Chickens and rabbits are in the same cage, with 17 heads and 42 legs, and chickens and rabbits each

Let's say it's all normal chickens and rabbits, one chicken with one head and two legs, not McDonald's chickens, one rabbit with one head and four legs, no splits.

Then 42-17*2=8 2=4 has four rabbits.

You can also assume that rabbits are disabled, that they all have two legs, that chickens are McDonald's chickens, that each chicken has four legs, that's four chickens.

Suppose they are all chickens and rabbits with normal heads and legs, and they are very smart, and they whistle once and stand on one leg, then blow once, and there are 25 legs left, and if they blow again, the chickens will all fall, and there are 8 legs left, divided by two, which is 4, and there are 4 rabbits and 13 chickens.

Set x chickens and y rabbits.

x+y=17

2x+4y=42

Solution: x=13, y=4

13 chickens and 4 rabbits.

Let's say there are x rabbits.

4x+2*（17-x）=42

4x+34-2x =42

2x=8x=4

17-4=13.

A: There are 4 rabbits and 13 chickens.

Hope!!!

Assuming that all 17 domestic animals are rabbits, then there are: 17 4 = 68 legs, which is more than the original 42 legs: 68-42 = 24 legs.

It is also known that there are more rabbits than chickens: 4-2 = 2 legs.

So how many extra legs do you need to make up for the extra 24 legs?

24 2 = 12 So there are 12 chicks and 17-12 = 5 rabbits.

Solution: Set up rabbits x only.

Then there are 11-x chickens.

4x+2（11-x）=42

4x+22-2x=42

2x=20x=10

Chickens have: 11-x = 11-10 = 1 (only).

A: There is 1 chicken and 10 rabbits.

If there are x chickens, then the rabbits are 17-x, so, 2x+(17-x)*4=42, and the solution is x=13, so there are 13 chickens and 4 rabbits.

Chickens and rabbits can be thought of in the same cage: the rabbit stands up, all as a chicken hail hunger, because there are 18 heads, so there should be 36 feet, but there are 56 feet in the question, and there are 20 feet out of the question. So column:

The number of rabbits is (56-18 2) 2 10, and the number of chickens is 18-10 8, and the equation can also be listed, so if there are x rabbits, then there are (18-x) chickens, and the equation is: 4x+2(18-x) 56, so x=10, so 18-10 8

Assuming it's all rabbits, chickens have:

14 4-38) (e.g. branch 4-2), 18 2, 9 (only), then rabbits have: 14-9 = 5 (only), A: There are 9 dregs of potatoes and 5 rabbits

So the answer is: 9; Hand Fight 5

There are x chickens, y rabbits x+y=17 2x+4y=42 The solution is y=4, x=13 4 rabbits, 13 chickens.

Set x chickens and 17-x rabbits.

2x+4(17-x)=42

2x=26x=13

13 chickens and 4 rabbits.

Let's say it's all rabbits.

4 10 = 40 (only) - feet.

6 (pcs) - Chickens.

10-6=4 (only) -- rabbit.

A: There are 6 chickens and 4 rabbits.

Solution: If there are x chickens, there are rabbits (10-x).

2x+4（10-x）=28

2x+40-4x=28

x=610-6=4 (only).

A: There are 6 chickens and 4 rabbits.

Suppose all chickens have 20 legs = 20 x 2 = 40 less 44-40 = 4.

So rabbit = 4 (4-2) 2

18 chickens and 2 rabbits.

The chicken has two legs, the rabbit has four legs, assuming that the chicken and the rabbit have no two legs, then 62-42 = 20, the rabbit has two legs at present, the rabbit originally had 4 teaching, 20 * 2 = 40, so the rabbit has a total of 40 legs, that is, there are ten rabbits, 21-10 = 11, there are 11 chickens.

Number of rabbits: (62-21x2) 2=10

Number of chickens: 21-10 = 11

Assuming that they are all rabbits, chickens have:

4 21-62) (4-2) = 11 (only).

21-11=10 (only).