Simple C language problems I can t do when I just learn them

It should be 0It should be a remainder operation.

C++.

#include

using namespace std;

int main()

static const int gounianyear = 2006;

cout<<"Enter a 21st century Year of the Dog"<>yearget;

if(0 ==(yearget-gounianyear)%12){for(;yearget<3000; )cout<

Landlord,Upstairs doesn't know how to talk.,Don't pay attention.,Wait for me to post it**.。 C beginners who don't have a basic knowledge of other languages are a little slower to start, but they need to be dirty

#include

int main()

return 0;}

1 Select C for all

Relational division in a database looks like this:

For example, if r is divided by s, then the corresponding term with s is first found in r, and only the third record in the question r is eligible, r sa b c a bc 3 1 c 3 when r is divided by s to get the remaining column attributes, that is, c

，y=x>7? 6:5;means that if x>7 y=6, otherwise it is equal to 5.

k=7, k++ means to take the value of k first, and then give k+1, which is different from ++k. If j=++k, then give k+1 first, and then take the value of k, i.e., j=7, k=7

The first question is a trinocular operator that means "? "The former thing is true": "The former thing is false": "The latter thing, so the first question should be 6

The meaning of the second question is that k++ is used first and then added by one, and ++k is used first and then used, so the second question is that the value of j is 6 and the value of k is 7

The first one is a ternary operator, which means that x>7 is y=6, otherwise it is equal to 5

The second i++ means that the value of i is taken first, and then 1 is added to i, so j=6, k=7

Are you going to enter a public institution? Congratulations.

1) Two variables are defined, y=6 if x>7 and y=5 otherwise

2) Execute j=k first, then k=k=1 (k++), then j=6, k=7

The value of y is 6, + is in front, add 1 first, then assign, ++ is behind, assign value first and then add 1, so, j=6, k=7

y=x>7? 6:5;, first determine whether x>7 is true, if it is established, it is 6, and if it is not established, it is 5