Primary 5 Mathematics Wisdom House Application Questions, Rush T

Let ab be x kilometers apart, when A walks a kilometer and B walks x+ (a kilometer when two people meet, A walks a kilometer less than B. So.

x+(get x=12 km.)

km) km).

24 2 = 12 (km).

A: A and B are 12 kilometers apart.

Walk one kilometer less than B", which means that the meeting point is one kilometer away from place B), plus A walks first is 12 kilometers.

At this point, A walked a kilometer, which is less than B's. It can be calculated that B walked a kilometer) two people walked a total of a kilometer) that is, two whole journeys, then it can be calculated that A and B are 24 2 = 12 (kilometers) apart

Comprehensive equation: km).

You can draw a picture and you will understand, it is not difficult

B traveled a kilometer) A and B traveled together twice the distance between AB and 2 places, then the distance between AB and 2 places is. km).

Question 1 z=2+5-2=5 2x=3y, get x = 3 2 y, bring it into y+2z=x to get y+2 z=3 2 y 2 z=1 2 y

Y is 4 times that of Z.

x is 6 times that of z.

Question 2: When B catches up with A, the distance traveled by B is x, then the distance traveled by A is x+120, and the time required for them is t

64t=x72t=x+120

Get x=960

That is to say, A ran two laps, exactly two laps.

That is, in the position of A.

1) 2x=3y, x=(3 2)y, because y+2z=x, y+2z=(3 2)y, 2z=(3 2)y-y, 2z=(1 2)y, z=(1 4)y, so y=4z, x=6z

2) 120 (72-64) = 15 points, A: 64 * 15 + 120 = 1080 meters, B: 72 * 15-120 = 960 meters, choose one of them (1080 120) 4 = 9 4 =.

The first time B catches up with A, he is on point C of the square.

=y-5x-2

Bring into the following two formulas:

2x+3y-2(y-5x-2)=-6 2x+3y-2y+10x+4=12x+y+4=-6 12x+y=-10 y=-12x-10

3x-2y+6(y-5x-2)=23 3x-2y+6y-30x-12=-27x+4y-12=23 -27x+4y=35

27x+4(-12x-10)=-27x-48x-40=35-75x=75 x=-1

y=-12*-1-10=2

z=2+5-2=5 2x=3y, we get x = 3 2 y, and bring it into y+2z=x to get y+2 z=3 2 y 2 z=1 2 y

Y is 4 times that of Z.

x is 6 times that of z.

In the first question, y is 4 times that of z, and x is 6 times that of z (x=3y2 or y=2x3 can be substituted into y+2z=x, respectively).

In the second question, the time of encounter is t

Then, 64*t=72*t-360, we get t=45 (minutes) and 64*t 480=64*45 480=6, which is just divisible so A is at the place of departure, i.e., point a.

y is 4 times that of z x is 6 times that of z.

Neither will I be on the second question.

Give me more points.

y is 4 times that of z x is 6 times that of z. Because 2x=3y,y+2z=x, so 2(y+2z)=3y,2y+4z=3y,4z=y,y=4z,y=4z,2x=3(4z),2x=12z,x=6z,because y=4z,2x=3(4z),2x=12z,x=6z

Grade 5 Olympiad Mathematics Calculation Questions.

What is the single digit of the product of 2006 times 2007 and 2007 times 2008 2008?

The single digit of 2006 in 2006 is 6

The single digit of 2007 is 3

The single digit of 2008 is 6

The single digit of 2006, 2006 times 2007, 2007 multiplied by 2008, and 2008 is 8

Think for yourself! It's simple. You can report the question you don't know, and we'll help you solve it.

From the bottom of the mountain to the top of the mountain: 10 km.

So the average speed: 12 2 (km/h.)

10×2÷（

The average speed of their ascent and descent was 10 kilometers per hour.

Question 1: There should be 4; 4 by 6 molecules, 5 by 3, by 8 molecules, 5 by 2, 2 by 12 molecules, 5 by 1, by 24 molecules, 5

Question 2: After 12 days of the wheel once, so it is March 24.

(1) This band fraction may be one and twenty-four points.

Five, two and twelveth.

Five, three and eighth.

Five, four and five-sixths.

2) The least common multiple of 4 and 6 is 12, so the next simultaneous duty is March 24th.

1. Suppose the band fraction is a and 5/b false fraction is 29/b and you can find ab=24, so as long as this condition is met, 2, find their least common multiple, that is, March 24

1.Four and five sixths.

2.March 20 (I don't know if I understand the title correctly).

The second is to calculate the common multiples.

We haven't learned this unit yet......

Explain that the number of boys in the first row minus 2 divided by 3,4,6 is divisible, 3,4,6 least common multiple is 12, so one row of boys should be (12x+2), two rows are (24x+4), and because there are only 45 students in the class, x can only be equal to 1, so boys are (24+4)=28.

is 3,4,6 least common multiple plus 2

So the total number of boys is 3 2 2 2 = 14.