An iron ball fell from a tower of 100 meters

Correct answer: Drift westward. Reason:

We all know that the earth rotates from east to west, and any object will have inertia, inertia can maintain the motion of the object, the iron ball comes out of the hand and falls straight down, and in the process of the iron ball falling, the earth does not stop the process of turning eastward, so although the iron ball is falling in a straight line, it also falls in the "middle" of the west, in fact, this question is not difficult, draw a picture will come out immediately, I am not good at drawing pictures with my mobile phone, so I will not draw here, so you have to come on!

Theoretically, in the absence of external forces such as wind, iron balls are only subjected to gravity and electromagnetic forces. In the electromagnetic force, even if you let go of the equator, the electromagnetic force on an iron ball is only 1/10,000 of the neutral, and such a force cannot be offset at all at a height of 100 meters, so it will not be offset from the tower. It is a uniform acceleration motion in the vertical direction.

If you don't have to consider the electromagnetic force, it should be slightly biased like the east, because the iron ball will only be positively charged during the friction process, and the direction of the magnetic field is from north to south, so the iron ball can be regarded as a particle point charge, so the force is eastward. I don't know if this brother is satisfied? Hehe.

It doesn't matter which hemisphere it is in, from the angle of rotation of the earth, the distance from the spire to the center of the earth is larger than the distance from the bottom of the tower to the center of the earth, the angular velocity of rotation is the same, by v=r, the linear velocity of the spire is relatively large, and because the earth turns from west to east, the iron ball should deviate to the east. (Of course, this is not visible to the naked eye, and it has to be measured with quite advanced and accurate instruments, because the difference is too little!) I think in theory it should be

Because of the gravitational effect. Biased to the center of the earth.

It won't change.

It's like if you're in a car, you jump up and then you land, are you still in your original relative position?!In the same way, the iron ball is the same as the earth.

ABC is all wrong! Because when the ball is at the top of the tower, it also rotates and revolutionizes with the earth due to inertia.

So the ball won't be good!

Although given a height of 100 meters!

But it can't be simply assumed that it is affected by magnetic fields!

Effect of the Earth's rotation The Northern Hemisphere is westward and the Southern Hemisphere is eastward.

If you don't explain it, you can determine it in your own place, and the topic is from China, so I chose A.

bThe left-handed rule.

Affected by the Earth's magnetic field.

The geomagnetic field points from south to north.

Is there a problem with the topic?

I don't think it's biased in any direction.

For example, if you jump up on a bus, can you change the position where you land? It can't be changed, and this question is the same reason.

c Because the direction of the geomagnetic field is from south to north, and because it is an iron ball, it should be north.

If you don't think you have the right answer, then you can find a 100m tower and try it yourself!

It depends on whether you're in the Southern Hemisphere or in the Northern Hemisphere, and you have to think about the rotation of the Earth.

Galileo's experiments showed that they landed at the same time.

In the absence of the same resistance, they are landed together, according to the kinematic free fall formula h=1 2g(t) squared, the landing has nothing to do with the mass m, if the density is the same as the shape, the volume is large, the resistance is large, and the volume is large.

Ideally, it is to land at the same time. In reality, it is not easy to judge because of various factors

If it is released from the stool swimming, the air resistance is not counted.

Obtained by Bidane V 2 2gh.

The velocity sought is v root number (2gh) root number (2*10*100) 20*root number 5 m s

2ax=v a=g=10m s x=100 v=20 5m positive s t=v a=2 closed for 5s so 2 5s after landing in the first second falling distance x=1 2at=5m (t=1s) second x=1 2at 5m=15m (t=2s) third second x=1 2at 15m 5m=25m (t=3s) fourth second x=1 2at 25m 15m 5m 5m...

2ax=v?a=g=10m／s?x=100 v=20 5m s t=v a=2 5s so 2 5s after falling Zheng noisily in the first second to shout the distance x=1 2at?

5m (t=1s) second x=1 2at?5m=15m (t=2s) third second x=1 2at?15m 5m=25m (t=3s) fourth second x=1 2at?

25m－15m－5m=35m (t=4s) 4s~2√5s :x=100－35m－25m－15m－5m=20m,5,

There are two iron balls, one large and one small, which one will land first?

h=gt2/2 80=10xt2/2 t=4svy=gt=10x4=40m/s

Horizontal displacement = vot = 15x4 = 60m

vt = root number (v2 + vy2) = root number (15 2 + 40 2) = root number 1825 direction TGA = vy vo = 15 40 = 3 8s = root number (x2 + h2) = root number (60 2 + 80 2) = 100m

h=（1/2）gt^2

v vertical = gt = 40m s

t = root number (2h g) = 4s

x level = v level * t = v0 * t = 60m

h = 80mv = root number 1825m s

and the vertical direction angle is set to a

tana=3/8

x = root number (3600 + 6400) m = 100m direction and vertical direction 37 degrees angle.

Falling height h=1 2gt2, where h=100, g= substituting the formula to calculate t, v=gt, and the final result v= is obtained

If it is released from a standstill, the air resistance is not counted.

Obtained by v 2 2gh.

The velocity sought is v root number (2gh) root number (2*10*100) 20*root number 5 m s

Generally, the gravitational acceleration is directly determined to be g=10m s, if the iron ball has no initial velocity, then x=1 2gt can be obtained directly by using the uniform acceleration linear motion formula

1/2×10×25=125m