11111108888889 Question 2: 12 42 = 24 21, 13 62 = 26 31, 14 82 = 28 41, 46 96 = 69 64.
Write a few more equations like this? The rules that can be obtained from the first three groups are: the ten digits of the second number are twice the single digits of the first number, and the single digits of the second number are twice the first tens of digits, and the two numbers exchange their own tens and single digits respectively and multiply, and the product is equal.
From this rule we can write: 34 86 = 43 68, 42 48 = 14 84
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1.I don't know.
2.Answer: 86, 87
Regularity: x, 2x, 2x+1, 2(2x+1), 2(2x+1)+1, 2[2(2x+1)+1], ,,2[2(2x+1)+1]+1, and so on.
It's a really hard question now.
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Only the second one was seen.
The rule is based on 10 and then in pairs.
The first number is 2 times the previous number, the second number is the first number plus 1, so the second number is 10 2=20, the second number is 20+1=21, and the third number is 21 2=42
The 4th number is 42+1=43, the 5th number is 43, 2=86, and the 6th number is 86+1=87
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First: the first two are multiplied by two plus one, then add 11, then add 10, and then add 9.
Second: It has already been said above.
I don't know if it's right???
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Find out the arrangement of the following questions, and then fill in the appropriate number in ( ).
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, carefully observe the pattern of each row below, and then fill in a number in parentheses to make it conform to this pattern.
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1) 17, a difference of 4; 2) 81, 3 times the previous number of the latter number; 4) 11, +1+2+3+4+5+6, add 1 in turn. If the boys are standing in a row, 5 boys.
There are 4 girls in the middle station, 9 girls in the middle station of 10 boys, 19 girls in the middle station of 20 boys, 49 girls in the middle station of 50 boys, and 99 girls in the middle station of 100 boys. Looking at the interval, there are 4 intervals in the middle of 5 people, and the interval can be subtracted by 4 by the total number of people in minus 1 is equal to 11, the same as the previous question.
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28 Three in a group, and the multiplication of two equals the third.
Pay attention.
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1)27,243,729;Rule: 3 to the power of 0 = 1, 3 to the power of 1 = 3, 3 to the power of 2 = 9, 3 to the power of 3 = 27 ......
2)31;Rule: The previous number adds the last one of a certain number 1 + 2 = 3, 3 + 4 = 7, 7 + 8 = 15, that is, the addition of the number is multiplied by two respectively) So 15 + 16 = 31, 31 + 32 = 63
3)13;Rule: The sum of the first two numbers is the next one.
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27,243,729;Each number is three times the previous number.
31;Each number is twice the previous number plus one.
13;Each number is the sum of the first two numbers.
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The first group of bai
is multiplied by 3 in turn, so 1*3=3,3*3=9,9*3=27,27*3=81,81*3=243,243*3=729, and the answer is 27,243,729;zhi
The second group is the DAO plus 2 to the nth power in turn.
version (that is, n 2 multiplication), weight 1 + 2 = 3, 3 + 2 * 2 = 7, 7 + 2 * 2 * 2 = 15, 15 + 2 * 2 * 2 * 2 = 31, so fill in the parentheses 31, 31 plus the product of 5 2 multiplied to get the latter number 63,;
The third group is the sum of the first two numbers is the third number, such as 1+1=2, 1+2=3, 2+3=5, 5+8=13, so fill in 13 in parentheses, you can verify it, because 13+8 is equal to the following 21.
I don't know if you can understand this, I'm really a waste of wood in terms of language expression, children, you give some face
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