Is it possible that the centripetal force of a satellite in different orbits is the same?

It's possible. Because the centripetal force required to do circular motion is completely provided by gravitational force. And gravity with planets.

The mass is directly proportional to the square of the distance from the center of mass. In addition to the gravitational constant, in addition to the mass of the sun, the other two conditions, that is, the mass of the planet and the orbital radius mentioned above, as long as the ratio is appropriate.

The centripetal force is the resultant force directed towards the center of the circle (center of curvature) when an object moves along a circumferential or curvilinear orbit. The term "centripetal force" is named after the effect produced by the action of this combined external force. This effect can be produced by any force such as elasticity, gravity, friction, etc., or it can be provided by the resultant force or components of several forces.

Because circular motion is a curvilinear motion, an object in circular motion is also subjected to a resultant force that is different from the direction of its velocity. For an object in a circular motion, the centripetal force is a pulling force whose direction keeps changing as the object moves in a circular orbit. This tensile force points to the center of the circumference along the radius of the circumference, hence the name "centripetal force".

The centripetal force is directed towards the circumferential center, and the object controlled by the centripetal force moves in the direction of the tangent, so the centripetal force must be perpendicular to the direction of motion of the controlled object, producing only acceleration in the direction of the normal of velocity. Therefore the centripetal force only changes the direction of motion of the controlled object and does not change the rate of motion, even in non-uniform circular motion. In non-uniform circular motion, the tangential acceleration that changes the rate of motion is not generated by the centripetal force.

The magnitude of the centripetal force is closely related to the mass of the object (m), the length of the circumferential radius of motion of the object (r), and the angular velocity ( ).

Satellite Question: Gravitational Force Equals Gravity Equals Centripetal Force? - Correct.

For satellites, gravitational force and gravity are one and the same thing, and centripetal force is the effect it produces.

Terrestrial objects are not satellites and are affected by rotation, so they are approximately equal.

Weightlessness, overweight, and being subjected to gravity are two different things, and objects that are completely weightless are also subjected to gravity.

The circular motion of the earth satellite around the earth must be centripetal force, and this centripetal force is the gravitational force between the satellite and the earth. f 10,000 = f direction.

The gravitational force exerted on an object near the surface is the gravitational force at this time. f million = mgSo we can also say that the Earth's satellites orbiting in low earth orbit are the centripetal force provided by gravity. mg=f=mv2r=,,

To be precise, the attraction of the Earth to the satellite (gravitational force), not gravity.

1. Near-Earth satellite: The orbit of a spacecraft with an altitude of less than 500 km is usually called low orbit, and the orbit of 500 km and 2000 km high is called medium orbit. Medium and low orbits are collectively known as low earth orbit (also known as anterograde orbit).

2. The centripetal force of the satellite: The artificial earth satellite can operate in the earth's orbit, first because it has the first cosmic speed (kilometers and seconds), and because the earth's gravitational force (centripetal force) has been pulling it, like pulling a stone to a thin rope. In order for an object to move in a circle around the Earth under the influence of the Earth's gravitational pull (near-Earth satellite), the velocity of the object must reach the first cosmic velocity.

If the centripetal force required by the satellite happens to be equal to the gravitational force on it, it will move in a circular motion. If the centripetal force required is greater than the Earth's gravitational force, the trajectory of the object becomes an elliptical orbit. The more the velocity of the object is greater than the orbital velocity (the velocity of the circular motion), the more the elliptical orbit becomes "flattened", until the second cosmic velocity is reached, and the object flies out of the Earth's gravitational field along the parabolic orbit.

Exactly it should be provided by gravity. The essence of gravity is gravity.

Yes, because near-Earth satellites move around the Earth.

1 For objects on the ground, the object always moves in a uniform circular motion around the earth's axis, so the direction of centripetal acceleration is always directed towards the earth's axis.

If the object is at the equator, it moves in a uniform circular motion within the equatorial plane.

The gravitational force f = g m m r 2 (approximately equal to the gravitational force mg), which is exactly within the equatorial plane, is all used to provide centripetal acceleration.

f = m a = g m m r 2 , so at this time [centripetal acceleration] = [gravitational acceleration g] = g m r 2

If the object is at the poles, the centripetal acceleration is 0 due to being on the earth's axis

If the object is on the equator and between the poles, since the object is moving in a uniform circular motion around the earth's axis, so.

At this point, one component of the gravitational force provides centripetal acceleration.

Gravitational force f = g m m r 2 (approximately equal to gravity mg) and the direction is directed towards the center of the earth.

Centripetal acceleration] between the equestrian and the poles > of the poles.

Centripetal acceleration of ground objects and satellites: > of satellites at the equator.

Centripetal acceleration of terrestrial objects and geostationary satellites: Terrestrial > satellites [a = w 2 r = (2 t) 2 (r+h)].

Rationale: t is the same, the radius of the ground < the radius of the geostationary satellite.

Find g1 for geostationary satellites, g=g= for ground objects, in comparison.

The satellite orbiting the earth can be seen as a constant circumferential movement of Dachang, and the gravitational force provides the centripetal force for the satellite to move and roll; Swift Feast.

Therefore, the answer is: uniform circumference; Gravitational pull

The gravitational force is the resultant force of the centripetal force and the gravitational force, and when the gravitational force completely provides the centripetal force, the other component force is zero, i.e., the gravitational force is zero.

Follow-up question: Why does gravity provide all the centripetal force?

Answer: The centripetal force is provided by gravity.

Answer: The satellite moves around the celestial body, the distance is far from the comparison section, and the centripetal force is provided by the gravitational force.

Follow-up question: gravitational force will provide centripetal force and gravity, it is possible that gravitational force will also provide gravity at the same time as centripetal force, why is it only said that centripetal force is provided.

Follow-up question: Is it not subject to gravity if it is far away?

Follow-up: Gravity is the Earth's grip on objects on Earth, not celestial bodies.

a. The centripetal force of the geostationary satellite is provided by the gravitational force of the earth to the satellite, according to f direction =g mm r 2, although the mass of the earth is the same, the mass of the satellite may not be the same, so the centripetal force required by different satellites must be the same, so a is wrong; b. According to the centripetal force of circular motion provided by gravity, it can be seen that the linear velocity of the synchronous satellite is the same, but considering the vector nature of the linear velocity, it cannot be said that the linear velocity is the same, so b is incorrect; c. According to the centripetal force of circular motion provided by gravity, it can be seen that the centripetal acceleration of the synchronous satellite is the same, but considering the vector nature of the centripetal acceleration, it cannot be said that the centripetal acceleration is the same, so C is incorrect; d. According to the centripetal force of circular motion provided by gravitational force, it can be seen that since the period of the geostationary satellite is the same, the orbital radius of its circular motion is also the same, that is, the distance of the geostationary satellite from the center of the earth is the same d is correct, so d is selected