First aid, junior high school math problems, find function expressions the worst type of question I

Let me try: set the time t of the q-point movement

Then s=(qn+pm)*mn2

mn=am-an

Because. qn = 3 times the root number of qa divided by 2 (math does not represent) am=ap 2 an=aq 2

Similarly. PM = 3 times the PA of the root number divided by 2

So. s = (Qa of 3 times the root number divided by 2 + 3 times the PA of the root number divided by 2) * (AP 2 - AQ 2

Simplification yields s = (root number 3 times t + root number 3) 2

1.By the title:

m²-6n+9+n²-4n+4=0

m-3)²+n-2)²=0

m=3,n=2

a（3,3）b（-2,2）

The analytic formula of the straight line is y=1 5x+12 5

2.By the title:

Substituting the (0,0) points into the original analytic formula, we get m=o or m=- 3 The original problem is a one-time function.

k≠0m≠-√3

m=0 must be written, otherwise it is incomplete.

1, by the square of m + the square of n - 6m-4n + 13 = 0The result is: (m-3) 2+(n-2) 2=0

obtained: m=3, n=2

After the point ab, then: mk+b=3,-2k+b=n brings in the value of m,n, and the solution obtains, k=1 5, b=12 52By the title:

Substituting the (0,0) points into the original analytic formula, we get m=o or m=- 3 The original problem is a one-time function.

k≠0m≠-√3

m=0 must be written, otherwise it is incomplete.

mk+b=3,-2k+b=n,(m+2)k=3-n,(m-3) squared plus (n-2) squared is equal to 0, so m=3,n=2, bring in k = one-fifth, b = twelve-fifth, (2).

1.Formula, (m-3) square + (n-2) square = 0, m = 3, n = 2 substitution.

2.I don't understand the question, is the square of +m + the square of m +2m squared?

1.From m2+n 2-6m-4n+13=0, the formula yields (m+3) 2+(n-2) =0

So m=3, n=2

So, 3=3k+b 2=-2k+b

The solution gives k=1 5b = 12 5 Therefore, y = (1 5) x + (12 5).

2.I don't understand.

The square of + n squared - 6m-4n + 13 = 0 can be changed to the square of (m-3) + the square of (n-2) = 0, because the square is greater than or equal to 0, so m = 3, n = 2, substitute into a straight line.

2.There is only one square of m, substituting (0,0) into the function, you can get the square of m + the root number 3m=0, and propose m,m(m+root number 3)=0, so m=0 or negative root number three, because it is a one-time function, the coefficient of x cannot be 0, so m is not equal to the negative root number three, so m=0

1 。3=mk+b

n=-2k+b

m 2 + n 2-6m -4n + 13 = 0 to get (m-3) 2+(n-2) 2=0, so m = 3, n = 2, bring in the above two equations to get k, b.

m^2+√3m

Bring in (0,0) and you will know m=0

1.Since any x is true, the coefficient of x is 0, and (2a-7b-8)x=10+8b-3a

2a-7b-8=0

10+8b-3a=0, a system of simultaneous equations, solved.

a=6/5, b=-4/5

2.When this function is a one-time function, it must satisfy m-1=1 and m-3≠-1, which is obviously not satisfied, and there is an x after it, so when.

m-3=0, this function is a one-time function, so m=3

Solution: From the problem: (2a-7b-8)x+(3a-8b-10)=0 to one real number x is true.

Therefore, the question condition can be satisfied if and only if: 2a-7b-8=0 and 3a-8b-10=0.

Solution: a=6 5 b=-4 5

Respectively through P1, P2, P3 as the perpendicular line of the X-axis, the perpendicular foot is H1, H2, H3, then Op1H1, A1P2H2, A2P3H3 is an isosceles right triangle, according to the product of the abscissa and the ordinate of the points on P1, P2, P3 is 4, respectively, the value of the abscissa of each point is found, and the law is found

To be honest, I can't see the problem clearly! **It's too small to see clearly when looking at the big picture.

(1) Solution: straight line ob: y=kx

Bring in b(2,3).

Get: y=3 2x

Let the expression of the inverse proportional function be: y=k x

Bring in e(2, get:

y=3/x

From the question, we can know o(0,0),b(2,3).

Therefore, the analytic formula of ob is y-0=(3-0) (2-0) and simplified to y=(3 2)x

From the question, we can know that e(2, let the analytic formula of the inverse function be y=k x

Because the inverse function crosses the point e

So the solution is k=3

So the analytic expression of the inverse function is y=3 x

2) From the question, it can be seen that the area of the quadrilateral is equal to the area of the rectangle, minus the area of the triangle OAD, and then subtract the area of the triangle OFE.

When y=3, 3=3 x, the solution is x=1

So f(1,3).

So the triangle OAE area is 2*

The area of the triangle OCF is 3*1 2=

So the area of the quadrilateral is equal to 3*

Solution: 1

s abm:s amc=bm:mc=1:2, i.e. (ob-om):(oc+om)=1:2 solution: om=1

i.e. the coordinates of m are: (-1,0).

2、∵cm=2bm, ob=oc=3

i.e. oc+om=2 (ob-om).

om=1∠ocn+∠kmc=90°， oam+∠amo=90°∴ ocn=∠amo

oc=oa△ocn≌s△oam

then on=om=1

3. There are 2 points.

ob=oa ∴ b=45°

Do BF perpendicular BC and equal BC, connect FE

Because fbe= cbe=45°

BFE BCE (Corner Edge).

In this case, the coordinates of point f are: (-3,6).

Make EF parallel to BC and equal to BC, connect BF

bef=∠ebc

EFB BCE (Corner Edge).

The coordinates of point f are:

Slope of AM = OA OM = 3

The equation for CE is: y-0=-1 3(x-3).

The equation for ab is: y=x+3

The coordinates of the intersection of CE and AB are (-3 2, 3 2) F coordinates: (-3 2-6, 3 2) i.e. (-15 2, 3 2).

Since y1 is proportional to x-1 and y2 is proportional to x, then let y1=a(x-1) y2=bx

y=a（x-1）+bx （1）

When x=4,y=2 and x=-1,y=-5.

4=a+2b,-5=-2a-b

The solution yields a=2 and b=1

Substituting Eq. (1), then y=3x-2

Solution: 1 Since y1 is proportional to x-1 and y2 is proportional to x, and y=y1+y2 let y1=a(x-1) y2=bx

So y=a(x-1)+bx

Substituting x=2, y=4 and x=-1 y=-5

a+2b=4

2a-b=-5

Solve the system of equations to get a=2, b=1

So the functional relationship between y and x is: y=3x+2

, y=-13

y1=k(x-1) y2=qx y=y1+y2=k(x-1)+qx

x=2 y=4 gives 2q+k=4 x=-1 y=-5 gives -q-2k=-5

Then solve by substituting x=5 into y=f(x).

When fed a feed: y=

i.e. y=(1) when fed b feed: y=

That is, y = (2) subtract (2) formula with (1) formula to get "0", indicating that feeding feed A is profitable, on the contrary, feeding B feed profit is large, if it is equal to zero, then the two are the same.

Solution: When feeding feed a is profitable.

At 5 o'clock, feeding B feed is profitable.

It's not good to play on a computer, you have to write it as less than or equal to 6

Greater than or equal to. Got it? If you don't understand, ask again!