A and B have 56 apples, A has 5 more apples than B, and how much A and B each have is solved by equa

Updated on educate 2024-02-08
11 answers
  1. Anonymous users2024-02-05

    The first on the first floor made a mistake, the question said that B took one-eighth less time than A, it should be t B = (1-1 8) t A, but by no means t A = (1 + 1 8) t B.

    Let the distance of A be s1 and the distance of B be s2, and the time taken by A and B is t1 and t2 respectively, then the system of equations can be obtained according to the known.

    s1=s2+(2/5)s2

    t2=t1-(1/8)t1

    i.e. s1=(7 5)s2

    t1=(8/7)t2

    The two equations are divided left and right, and s1 t1 = (49 40) (s2 t2).

    i.e. v1=(49 40)v2

    So v1:v2=49:40

    This kind of question must be kept in mind: a fraction of a fraction is multiplied by a fraction on the basis of whom. For example, if I am 1 5 years older than you, I add 1 5 to "your age", which does not mean that you are 1 5 years younger than me

    For example: I have three apples and you have two, and I have one-half more than you (and more is one-half of your apples). And you're one-third less than me (because one-third of my apples are one).

    You are one less than me, of course a third less than me——— because you are comparing me to see how many or less are a fraction of my number.

    It's a bit of a mess, but I think everyone understands. Hehe, it's that you often make mistakes when doing questions.

  2. Anonymous users2024-02-04

    Solution: Let A have x and B have x-5.

    x+(x-5)=56

    2x-5=56

    2x=61x=

    The data in the question is incorrect.

  3. Anonymous users2024-02-03

    Dissolution: Already? Piece.

    5 equals 562? +5 equals 56

    2?Equal to 51 equals.

  4. Anonymous users2024-02-02

    Summary. Pro, since A gives B 6, so that A reduces by six, B has six more, and the difference between A and B becomes 12, because A is 2 less than B, so these 12 minus two is equal to ten, which is the original number of A more than B.

    A and B have some apples, and after A gives B 6, A has 2 fewer apples than B, so it turns out that A has more apples than B.

    Dear, this question will take about two minutes, and I'll send it to you right away!

    Waiting. The calculation process is as follows: 6 + 6-2 = 10 (pieces) A turns out to be ten more than B.

    Seek parsing. Pro, since A gives B 6, so that A reduces by six, B has six more, and the difference between A and B becomes 12, because A is 2 less than B, so these 12 minus two is equal to ten, which is the original number of A more than B.

  5. Anonymous users2024-02-01

    Right now. A has 50 3 2 +1)=20.

    B has 50-20 = 30.

    The original year of the bureau is coming:

    There are 20+5=25 carapaces.

    B has 30-5=25.

  6. Anonymous users2024-01-31

    A and B have a total of 15 + 25 = 40, A gives B some, and it is known that B is 7 times that of A.

    Let A have a, then B is 7a key cavity.

    a+7a=40

    A = 5 A pairing: 5 B: 35.

  7. Anonymous users2024-01-30

    A has 5 apples and B has 35 apples.

  8. Anonymous users2024-01-29

    B quietly turned out to be only 1-1 5x2=3 5 of A

    A originally had 240 (1+3 hail yards 5) source state which = 150 kg.

    B originally had 240-150 = 90 kg.

  9. Anonymous users2024-01-28

    After dissolving x to B, it is 4 times that of A.

    4(23-x)=27+x

    92-27=5x

    x = 13.

  10. Anonymous users2024-01-27

    19+5=24 (pcs).

    24 2 = 12 (pcs).

    Answer: After A gives B 12 potatoes and hailstones, B has 5 more apples than Liang A.

  11. Anonymous users2024-01-26

    Summary. Hello dear, let A have x, B has y x+y=15x-3=y+3+1 solution x=10, y=5

    A and B have a total of 15 apples, A gives 3 to himself, and after B eats 1, A and B have the same amount, so how many are A and B.

    To be solved with equations.

    Hello dear, let A have x, B has y x+y=15x-3=y+3+1 solution x=10, y=5

    Don't use binary equations.

    If A has x, then B has 15-x x-3=15-x+3-1x=1015-x=5 answers.

    OK dear, if there is anything unclear, you can consult me again

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