What is the number of black holes in 3? Detailed answers

6174 black hole value, its algorithm is as follows:

Number: Set a 4-digit number that is not exactly the same, such as 1234 (you can also take a duplicate number, such as 2244, etc., as long as the 4 digits are not identical);

Large number: take the maximum number that can be formed by these 4 numbers, in this example: 4321;

Decimal: Take the smallest number that these 4 numbers can compose, in this case: 1234;

Difference: Find the difference between large and small numbers, in this case: 4321-1234=3087;

Repeat: For the new number 3087, the algorithm of , , and the new number is obtained: 8730-0378=8352;

Repeat: For the new number 8352, the algorithm of , , and the new number is obtained: 8532-2358=6174;

Conclusion: For any 4-digit number that is not the same as 4 digits, according to the above algorithm, the final result cannot escape the 6174 black hole if it is calculated no more than 7 times;

The number of three-digit black holes is 495

The number of four-digit black holes is 6174

Make a four-digit number at will, such as a1 = 1628, first arrange the four numbers of the component 1628 from large to small to get a2 8621, and then arrange the four numbers of 1628 from small to large to get a3 1268, subtract the small a2-a1 = 8621-1268 7353 with the large one, and do 7353 again according to the above method, arrange the seven from large to small to get 7533, arrange from small to large to get 3357, and subtract 7533-3367 4176 Repeat 4176 again: 7641-1467 6174. If you go any further, a miracle will happen!

7641-1467 6174, back to 6174.

The so-called mathematical black hole is to start from a given number, and under the prescribed operation rules, it will eventually get a fixed value and can no longer jump out. Just like a black hole in the universe can suck any matter, including light, so firmly that it cannot escape.

Such a number is called a "black hole number", and such an operation is called a "rearrangement and difference" operation.

For example, a three-digit black hole has a number of 495

Simple derivation process: find a random number, such as 297, the numbers in the three digits are arranged once from small to large and from large to small, which are 972 and 279, and subtract them to get 693

Do it again according to the above method, get 594, do it again, get 495 and then get 495 repeatedly, and the number of four-digit black holes has 6174

This requires deep theoretical knowledge, coupled with mathematical knowledge, to be able to say its specific numbers, which ordinary people can't calculate.

Answer: 495

Proof: Let a > b > c

There are 3 possible scenarios for the first operation:

1)aab-baa

2)abb-bba

3)abc-cba

Consider (1), the single digits of AAB-BAA are b-a, the tens are 0, and the hundred-digit number is a-b = 99(a-b).

Consider (2), the single digits of ABB-BBA are b-a, the tens are 0, and the hundred-digit is a-b = 99(a-b).

Consider (3), the single digit of ABC-CBA is C-A, the number of tens is 0, and the number of hundreds: A-C = 99(A-C).

Therefore, the number obtained must be a multiple of 99, so that the number obtained may be 198, 297, 396, 495

594, 693, 792, 891 do not need to be considered, because the result will be the same as 198, 297, 396, 495).

99, 990 don't need to be considered, because it doesn't meet the criteria).

Divide 4 numbers into 4 sets.

s1 =s2 =

s3 =s4 =

Then the elements in s(i+1) can be obtained by arranging the new three-digit numbers appropriately after one operation, so only 495, 954-459 = 495 is proved.

Four-digit number: 6174

You're too black a hole for us to figure out!

They are: 314, 123, 213, 213....Xiang Xian....So the number of black holes is 213

For a three-digit black hole number, the single digit must be 3 (because it is a three-digit number), and the ten digit and the Baijinbi imitation digit are 1 or 2 or 3, but we can see that Waiting, Huinian is obviously not a black hole number, only 213 can.

For example, a three-digit black hole has a number of 495

Simple derivation process: find a random number, such as 297, the numbers in the three digits are arranged once from small to large and from large to small, which are 972 and 279, and subtract them to get 693

Do it again as above to get 594, do it again, get 495 and get 495 repeatedly

For example, the number of four-digit black holes is 6174

There are several types of black holes, because when matter collapses, most of their properties disappear with it, such as volume and temperature. But three properties are preserved: mass, charge, angular momentum.

That is, a black hole can stand there without an electric charge; It can also be immobile with an electric charge; It can also be uncharged, but rotates; It can also carry an electric charge and rotate.

At the periphery of a black hole, there is an event horizon

horizon), that is to say, as long as this "horizon" is passed, everything is good, even if it is wide, there is no return. If this black hole is not charged, then this "event horizon" is just a simple boundary. However, if this black hole is charged, then this black hole will have three boundaries.

One is normal, and the other two, one on the inside and one on the outside, are charged "horizons". For example, if a positively charged black hole falls into the event horizon, then the object has no return, but if a negatively charged object approaches the black hole, it has no return before it reaches the event horizon due to the action of the electric field. In other words, when he crosses the "negative event horizon" that is a little outer, he will be overwhelmed.

But Zhengqin is different. In this case, the positron can get closer to the singularity because of repulsion. Therefore, there is also a "positive event horizon".

Then, the black hole is divided into 3 layers. ：）

How big is the black cherry blossom core hole?

It's hard to explain in a word, but for details, see A Brief History of Time and the Universe in the Shell.

A black hole may also be just a body that is just a lens that bends light.