Computer Network Fundamentals Post course Questions If a company has 350 hosts, what kind of IP addr

Assign a Class B IP within the LAN!

Characteristics of Class A, B, and C IP addresses: When writing IP addresses in binary form, the first digit of Class A addresses is always 0, the first two digits of Class B addresses are always 10, and the first three digits of Class C addresses are always 110.

Class A addresses. 1) The first byte of a Class A address is the network address, and the other three bytes are the host address. The first bit of its 1st byte is fixed at 0

is a private address (a so-called private address is an address that is not used on the Internet, but is used in a local area network).

Range (is a reserved address for round-robin testing.)

Class B addresses. 1) The first and second bytes of a Class B address are network addresses, and the other two bytes are host addresses. The first two digits of its 1st byte are fixed at 10

3) Private addresses and reserved addresses for Class B addresses.

is a private address.

is a reserved address. If your IP address is automatically acquired, and you don't find a DHCP server available on the network. You'll get one of the IPs.

It is a broadcast address and cannot be assigned.

Class C addresses. 1) The 1st, 2nd, and 3rd bytes of the Class C address are the network address, and the 4th byte is the host address. In addition, the first three digits of the first byte are fixed at 110.

is a private address. （

Solution: (1) The binary of the subnet mask is :, since the first 3 paragraphs are all 1, so just look at the last paragraph:

11100000 on it. The binary of 112 is: 01110000, and the binary of 120 is:

The binary of 01111000, 161 is: 10100001, and the binary of 222 is: 11011110, and their binary and 11100000 are logically and calculated (all 1 is 1, see 0 is 0) respectively

01100000, 01100000, 10100000, 11000000, it can be seen that the logic is the same as the calculated result is 112 and 120, so they can communicate directly; The rest of them cannot communicate directly with each other and with the first two (because the logic and calculation results are different, then they have different network numbers and belong to different networks).

2) The result of logic and calculation from the binary of (1) and 111000000 is 11000000, which is 192; Set the last 5 digits of 110 00000 to 1 to get it

110 11111, converted to decimal is: 223. Explanation:

The network address of the network segment can be obtained by logic and calculation, and all host bits are set to 1 to obtain the broadcast address. Therefore, the range of host E is: remove the network address and broadcast address, and then remove the 222 occupied by host D).

The network address applied for by a company is to be divided into 6 subsidiaries, the largest subsidiary has 30 computers, and each subsidiary is in a subnet, so what should be the subnet mask? What are the network addresses of each of the 5 subsidiaries?

Subnet division first refers to a specific host address, which is more accurate to be divided into 6 subnets, and it is necessary to borrow 3 bits of the 8 bits of the host address, 2 to the 3rd power is equal to 8, and 2 to the 2nd power is equal to 4 is not enough. If you borrow 3 bits, the host bit also has 2 to the 5th power, that is, 32 (-2) hosts, which can meet the requirements of 26 hosts, so it is divided into 8 subnets 1. Subnet mask.

Subnet mask. Subnet mask. Subnet mask.

Subnet mask. Subnet mask. Subnet mask.

Subnet mask.

Assuming that the IP address of a computer in a network is assumed, the maximum number of machines+ that can be accommodated in the network

Dear, I'm glad to answer for you: Suppose the IP address of a computer in a network is, then the network can accommodate the largest machine + Answer: Dear, hello, this is related to the number of bits of the host bit of the IP address of the virtual address.

For IP addresses, the first 24 bits of the IP address are network bits, and the last 8 bits are the host bench burn bits, which belong to Class C IP addresses and the subnet mask is. n=8, then the number of hosts = 2 8 -2 = 254. If you have any questions, you can give me feedback in time!

Summary. Hello dear! <>

Glad to answer for you: in order to meet the needs of the largest subsidiary with 35 computers, we need to calculate the subnet mask. The nearest but not more than 35 to the power of 2 is 32 (2 5 = 32), so we need 5 bits to allocate the host.

Because an IPv4 address has a total of 32 bits, we need to keep 27 bits in the subnet mask (32 - 5 = 27). (1) The subnet mask should be set to: Next, we need to calculate the effective host IP address range for the 4 subsidiaries.

Subsidiary 2] Start IP: End IP: Subsidiary 3] Start IP:

End IP: Subsidiary 4] Start IP: End IP:

The network address applied for by a company is to be divided into 5 subsidiaries, and the largest subsidiary has 28 computers.

Wrong. Not this topic.

Hello dear! <>

Glad to answer for you: in order to meet the needs of the largest subsidiary with 35 computers, we need to calculate the subnet mask. The nearest but not more than 35 to the power of 2 is 32 (2 5 = 32), so we need 5 bits to allocate the host.

Because an IPv4 address has a total of 32 bits, we need to keep 27 bits in the subnet mask (32 - 5 = 27). (1) The subnet mask should be set to: we need to calculate the effective host IP address range of the 4 subsidiaries.

Subsidiary 2] Start IP: Celebration Hand Bundle IP: Subsidiary 3] Start IP:

End IP: Subsidiary 4] Start IP: End IP:

Good. The second question can be answered. a

(1) Decimal representation.

2) It is a Class C address.

3) The subnet mask is:

4) (5) The network number of each subnet is the last digit of the IP address before to, minus 1, and the broadcast address of each subnet is the last digit of the IP address after to, plus 11> to

2> to

3> to

4> to

5> to

6> to

7> to

8> to

6) (7) Switches, routers.

8) The topology diagram is simple to do by yourself.

(1) Class (3) has a total of 5 subnets, and the 3rd power of subnet 2 -2 is 6>5, so that the subnet occupies 3 host bits, and the host bit is 5, and the 5th power of 2 -2=30 is just enough for each department. (5)

Subnet mask. Layer 2 and Layer 3 switches. Layer 2 divides VLANs and data of each department, and Layer 3 connects each VLAN. (8) Five second floors are connected to one third floor.

Hand-typed.,It's not divided yet.。。。

1．2．c3．

4 5 departments, about 20-30 computers per department. So a 27-bit mask can be used, and each bottom can accommodate 32 hosts. The subparagraphs are as follows:

5 Departments.

IP ranges. Mask 1 sector.

2 divisions, 3 divisions.

4 divisions, 5 divisions.

6 8 Draw your own topology diagram.

They have a problem with this typography. Annex.

A is false, the IP address of the home computer generally belongs to the C category.

B is wrong, you can only set it yourself if you have a router, and it is not arbitrary to set C right, because this refers to the IP address of the host in the Internet, which means that there is no router connected to the home side.

d wrong, ipv6 is 32-bit hexadecimal.